Mixture Problem: Equal Removal from Two Containers
Mixture Problem: Equal Removal from Two Containers
What This Problem Teaches
- Setting up equations when equal quantities are removed from different starting amounts
- Understanding how ratios change when you subtract the same value from different quantities
- Recognizing that the difference between containers stays constant during equal removal
- Translating "times as much" language into algebraic relationships
- Verifying solutions by checking both the arithmetic and the logical constraints
Solution: Method 1 — The Direct Ratio Approach
This is a classic "equal removal" problem where the key insight is that removing the same amount from different quantities changes their ratio. Let's work through this systematically.
Step 1 — Define the variable
Let x = the number of liters removed from each container.
Step 2 — Express the final amounts
After removing x liters from each container:
- Container A will have:
18.6 - xliters - Container B will have:
10.3 - xliters
Step 3 — Set up the ratio equation
We're told that after removal, container A has 5 times as much water as container B. This gives us:
Step 4 — Solve the equation
Expand the right side:
Add 5x to both sides:
18.6 + 4x = 51.5
Subtract 18.6 from both sides:
4x = 32.9
x = 8.225
Solution: Method 2 — The Constant Difference Strategy
Here's a more elegant approach that uses the fact that the difference between the containers stays the same when we remove equal amounts.
Step 1 — Find the initial difference
The difference between the containers initially is:
Step 2 — Use the final ratio to find the individual amounts
After removal, if container B has y liters, then container A has 5y liters. The difference must still be 8.3 liters:
4y = 8.3
y = 2.075
Step 3 — Find how much was removed
Container B ends with 2.075 liters, so the amount removed was:
We can verify: Container A ends with 5 × 2.075 = 10.375 liters, so 18.6 - 10.375 = 8.225 liters was also removed from A.
Verification
Let's check our answer by substituting back into the original conditions:
After removing 8.225 liters from each container:
- Container A:
18.6 - 8.225 = 10.375liters - Container B:
10.3 - 8.225 = 2.075liters
Check the ratio:
Perfect! Container A indeed has exactly 5 times as much water as container B.
Common Pitfalls
✗ Assuming the ratio stays the same
Students often think: "A starts with about 1.8 times as much as B, so after equal removal it should still be 1.8 times as much." This misses the key point that equal subtraction changes ratios dramatically.
✗ Setting up the wrong equation
Writing 18.6/10.3 = 5 or (18.6-x)/(10.3-x) = 1.8 instead of (18.6-x) = 5(10.3-x). The phrase "5 times as much" means multiplication, not division.
✗ Forgetting that the same amount is removed from both
Using different variables like 18.6 - a = 5(10.3 - b). The problem specifically states "equal amount," so both containers lose the same quantity.
The Pattern Behind This
This problem follows the general pattern for "equal removal with a final ratio" problems. If you start with quantities A and B, remove x from each, and end with a ratio of r:1, then:
Solving this general equation:
A - rB = x - rx
A - rB = x(1 - r)
x = (A - rB)/(1 - r)
A = 18.6, B = 10.3, r = 5:x = (18.6 - 5×10.3)/(1 - 5) = (18.6 - 51.5)/(-4) = -32.9/(-4) = 8.225 ✓Does This Seem Reasonable?
Let's do a sanity check on our answer of 8.225 liters removed:
Also consider: we're removing more than 80% of the original water from both containers. This makes sense because we're going from a ratio of about 1.8:1 down to 5:1 — a dramatic change requires dramatic removal.
If we'd only removed a small amount, the ratio would have stayed close to the original 1.8:1. To get to 5:1, we need to remove most of the water, leaving container B nearly empty.
What If?
Let x be the amount removed. After removal: 18.6 - x = 3(10.3 - x)
18.6 - x = 30.9 - 3x18.6 - x + 3x = 30.918.6 + 2x = 30.92x = 12.3x = 6.15
Container A: 18.6 - 6.15 = 12.45L
Container B: 10.3 - 6.15 = 4.15L
Ratio: 12.45 ÷ 4.15 = 3 ✓
6.15 liters was removed from each container.
Container A: 20 - 3 = 17 liters
Container B: 8 - 3 = 5 liters
17 ÷ 5 = 3.4
Container A has 3.4 times as much water as container B.
Initially A had 20 ÷ 8 = 2.5 times as much as B. Equal removal increased the ratio from 2.5:1 to 3.4:1.
Let x = liters removed from B
Then x + 2 = liters removed from A
After removal: 18.6 - (x + 2) = 4(10.3 - x)
Simplify: 16.6 - x = 4(10.3 - x)
16.6 - x = 41.2 - 4x16.6 - x + 4x = 41.216.6 + 3x = 41.23x = 24.6x = 8.2
Removed from B: 8.2L → B has 10.3 - 8.2 = 2.1L
Removed from A: 10.2L → A has 18.6 - 10.2 = 8.4L
Ratio: 8.4 ÷ 2.1 = 4 ✓
8.2 liters was removed from container B.
Let x = amount added to each
After addition: 18.6 + x = 2(10.3 + x)
18.6 + x = 20.6 + 2x18.6 + x - 2x = 20.618.6 - x = 20.6-x = 2x = -2
The negative answer means this scenario is impossible! Container A starts with more than twice what B has (18.6 > 2 × 10.3 = 20.6 is false, but 18.6 > 2 × 10.3 = 20.6 let me recalculate: 2 × 10.3 = 20.6, and 18.6 < 20.6).
Actually: 18.6 + x = 20.6 + 2x18.6 - 20.6 = 2x - x-2 = x
This means we'd need to remove 2L to achieve a 2:1 ratio, not add.
Impossible as stated. A already has less than twice B's amount, so adding equal amounts would move further from a 2:1 ratio.
Frequently Asked Questions
2026-09-14