Conveyor Line Rates: Setting Up Equal Equations

Work Rates 9th-10th Grade
PROBLEM
In a paint factory, an old conveyor line has filled 15 barrels of paint and is filling more at a rate of 2 barrels per minute. A worker just switched on a newer line that can fill 5 barrels per minute. In a little while, the two lines will have filled an equal number of barrels. How long will that take?

What You Will Learn

  • Setting up linear equations from rate problems with different starting points
  • Recognizing when a "catching up" scenario creates an equality condition
  • Using substitution to solve systems where rates compete over time
  • Interpreting intersection points as the moment when two quantities become equal
  • Converting word problems about cumulative processes into algebraic expressions

Solution: Method 1 — The Equal Quantities Approach

This problem asks when two different processes will have achieved the same total result. The key insight is that each conveyor line's total output follows a predictable pattern over time.

Step 1 — Express each line's total barrels as a function of time

Let t be the number of minutes from when the new line starts. The old line already has a 15-barrel head start and adds 2 barrels per minute:

Old line total = 15 + 2t

The new line starts from zero and adds 5 barrels per minute:

New line total = 5t

Step 2 — Set up the equality condition

We want to find when both lines have filled the same number of barrels, so we set the expressions equal:

15 + 2t = 5t

Step 3 — Solve for time

Subtract 2t from both sides:

15 = 5t - 2t 15 = 3t

Divide both sides by 3:

t = 5

Step 4 — Calculate how many barrels each line will have filled

After 5 minutes, substitute back into either equation:

Old line: 15 + 2(5) = 15 + 10 = 25 barrels New line: 5(5) = 25 barrels

Solution: Method 2 — The Gap-Closing Strategy

Instead of setting up equations, we can think about this as a race where one contestant has a head start. The question becomes: how long does it take for the faster contestant to close the gap?

Step 1 — Identify the gap and the rate difference

The old line starts with a 15-barrel advantage. Each minute, the new line gains ground by producing more barrels than the old line:

Rate advantage = 5 - 2 = 3 barrels per minute

Step 2 — Calculate the catch-up time

At a rate of 3 barrels gained per minute, how long to close a 15-barrel gap?

Time to catch up = Initial gap ÷ Rate advantage Time to catch up = 15 ÷ 3 = 5 minutes

Step 3 — Verify with the final totals

After 5 minutes of the catch-up process:

Old line total: 15 + 2(5) = 25 barrels New line total: 0 + 5(5) = 25 barrels ✓
It will take 5 minutes for both lines to have filled the same number of barrels (25 barrels each).

Verification

Let's check our answer by substituting t = 5 back into the original expressions:

Old line after 5 minutes: 15 + 2(5) = 15 + 10 = 25 barrels New line after 5 minutes: 5(5) = 25 barrels

Both lines have indeed filled 25 barrels after 5 minutes, confirming our answer is correct.

We can also verify this makes intuitive sense: the new line produces 3 more barrels per minute than the old line, so it should take 15 ÷ 3 = 5 minutes to overcome the 15-barrel head start.

Watch Out For These

✗ Forgetting the head start

Setting up the equation as 2t = 5t ignores that the old line already had 15 barrels when timing began. This gives t = 0, which would mean they're equal immediately — clearly wrong since the old line starts ahead.

✗ Adding rates instead of setting totals equal

Some students mistakenly write 2 + 5 = 7 and try to use the combined rate. But the question isn't about their combined output — it's about when their individual outputs become equal.

✗ Using the wrong time reference

If you accidentally count time from when the old line started rather than when the new line started, your equation becomes much more complicated. Always define your time variable clearly: t = minutes since the new line began operating.

The Pattern Behind This

This problem represents a classic "catch-up" scenario that appears throughout mathematics. The general pattern is:

Slower rate with head start: H + r₁t Faster rate from zero: r₂t Catch-up time: t = H ÷ (r₂ - r₁)

Where H is the initial head start, r₁ is the slower rate, and r₂ is the faster rate. This formula only works when r₂ > r₁ — if the rates were equal or if the "old" line were faster, they would never meet or would only grow further apart.

The beauty of this pattern is that it doesn't matter what units you're measuring. Whether it's barrels per minute, cars per hour, or widgets per day, the mathematical structure remains identical.

Real Applications

This type of problem appears frequently in industrial and business contexts:

  • Manufacturing: When a new production line is added to catch up with demand that an existing line has been partially fulfilling.
  • Data processing: Comparing the progress of different servers processing a backlog, where one server had a head start on the workload.
  • Inventory management: Determining when two different supply chains will have delivered the same total quantity, accounting for different start times and rates.

What If?

1
Faster Old Line
The old conveyor line has filled 12 barrels and fills at 4 barrels per minute. The new line fills at 6 barrels per minute. When will they have filled equal amounts?
Step 1 — Set up equations

Old line: 12 + 4t barrels, New line: 6t barrels

Step 2 — Set them equal

12 + 4t = 6t

Step 3 — Solve for t

12 = 6t - 4t = 2t, so t = 6

Step 4 — Find the number of barrels

After 6 minutes: both lines have 12 + 4(6) = 36 barrels

Verification

Old: 12 + 4(6) = 36, New: 6(6) = 36

Answer: 6 minutes

2
Adding a Constraint
The old line has 15 barrels and fills 2 per minute. The new line fills 5 per minute. But the old line will shut down after 8 minutes for maintenance. Do they ever have equal amounts?
Step 1 — Find when they would be equal normally

15 + 2t = 5t gives t = 5 minutes

Step 2 — Check if this happens before shutdown

Since 5 < 8, they do become equal before the shutdown

Step 3 — Calculate the equal amount

At t = 5: both have 15 + 2(5) = 25 barrels

Step 4 — What happens after?

From minutes 5-8, new line pulls ahead: 5(8) = 40 vs old 15 + 2(8) = 31

Verification

At 5 min: Old 15 + 10 = 25, New 25

Answer: Yes, they're equal at 5 minutes (25 barrels each)

3
Three Lines
Three lines: old (15 barrels, 2/min), new (0 barrels, 5/min), and newest (0 barrels, 8/min). When do all three have the same amount?
Step 1 — Set up three equations

Old: 15 + 2t, New: 5t, Newest: 8t

Step 2 — Set old = new

15 + 2t = 5t gives t = 5

Step 3 — Check if newest equals them at t = 5

Newest at t = 5: 8(5) = 40 barrels

Step 4 — Check old and new at t = 5

Old and new both have 25 barrels at t = 5

Conclusion

Since 40 ≠ 25, all three are never equal. The fastest line is always ahead when the other two meet.

Answer: Never — the newest line is too fast

4
Reverse the Unknown
The old line fills 2 barrels per minute. The new line fills 5 per minute. If they have equal amounts after exactly 6 minutes, how many barrels did the old line start with?
Step 1 — Set up the equation with unknown head start

Let H = initial barrels. Old: H + 2t, New: 5t

Step 2 — Use the given condition

At t = 6, they're equal: H + 2(6) = 5(6)

Step 3 — Simplify

H + 12 = 30

Step 4 — Solve for H

H = 30 - 12 = 18

Verification

After 6 min: Old 18 + 12 = 30, New 30

Answer: 18 barrels

Frequently Asked Questions

How do you solve when two rates with different starting points become equal?+
Set up equations for each quantity over time, then solve where they're equal. The faster rate will eventually catch up to the slower rate that had a head start. In this problem, 15 + 2t = 5t gives us t = 5 minutes when both lines have filled 25 barrels.
What's the difference between rate problems and linear equation problems?+
Rate problems ARE linear equation problems in disguise. Each rate creates a linear function: starting amount plus rate times time. Here, the old line follows 15 + 2t and the new line follows 5t. The intersection point tells us when they're equal.
Why does the faster rate always catch up in these problems?+
As long as the faster rate's advantage per unit time is greater than zero, it will eventually overcome any finite head start. The new line gains 3 barrels per minute (5 - 2), so it closes the 15-barrel gap in exactly 15 ÷ 3 = 5 minutes.
NJ
Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

Contact

This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-08-02