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Created on: 2012-01-23

A sample problem solved by Quickmath online algebra solver

8*x^2-6*x+1 = 0 equation solved | (1/s^2+1)^4/(16*(1/s-s)^3)+(1/(s^6*(1/s-s)^2)-(1/s^2+1)^2/(2*s^3*(1/s-s)^2)) problem solved

Command

Factor

Expression

18*x^2*y-24*x^2+(-12)*y+16

  1. A sum of 4 terms. The 1st term of the sum is a product of 3 factors. The 1st factor of the product is eighteen. The 2nd factor of the product is equal to a power. The base is x. The exponent is two. The 3rd factor of the product is equal to y. The 2nd term of the sum is equal to a negative product containing 2 factors. The 1st factor of the product is equal to twenty four. The 2nd factor of the product is equal to a power. The base is x. The exponent is two. The 3rd term of the sum is equal to a product consisting of 2 factors. The 1st factor of the product is equal to negative twelve. The 2nd factor of the product is equal to y. The 4th term of the sum is equal to sixteen.
  2. eighteen multiplied by x to the power two multiplied by y plus negative twenty four times x to the power two plus left brace negative twelve right brace times y plus sixteen.

Result

2*(3*x^2-2)*(3*y-4)

  1. A product that consists of 3 factors; the 1st factor of the product is equal to two; the 2nd factor of the product is equal to a sum that contains 2 terms; the 1st term of the sum is equal to a product that contains 2 factors; the 1st factor of the product is three; the 2nd factor of the product is a power; the base is x; the exponent is two; the 2nd term of the sum is negative two; the 3rd factor of the product is equal to a sum that comprises 2 terms; the 1st term of the sum is equal to a product that contains 2 factors; the 1st factor of the product is equal to three; the 2nd factor of the product is equal to y; the 2nd term of the sum is negative four;
  2. two multiplied by open brace three multiplied by x to the power two plus negative two close brace multiplied by open parenthesis three times y plus negative four close parenthesis.