Created on: 2012-01-05

A sample problem solved by Quickmath online math solver

expanding ((7/9+2/3+(-13)/9)*(5/4*3/10+1/6)+3/5+(-1)/10)*10/5+4/5 into partial fractions

Command

Partial Fractions

Expression
(b+5)*(6*b-7)

  1. A product that consists of 2 factors. The 1st factor of the product is equal to a sum consisting of 2 terms. The 1st term of the sum is equal to b. The 2nd term of the sum is equal to five. The 2nd factor of the product is a sum of 2 terms. The 1st term of the sum is equal to a product that consists of 2 factors. The 1st factor of the product is equal to six. The 2nd factor of the product is b. The 2nd term of the sum is equal to negative seven.
  2. open brace b plus five close brace times opening parenthesis six multiplied by b plus negative seven closing parenthesis.
Result
6*b^2+23*b-35

  1. A sum that contains 3 terms. The 1st term of the sum is a product that contains 2 factors. The 1st factor of the product is equal to six. The 2nd factor of the product is equal to a power. The base is b. The exponent is two. The 2nd term of the sum is equal to a product comprising 2 factors. The 1st factor of the product is equal to twenty three. The 2nd factor of the product is equal to b. The 3rd term of the sum is negative thirty five.
  2. six multiplied by b raised to the power of two plus twenty three multiplied by b plus negative thirty five;