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Created on: 2011-12-28

A sample problem solved by Quickmath algebra solver

Command

Solve

Equation
(7.23*(13*1.14)+50+20)*1.025 = x

  1. an equation Left side of the equation is a product consisting of 2 factors. The 1st factor of the product is a sum that contains 3 terms. The 1st term of the sum is equal to a product of 2 factors. The 1st factor of the product is equal to seven point two tenth and three hundredth. The 2nd factor of the product is a product consisting of 2 factors. The 1st factor of the product is thirteen. The 2nd factor of the product is equal to one point one tenth and four hundredth. The 2nd term of the sum is fifty. The 3rd term of the sum is equal to twenty. The 2nd factor of the product is equal to one point zero two five Right side of the equation is x.
  2. left brace seven point two tenth and three hundredth multiplied by open parenthesis thirteen multiplied by one point one tenth and four hundredth close parenthesis plus fifty plus twenty right brace multiplied by one point zero two five is equal to x;
Variable
Result

Exact

x = 392207/2160

  1. an equation LHS is equal to x RHS is equal to a quotient: dividend of the quotient is three hundred and ninety two thousand and two hundred and seven. Divisor of the quotient is two thousand and one hundred sixty.
  2. x is equal to three hundred and ninety two thousand and two hundred and seven fraction line two thousand and one hundred sixty;


Approximate

x = 181.577

  1. an equation LHS is equal to x RHS is one hundred eighty one point five seven seven;
  2. x is one hundred eighty one point five tenth, seven hundredth and seven ten hundredth.