QuickMath Download on App Store Download on Google Play
Welcome to Quickmath Solvers! Download on App Store Download on Google Play
Created on: 2012-04-16

A sample problem solved by Quickmath online math solver

a product that consists of 3 factors. the 1st factor of the product is 4. the 2nd factor of the product is equal to (k+5). the 3rd factor of the product is (k+9). factored | analyze how to multiply out a sum that comprises 2 terms. 2*(4*g^2-3*g)

Command

Solve

Equation
(-3*x)/(x-4) = (-18)/(x^2-9*x+20)

  1. an equation LHS is equal to a quotient: dividend of the quotient is a product consisting of 2 factors. The first factor of the product is equal to negative three. The second factor of the product is equal to x. Divisor of the quotient is a sum containing 2 terms. The first term of the sum is x. The second term of the sum is negative four Right side of the equation is equal to a fraction: the top of the fraction is negative eighteen. The bottom of the fraction is a sum consisting of 3 terms. The first term of the sum is a power. The base is x. The exponent is two. The second term of the sum is equal to a negative product that comprises 2 factors. The first factor of the product is equal to nine. The second factor of the product is x. The third term of the sum is equal to twenty.
  2. negative three times x fraction line x plus negative four is equal to negative eighteen fraction line x to the power two plus negative nine multiplied by x plus twenty.
Variable
Result

Exact

Solution 1 ( real )
x = 6

  1. an equation LHS is equal to x RHS is equal to six.
  2. x is equal to six;
Solution 2 ( real )
x = -1

  1. an equation Left side of the equation is equal to x Right side of the equation is equal to negative one;
  2. x is equal to negative one;