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Created on: 2012-01-12

A sample problem solved by Quickmath online math calculator

finding solution to 2*x2+5*x-12 <= 0 inequality

Command

Partial Fractions

Expression
1/(x^3-3*x^2+7*x-5)

  1. A rational expression: the numerator of the rational expression is one. The denominator of the rational expression is a sum of 4 terms. The 1st term of the sum is equal to a power. The base is x. The exponent is three. The 2nd term of the sum is a negative product consisting of 2 factors. The 1st factor of the product is equal to three. The 2nd factor of the product is a power. The base is x. The exponent is two. The 3rd term of the sum is equal to a product comprising 2 factors. The 1st factor of the product is equal to seven. The 2nd factor of the product is equal to x. The 4th term of the sum is equal to negative five.
  2. one over x raised to the power three plus negative three multiplied by x to the power of two plus seven times x plus negative five.
Result
1/(4*(x-1))-(x-1)/(4*(x^2-2*x+5))

  1. A sum containing 2 terms. The 1st term of the sum is equal to a rational expression: the numerator of the rational expression is one. The denominator of the rational expression is a product of 2 factors. The 1st factor of the product is equal to four. The 2nd factor of the product is equal to a sum containing 2 terms. The 1st term of the sum is equal to x. The 2nd term of the sum is negative one. The 2nd term of the sum is equal to a negative fraction: the numerator of the fraction is a sum that contains 2 terms. The 1st term of the sum is equal to x. The 2nd term of the sum is negative one. The denominator of the fraction is a product comprising 2 factors. The 1st factor of the product is equal to four. The 2nd factor of the product is a sum that consists of 3 terms. The 1st term of the sum is equal to a power. The base is x. The exponent is two. The 2nd term of the sum is a negative product of 2 factors. The 1st factor of the product is two. The 2nd factor of the product is equal to x. The 3rd term of the sum is five.
  2. one over four times open bracket x plus negative one close bracket plus negative x plus negative one divided by four multiplied by opening brace x raised to the power two plus negative two times x plus five closing brace.