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Created on: 2012-01-13

A sample problem solved by Quickmath web algebra calculator

how to simplify a sum comprising 3 terms.

Command

Solve

Equation
3*(y-14) = 21*y+12

  1. an equation LHS is equal to a product that contains 2 factors. The 1st factor of the product is equal to three. The 2nd factor of the product is equal to a sum of 2 terms. The 1st term of the sum is equal to y. The 2nd term of the sum is equal to negative fourteen RHS is a sum that consists of 2 terms. The 1st term of the sum is equal to a product that consists of 2 factors. The 1st factor of the product is twenty one. The 2nd factor of the product is equal to y. The 2nd term of the sum is twelve.
  2. three times opening brace y plus negative fourteen closing brace is equal to twenty one multiplied by y plus twelve;
Variable
Result

Exact

y = -3

  1. an equation LHS is y RHS is negative three;
  2. y is equal to negative three.