Mixture Problem: Antifreeze Solution
What This Problem Teaches
- How to track the amount of a substance (not just percentages) through mixture changes
- Setting up equations where the same unknown appears in both "removal" and "addition" terms
- Understanding that draining removes substance proportionally to current concentration
- Recognizing drain-and-replace as a fundamental mixture operation in real applications
- Converting between percentage concentrations and actual quantities
Solution: Method 1 — The Antifreeze Balance Approach
The key insight is to track the actual amount of antifreeze, not just the percentages. We'll follow where the antifreeze goes: some gets removed when we drain, and some gets added when we replace.
Step 1 — Calculate the current antifreeze amount
The radiator currently holds:
Step 2 — Set up what happens when we drain and replace
Let x = quarts of fluid drained and replaced.
When we drain x quarts of the 30% mixture, we remove:
When we replace those x quarts with pure antifreeze, we add:
Step 3 — Write the equation for final antifreeze amount
The final mixture should be 60% antifreeze out of 13 quarts total:
The balance equation is:
Step 4 — Solve for x
Simplify the left side:
Let's be more precise:
Solution: Method 2 — The Final Composition Setup
Instead of tracking the changes, we can set up an equation based on what the final mixture contains.
Step 1 — Identify what's in the final mixture
After draining x quarts and replacing with pure antifreeze, we still have 13 quarts total. This final mixture contains antifreeze from two sources:
- Antifreeze remaining from the original mixture:
(13-x) × 0.30quarts - Pure antifreeze added:
xquarts
Step 2 — Set up the final concentration equation
The total antifreeze in the final 13 quarts should equal 60% of 13:
Step 3 — Solve the equation
Expand and simplify:
This confirms our answer using a different setup approach.
Verification
Let's check our answer by calculating the final concentration:
Starting mixture after draining 5.57 quarts:
After adding 5.57 quarts of pure antifreeze:
Using the exact fraction 39/7:
Common Pitfalls
Wrong thinking: "We're mixing 30% with 100%, so the answer should be around (30% + 100%) ÷ 2 = 65%."
Why it's wrong: Percentages can't be averaged directly because they depend on the amounts being mixed. We're not mixing equal quantities—we're replacing a specific amount that we need to calculate.
Wrong setup: "3.9 + x = 7.8, so x = 3.9 quarts"
Why it's wrong: This assumes draining removes no antifreeze at all. In reality, when you drain x quarts of 30% mixture, you lose 0.30x quarts of antifreeze.
Wrong thinking: "After draining x and adding x, we have 13-x+x = 13 quarts, but let me write the volume as 13-x somewhere in my equation."
Why it's wrong: The total volume stays at 13 quarts because we drain and replace the same amount. The equation should reflect that we want 60% of those same 13 quarts.
The General Formula
For any drain-and-replace mixture problem, if we drain and replace x units:
Where:
- Concentration₁ = current concentration (what's being drained)
- Concentration₂ = concentration of replacement fluid
- Target amount = desired concentration × total volume
This simplifies to:
Important limitation: This formula only works when Concentration₂ ≠ Concentration₁. If they're equal, you're replacing with the same concentration, so nothing changes!
Real Applications
This exact calculation appears frequently in practical situations:
- Automotive maintenance: Adjusting antifreeze concentration for different climate zones or seasonal changes
- Swimming pool chemistry: Adjusting chlorine or pH buffer concentrations by partial water changes
- Industrial manufacturing: Adjusting solution concentrations in chemical processes, plating baths, or cleaning solutions
- Medical applications: Diluting or concentrating IV solutions, preparing topical treatments with specific active ingredient percentages
Does the Answer Make Sense?
Let's check whether 5.57 quarts seems reasonable:
Boundary check: We need to go from 30% to 60% antifreeze. That's doubling the concentration, which intuitively should require replacing a significant portion of the mixture with pure antifreeze.
Scale check: We're replacing 5.57 out of 13 quarts = about 43% of the total volume. Since we're roughly doubling the antifreeze concentration by adding 100% antifreeze, replacing nearly half makes sense.
Limit check: If we wanted 100% antifreeze, we'd replace all 13 quarts. If we wanted just slightly more than 30%, we'd replace very little. At 60%, replacing about 43% falls nicely between these extremes.
What If? — Try These Variations
Current antifreeze: 0.30 × 13 = 3.9 quarts
Target antifreeze: 0.80 × 13 = 10.4 quarts
Let x = quarts drained and replaced3.9 - 0.30x + x = 10.4
3.9 + 0.70x = 10.40.70x = 6.5x = 6.5 ÷ 0.70 = 65/7 ≈ 9.29 quarts
Remaining original: (13 - 65/7) × 0.30 = 26/7 quarts antifreeze
Added pure: 65/7 quarts antifreeze
Total: 26/7 + 65/7 = 91/7 = 13 × 0.80 ✓
Drain and replace approximately 9.29 quarts
After draining 4 quarts, 13 - 4 = 9 quarts of original mixture remain
Antifreeze in remaining mixture: 9 × 0.30 = 2.7 quarts
Pure antifreeze added: 4 quarts
Total antifreeze: 2.7 + 4 = 6.7 quarts
Total volume remains: 13 quarts
New concentration: 6.7 ÷ 13 = 0.515 = 51.5%
Check: 9 × 0.30 + 4 × 1.00 = 2.7 + 4 = 6.7 quarts antifreeze ✓
The new mixture is 51.5% antifreeze
After draining 3 quarts and adding water:
Remaining antifreeze: (13-3) × 0.30 = 10 × 0.30 = 3.0 quarts
New concentration: 3.0 ÷ 13 = 23.08%
Let x = quarts drained and replaced in second stage
Current antifreeze: 3.0 quarts
Target antifreeze: 0.60 × 13 = 7.8 quarts
3.0 - (3.0/13)x + x = 7.83.0 + x(1 - 3.0/13) = 7.83.0 + x(10/13) = 7.8x = 4.8 ÷ (10/13) = 4.8 × 13/10 = 6.24 quarts
Drain and replace 6.24 quarts in the second step
We must drain and replace exactly 6 quarts
Original antifreeze: 13 × 0.30 = 3.9 quarts
Antifreeze removed: 6 × 0.30 = 1.8 quarts
Final antifreeze = Original - Removed + Added= 3.9 - 1.8 + 6 = 8.1 quarts
Total volume remains: 13 quarts
Maximum concentration: 8.1 ÷ 13 = 0.623 = 62.3%
Check: 7 × 0.30 + 6 × 1.00 = 2.1 + 6 = 8.1 quarts antifreeze ✓
The maximum achievable concentration is 62.3%
Frequently Asked Questions
2026-09-07