QuickMath Download on App Store Download on Google Play
Welcome to Quickmath Solvers! Download on App Store Download on Google Play
Created on: 2012-01-12

A sample problem solved by Quickmath web math solver

the result of factorizing 3*(5*x-6)*(2*x-3)^3+(5*x-6)^2*(2*x-3) | expanding (z+4)/((z-1)*(z-2)*(z-3)) into partial fractions

Command

Solve

Equation
5-2*x/5+x+(-4)/10 = 3/10

  1. an equation Left side of the equation is a sum containing 4 terms. The first term of the sum is five. The second term of the sum is equal to a negative fraction: the top of the fraction is a product of 2 factors. The first factor of the product is two. The second factor of the product is equal to x. The bottom of the fraction is five. The third term of the sum is equal to x. The four term of the sum is equal to a fraction: the top of the fraction is negative four. The bottom of the fraction is ten RHS is equal to a fraction: the top of the fraction is three. The bottom of the fraction is ten.
  2. five plus negative two multiplied by x over five plus x plus negative four divided by ten is equal to three divided by ten.
Variable
Result

Exact

x = -43/6

  1. an equation Left side of the equation is equal to x Right side of the equation is a fraction: the numerator of the fraction is negative forty three. The denominator of the fraction is six.
  2. x is negative forty three divided by six.


Approximate

x = -7.16667

  1. an equation LHS is x Right side of the equation is equal to negative seven point one tenth, six hundredth, six ten hundredth, six thousandth and seven ten thousandth.
  2. x is equal to negative seven point one six six six seven;