QuickMath Download on App Store Download on Google Play
Welcome to Quickmath Solvers! Download on App Store Download on Google Play
Created on: 2012-04-15

A sample problem solved by Quickmath web algebra calculator

the best way to reduce 12*x^2*y^5/(25*x^2)*(5*x^4/(25*x^2))*(10*z^4/(60*y)) | partial fraction decomposition of (2/3-3)/1/9

Command

Solve

Equation
5*x^2+2*x-4 = 0

  1. an equation LHS is equal to a sum of 3 terms. The 1st term of the sum is a product containing 2 factors. The 1st factor of the product is five. The 2nd factor of the product is equal to a power. The base is x. The exponent is two. The 2nd term of the sum is equal to a product that contains 2 factors. The 1st factor of the product is equal to two. The 2nd factor of the product is equal to x. The 3rd term of the sum is equal to negative four Right side of the equation is zero.
  2. five multiplied by x raised to the power two plus two times x plus negative four is equal to zero;
Variable
Result

Exact

Solution 1 ( real )
x = -(sqrt(21)+1)/5

  1. an equation LHS is equal to x Right side of the equation is equal to a fraction: the top of the fraction is a negative sum consisting of 2 terms; the 1st term of the sum is square root of twenty one; the 2nd term of the sum is one; the bottom of the fraction is five;
  2. x is equal to negative open brace square root of twenty one plus one close brace over five.
Solution 2 ( real )
x = (sqrt(21)-1)/5

  1. an equation Left side of the equation is equal to x RHS is equal to a rational expression: the numerator of the rational expression is a sum consisting of 2 terms. The 1st term of the sum is equal to square root of twenty one. The 2nd term of the sum is equal to negative one. The denominator of the rational expression is five.
  2. x is equal to square root of twenty one plus negative one fraction line five ;


Approximate

Solution 1 ( real )
x = -1.11652

  1. an equation LHS is equal to x Right side of the equation is equal to negative one point one one six five two.
  2. x is equal to negative one point one one six five two;
Solution 2 ( real )
x = .716515

  1. an equation Left side of the equation is equal to x Right side of the equation is zero point seven one six five one five.
  2. x is equal to zero point seven one six five one five.