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Created on: 2012-03-28

A sample problem solved by Quickmath web algebra calculator

study how to factor a product consisting of 2 factors; 13*y^2-5*y*x+(-8)*x^2 | 4-3/4+(-2)/3 simplified

Command

Expand

Expression

(x+2)*(x2-6*x+5)

  1. A product of 2 factors. The first factor of the product is equal to a sum that contains 2 terms. The first term of the sum is equal to x. The second term of the sum is two. The second factor of the product is a sum that contains 3 terms. The first term of the sum is x 2-th. The second term of the sum is equal to a negative product that comprises 2 factors. The first factor of the product is equal to six. The second factor of the product is x. The third term of the sum is equal to five.
  2. left bracket x plus two right bracket times open brace x 2-th plus negative six times x plus five close brace;

Result

x*x2+2*x2-6*x^2-7*x+10

  1. A sum consisting of 5 terms. The first term of the sum is equal to a product comprising 2 factors. The first factor of the product is equal to x. The second factor of the product is equal to x 2-th. The second term of the sum is a product containing 2 factors. The first factor of the product is equal to two. The second factor of the product is x 2-th. The third term of the sum is equal to a negative product of 2 factors. The first factor of the product is equal to six. The second factor of the product is equal to a power. The base is x. The exponent is two. The four term of the sum is a negative product that comprises 2 factors. The first factor of the product is seven. The second factor of the product is equal to x. The five term of the sum is equal to ten.
  2. x multiplied by x 2-th plus two times x 2-th plus negative six times x exponentiated by two plus negative seven multiplied by x plus ten.