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Created on: 2012-04-11

A sample problem solved by Quickmath algebra calculator

Command

Solve

Equation
6*(3*x-2)/7 = 3*x-3

  1. an equation LHS is a quotient: dividend of the quotient is a product of 2 factors. The first factor of the product is equal to six. The second factor of the product is equal to a sum that comprises 2 terms. The first term of the sum is equal to a product consisting of 2 factors. The first factor of the product is equal to three. The second factor of the product is x. The second term of the sum is equal to negative two. Divisor of the quotient is seven Right side of the equation is equal to a sum containing 2 terms. The first term of the sum is equal to a product consisting of 2 factors. The first factor of the product is three. The second factor of the product is equal to x. The second term of the sum is negative three.
  2. six multiplied by opening parenthesis three times x plus negative two closing parenthesis fraction line seven is equal to three times x plus negative three.
Variable
Result

Exact

x = 3

  1. an equation Left side of the equation is equal to x Right side of the equation is three.
  2. x is three.