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Created on: 2012-02-18

A sample problem solved by Quickmath online math solver

Command

Solve

Equation
3*x^2+36*x+96 = 0

  1. an equation LHS is a sum that contains 3 terms. The 1st term of the sum is a product that consists of 2 factors. The 1st factor of the product is equal to three. The 2nd factor of the product is a power. The base is x. The exponent is two. The 2nd term of the sum is equal to a product that comprises 2 factors. The 1st factor of the product is equal to thirty six. The 2nd factor of the product is x. The 3rd term of the sum is ninety six Right side of the equation is equal to zero.
  2. three times x raised to the power two plus thirty six multiplied by x plus ninety six is zero.
Variable
Result

Exact

Solution 1 ( real )
x = -8

  1. an equation Left side of the equation is x RHS is equal to negative eight.
  2. x is equal to negative eight;
Solution 2 ( real )
x = -4

  1. an equation Left side of the equation is x RHS is negative four;
  2. x is equal to negative four.