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Created on: 2012-02-15

A sample problem solved by Quickmath math solver

Command

Solve

Equation
4*(8*n+3)-5 = 2*(6*n+8)+1

  1. an equation Left side of the equation is equal to a sum that comprises 2 terms. The 1st term of the sum is equal to a product consisting of 2 factors. The 1st factor of the product is four. The 2nd factor of the product is a sum that comprises 2 terms. The 1st term of the sum is equal to a product that contains 2 factors. The 1st factor of the product is equal to eight. The 2nd factor of the product is equal to n. The 2nd term of the sum is equal to three. The 2nd term of the sum is equal to negative five RHS is equal to a sum containing 2 terms. The 1st term of the sum is equal to a product comprising 2 factors. The 1st factor of the product is two. The 2nd factor of the product is equal to a sum comprising 2 terms. The 1st term of the sum is equal to a product of 2 factors. The 1st factor of the product is equal to six. The 2nd factor of the product is n. The 2nd term of the sum is equal to eight. The 2nd term of the sum is equal to one.
  2. four multiplied by left brace eight times n plus three right brace plus negative five is equal to two multiplied by open parenthesis six multiplied by n plus eight close parenthesis plus one.
Variable
Result

Exact

n = 1/2

  1. an equation Left side of the equation is equal to n RHS is a fraction: the top of the fraction is one; the bottom of the fraction is two;
  2. n is equal to one fraction line two.


Approximate

n = 0.5

  1. an equation Left side of the equation is n RHS is equal to zero point five;
  2. n is equal to zero point and five tenth;