


Enter a polynomial inequality along with the variable to be solved for and click the Solve button.
INEQUALITIES IN ONE VARIABLEORDER RELATIONSHIPS In Sections 1.1 and 2.1, we saw that of two different numbers, the graph of the lesser number lies to the left of the graph of the greater number on a number line. These order relationships can be expressed by using the following symbols: < means "is less than," > means "is greater than." ≤ means "is less than or equal to," ≥ means "is greater than or equal to." For example, "1 is less than 3" can be written as 1 < 3. "7 is less than 9" can be written as 7 < 9. "3 is greater than 5" can be written as 3 > 5. "2 is less than or equal to x" can be written as 2 ≤ x. "4 is greater than or equal to y" can be written as 4 ≥ y. Statements that involve any of the above symbols are called inequalities. Inequalities such as 1 < 3 and 7 < 9 are said to be of the same order or same sense because the lefthand member is less than the righthand member in each case. Inequalities such as 7 < 9 and 3 > 5 are said to be of opposite order or opposite sense because in one case the lefthand member is less than the righthand member and in the other case the lefthand member is greater than the righthand member. PROPERTIES OF INEQUALITIES In Section 3.1, we saw that a firstdegree equation in one variable has only one solution. But a firstdegree inequality has an infinite number of solutions. For example, the graphs of the infinite number of integer solutions of the inequality x > 3 are shown in Figure 3.1. Sometimes it is not possible to determine the solutions of a given inequality simply by inspection. But using the following properties, we can form equivalent inequalities (inequalities with the same solutions) in which the solution is evident by inspection. 1. If the same expression is added to or subtracted from each member of an inequality, the result is an equivalent inequality in the same order. In symbols, a < b, a + c < b + c, and a  c < b  c are equivalent inequalities. Example 1 a. Because 3 < 5, then 3 + 4 < 5 + 4 or 7<9 b. If x < 7, then x + 2 < 7 + 2 c. If 4 < y, then 4 + (2) < y + (2) 2. If each member of an inequality is multiplied or divided by the same positive number, the result is an equivalent Inequality in the same order. In symbols, are equivalent inequalities. Example 2 a. Because 2 < 3 and 5 > 0, 2(5) < 3(5) or 10 < 15 b. If 3x < 12, then c. If 5 < y and z > 0, then 5(z) < y(z) or 5z < yz 3. If each member of an inequality is multiplied or divided by the same negative number, the result is an equivalent inequality in the opposite order. In symbols, are equivalent inequalities. Example 3 a. Because 3 < 5 and 2 < 0, 3(2) > 5( 2) or 6 >10 b. If 3x < 12, then c. If 2 < x and y < 0, then 2(y) > x(y) or 2y > xy The three properties above also apply to inequalities of the form a > b, as well as a < b. SOLVING INEQUALITIES Now let us see how the three properties can help us solve inequalities. Example 4 Solve , where x is an integer. Solution Multiplying each member by 2 (a positive number), we have Then dividing each member by 3, we get The graph of this inequality is In the above example, all the inequalities were in the same order because we only applied Property 2 above. Now consider the following inequality. Example 5 Solve  3x + 1 > 7, where x is an integer. Solution Adding  1 to each member, we get 3x + 1 + (1) > 7 + (1) 3x > 6 Now we apply Property 3 and divide each member by 3. In this case we have to reverse the order of the inequality. When solving word problems involving inequalities, we follow the six steps outlined on page 115 except the word equation will be replaced by the word inequality. CHAPTER SUMMARY
TRANSLATING WORD SENTENCESMost problems that deal with practical applications of mathematics are expressed in words. Before we can solve such problems, we must translate word sentences into mathematical equations. We can then use the techniques of the previous sections to solve the equations. In this section, we will only be concerned with writing algebraic expressions and equations. In the following sections, we will actually solve equations. In Sections 1.2 and 1.3 we associated certain word phrases with certain mathematical operations:
We can translate these word phrases into algebraic expressions as shown in the following examples. Example 1 Similarly, we can translate word sentences into equations. Example 2 Common Errors: When translating a phrase such as "a subtracted from b," the order is important. We must write b  a, not a  b since a is subtracted from b. For example, to translate "If seven is subtracted from 4 times an integer, the result is 17," we represent the integer by a symbol, say x, and then write the sentence as follows. APPLICATIONSIn the last section we translated word sentences into equations. Now, we will solve a variety of word problems. The following steps are suggested. To solve a word problem:
In practice, we usually combine steps 1 and 2. Follow the six steps listed above to solve the following word problem. The sum of a certain number and 9 is equal to four times the number. What is the number? Solution Steps 12 We first write what we want to find (a number) as a word phrase. Then, we use a variable to represent this number. The number: x Step 3 A sketch is not applicable in this problem. Step 4 We write an equation relating the known and unknown quantities. x + 9  4x Step 5 We now solve the resulting equation. x + 9  x = 4x  x 9 = 3x 3 = x Step 6 The number is 3. CONSECUTIVE INTEGERS Some algebraic word problems involve the concepts of consecutive integers. Consecutive integers are integers that differ by 1 or  1. For example, 3 and 4 are consecutive integers and 2 and 1 are consecutive integers. If x represents an integer, then the next consecutive integer is represented by x + 1. Consecutive even integers are even integers that differ by 2 or 2. For example, 6 and 8 are consecutive even integers and 4 and 2 are consecutive even integers. If x represents an even integer, then the next consecutive even integer is represented by x + 2. Consecutive odd integers are odd integers that differ by 2 or 2. For example, 5 and 7 are consecutive odd integers and 3 and 1 are consecutive odd integers. If x represents an odd integer, then the next consecutive odd integer is represented by x + 2. Example 2 Follow the six steps listed on page 115 to solve the following word problem. The sum of two consecutive odd integers is 12. What are the integers? Solution Steps 12 We first write what we want to find (the integers) as two word phrases. Then, we use a variable to represent the integers. The smaller odd integer: x The next consecutive odd integer: x + 2 Step 3 A sketch is not applicable in this problem. Step 4 Next, we write an equation relating known and unknown quantities. x + (x + 2) = 12 Step 5 We now solve the resulting equation. x + x + 2 = 12 2x + 2 = 12 2x = 10 x = 5 Step 6 The integers are 5 and 5 + 2, or 7. In the following example, a sketch is helpful. Example 3 Follow the six steps listed on page 115 to solve the following word problem. A board 186 centimeters long is cut into two pieces so that one piece is twice as long as the other. How long is each of the two pieces? Solution Steps 12 We first write what we want to find (the lengths) as word phrases. Then, we use a variable to represent the lengths. The smaller piece: x The larger piece: 2x Step 3 We now make a sketch and label dimensions. Step 4 Writing an equation relating the known and the unknown quantities yields x + 2x = 186 Step 5 We now solve the equation. 3x = 186 x = 62 Step 6 The smaller piece is 62 centimeters and the larger piece is 2(62) or 124 centimeters. 