Simple numerical terms are commonly written last. |
Simple numerical terms are commonly written last. |
We need to get rid of expression parentheses. If there is a negative sign in front of it, each term within the expression changes sign. Otherwise, the expression remains unchanged. In our example, there are no negative expressions. |
Simple numerical terms are commonly written last. |
In order to factor an integer, we need to repeatedly divide it by the ascending sequence of primes (2, 3, 5...). The number of times that each prime divides the original integer becomes its exponent in the final result. In our example, Prime number 2 to the power of 2 equals 4. |
Before factoring this expression as a difference of two squares, we need to rearrange the expression, so that the first term becomes positive. |
We need to factor this expression by applying the difference of two squares rule: A2−B2=(A−B)(A+B). In our example, A is equal to 2 and B is equal to x. |
Simple numerical terms are commonly written last. |
Simple numerical terms are commonly written last. |
We need to add fractions. The following rule is applied: AB+CD=LCDBA+LCDDCLCD This example involves 3 terms. The LCD is equal to: (−x+2)(x+2) |
Number 1 as a factor, does not need to be explicitly written. In other words: 1A=A. In our example, the above transformation has been applied once. |
We need to get rid of parentheses in this term. All the negative factors will change sign. In our example, we have only one negative factor. The sign of the term will change, since there is an odd number of negative factors. |
We need to get rid of expression parentheses. If there is a negative sign in front of it, each term within the expression changes sign. Otherwise, the expression remains unchanged. In our example, there are no negative expressions. |
Simple numerical terms are commonly written last. |
We need to arrange this term for expansion. Commonly, the non-expandable factor is written first. In our example, the factor is x. |
We need to expand this term by multiplying two expressions. The following product distributive property will be used: (A+B)(C+D)=AC+AD+BC+BD. In our example, the resulting expression will consist of 4 terms: the first term is a product of −x and x. the second term is a product of −x and −1. the third term is a product of 2 and x. the fourth term is a product of 2 and −1. |
We need to combine like factors in this term by adding up all the exponents and copying the base. No exponent implies the value of 1. The following are like factors: x, x |
Number 1 as a factor, does not need to be explicitly written. In other words: 1A=A. In our example, the above transformation has been applied once. |
Number 1 as a factor, does not need to be explicitly written. In other words: 1A=A. In our example, the above transformation has been applied once. |
Numerical terms in this expression have been added. |
We need to combine like terms in this expression by adding up all numerical coefficients and copying the literal part, if any. No numerical coefficient implies value of 1. There is only one group of like terms: x, 2x |
We need to get rid of expression parentheses. If there is a negative sign in front of it, each term within the expression changes sign. Otherwise, the expression remains unchanged. In our example, the following 3 terms will change sign: −x2, 3x, −2 |
Numerical terms in this expression have been added. |
We need to factor the GCF (Greatest Common Factor). The resulting term is a product of the GCF and the original expression divided by the GCF. In our example, the GCF is equal to x. |
We need to reduce this fraction to the lowest terms. This can be done by dividing out those factors that appear both in the numerator and in the denominator. In our example, this is the common factor: x. |
We need to reduce this fraction to the lowest terms. This can be done by dividing out those factors that appear both in the numerator and in the denominator. In our example, this is the common factor: x. |
We need to reduce this fraction to the lowest terms. This can be done by dividing out those factors that appear both in the numerator and in the denominator. In our example, this is the common factor: x. |
Number 1 as a factor, does not need to be explicitly written. In other words: 1A=A. In our example, the above transformation has been applied once. |
Numerical terms in this expression have been added. |
Number 1 as a factor, does not need to be explicitly written. In other words: 1A=A. In our example, the above transformation has been applied once. |
Any fraction which has its denominator equal to 1 is equal to its numerator. In other words: NUM1=NUM In our example, the numerator is equal to x+2. |
This is a special case of exponentiation. The following rule is applied: A1=A In our example, A is equal to x. |
Any fraction which has its denominator equal to 1 is equal to its numerator. In other words: NUM1=NUM In our example, the numerator is equal to 3. |
Any fraction which has its denominator equal to 1 is equal to its numerator. In other words: NUM1=NUM In our example, the numerator is equal to x. |
We need to get rid of expression parentheses. If there is a negative sign in front of it, each term within the expression changes sign. Otherwise, the expression remains unchanged. In our example, there are no negative expressions. |
We need to organize this expression into groups of like terms, so we can combine them easier. There are 2 groups of like terms: first group: x, x second group: 2, −3 |
We need to combine like terms in this expression by adding up all numerical coefficients and copying the literal part, if any. No numerical coefficient implies value of 1. Numerical 'like' terms will be added. There are 2 groups of like terms: first group: x, x second group: 2, −3 |