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Created on: 2012-04-14

A sample problem solved by Quickmath online algebra solver

expanding ((7/9+2/3+(-13)/9)*(5/4*3/10+1/6)+3/5+(-1)/10)*10/5+4/5 into partial fractions

Command

Solve

Equation
(5*p-4)/6-(2*p+3)/2 = 7

  1. an equation LHS is equal to a sum of 2 terms; the 1st term of the sum is equal to a rational expression: the top of the rational expression is a sum containing 2 terms; the 1st term of the sum is equal to a product comprising 2 factors; the 1st factor of the product is five; the 2nd factor of the product is equal to p; the 2nd term of the sum is equal to negative four; the bottom of the rational expression is six; the 2nd term of the sum is equal to a negative fraction: the top of the fraction is a sum of 2 terms; the 1st term of the sum is equal to a product containing 2 factors; the 1st factor of the product is equal to two; the 2nd factor of the product is p; the 2nd term of the sum is equal to three; the bottom of the fraction is two Right side of the equation is seven;
  2. five multiplied by p plus negative four over six plus negative two multiplied by p plus three divided by two is equal to seven;
Variable
Result

Exact

p = -55

  1. an equation LHS is equal to p RHS is equal to negative fifty five;
  2. p is equal to negative fifty five;