Find Two Ages Using a System of Equations

Age Problems 7th-8th Grade
PROBLEM
Richard and Teo have a combined age of 24. Richard is 3 years older than twice Teo's age. How old are Richard and Teo?

What This Problem Teaches

  • How to translate age relationships into algebraic expressions
  • Setting up a single-variable equation from a system of constraints
  • Working with the phrase "older than twice" in mathematical context
  • Verifying solutions by checking both the sum and the relationship
  • Recognizing when substitution simplifies a two-variable system into one equation

Solution: Method 1 — The Substitution Strategy

When one age is defined in terms of another, we can use a single variable and substitute to create one equation.

Step 1 — Choose the variable

Let t = Teo's age in years. We choose Teo because Richard's age is described in terms of Teo's age.

Step 2 — Express Richard's age

The phrase "Richard is 3 years older than twice Teo's age" translates to:

Richard's age = 2t + 3

This means we first take twice Teo's age (2t), then add 3 years to get Richard's age.

Step 3 — Set up the sum equation

Their combined age is 24, so:

Teo's age + Richard's age = 24
t + (2t + 3) = 24

Step 4 — Solve for Teo's age

Combine like terms on the left side:

t + 2t + 3 = 24
3t + 3 = 24
3t = 21
t = 7

So Teo is 7 years old.

Step 5 — Find Richard's age

Substitute t = 7 into Richard's age formula:

Richard's age = 2t + 3 = 2(7) + 3 = 14 + 3 = 17

So Richard is 17 years old.

Teo is 7 years old and Richard is 17 years old.

Solution: Method 2 — The Two-Variable System

We can also solve this using two variables and formal substitution between equations.

Step 1 — Define both variables

Let R = Richard's age and T = Teo's age.

Step 2 — Write both equations

From "combined age of 24":

R + T = 24 (Equation 1)

From "Richard is 3 years older than twice Teo's age":

R = 2T + 3 (Equation 2)

Step 3 — Substitute equation 2 into equation 1

Replace R in equation 1 with 2T + 3:

(2T + 3) + T = 24
3T + 3 = 24
3T = 21
T = 7

Step 4 — Find Richard's age using equation 2

R = 2T + 3 = 2(7) + 3 = 17

Both methods give us the same answer: Teo is 7 and Richard is 17.

Verification

Let's check both conditions with our answer:

Check the sum

Teo's age + Richard's age = 7 + 17 = 24 ✓

Check the relationship

Twice Teo's age + 3 = 2(7) + 3 = 14 + 3 = 17 ✓
Richard's age = 17 ✓

Both conditions are satisfied, confirming our answer is correct.

Common Pitfalls

✗ MISTAKE 1: Confusing "older than twice"

Writing Richard's age as 3 × 2t or 6t instead of 2t + 3. The phrase "3 years older than twice Teo's age" means you first double Teo's age, then add 3. It's not "3 times twice Teo's age."

✗ MISTAKE 2: Setting up the wrong sum equation

Writing the sum as t + 2t = 24 and forgetting the "+3". You must include the full expression for Richard's age: t + (2t + 3) = 24.

✗ MISTAKE 3: Arithmetic error in the final step

Getting t = 7 correctly but then calculating Richard's age as 2(7) + 3 = 16. Double-check: 2 × 7 = 14, and 14 + 3 = 17.

How to Spot This Problem Type

Look for these key phrases in age problems:

  • "Combined age" or "total age" — signals you need a sum equation
  • "older than twice" or "younger than double" — indicates a linear relationship
  • "3 years older than twice [name's] age" — translates to 2x + 3
  • Two people with one constraint each — perfect for substitution method
Recognition tip: Any time you see ages described with both a sum AND a relationship, you're looking at a system that can usually be solved with substitution.

The Underlying Pattern

This problem follows the classic sum-and-relationship pattern:

If two quantities have sum S, and one equals mx + b where x is the other,
then x + (mx + b) = S, which gives x = (S - b)/(m + 1)

In our case: S = 24, m = 2, b = 3, so x = (24 - 3)/(2 + 1) = 21/3 = 7.

This formula works whenever one quantity is a linear function of the other. Age problems, money problems, and measurement problems often follow this structure.

What If?

1
Different Sum
Richard and Teo have a combined age of 30. Richard is 3 years older than twice Teo's age. How old are Richard and Teo?
Step 1 — Set up the equation

Let t = Teo's age. Then Richard's age = 2t + 3. Their sum: t + (2t + 3) = 30

Step 2 — Solve for t

3t + 3 = 30, so 3t = 27, therefore t = 9

Step 3 — Find Richard's age

Richard's age = 2(9) + 3 = 18 + 3 = 21

Step 4 — Verify

Check: 9 + 21 = 30 ✓ and 21 = 2(9) + 3 = 21 ✓

Answer: Teo is 9 years old and Richard is 21 years old.

2
Different Relationship
Richard and Teo have a combined age of 24. Richard is 5 years older than twice Teo's age. How old are Richard and Teo?
Step 1 — Set up the equation

Let t = Teo's age. Richard's age = 2t + 5. Sum: t + (2t + 5) = 24

Step 2 — Solve

3t + 5 = 24, so 3t = 19, therefore t = 19/3 = 6⅓

Step 3 — Find Richard's age

Richard's age = 2(19/3) + 5 = 38/3 + 15/3 = 53/3 = 17⅔

Step 4 — Verify

Check: 6⅓ + 17⅔ = 24 ✓ and 17⅔ = 2(6⅓) + 5 ✓

Answer: Teo is 6⅓ years old and Richard is 17⅔ years old.

3
Three People
Richard, Teo, and Maria have a combined age of 36. Richard is 3 years older than twice Teo's age. Maria is the same age as Teo. Find all three ages.
Step 1 — Define variables

Let t = Teo's age. Then Maria = t and Richard = 2t + 3

Step 2 — Write the sum equation

Teo + Richard + Maria = 36, so t + (2t + 3) + t = 36

Step 3 — Solve

4t + 3 = 36, so 4t = 33, therefore t = 8.25

Step 4 — Find all ages

Teo = Maria = 8.25, Richard = 2(8.25) + 3 = 19.5

Step 5 — Verify

Check: 8.25 + 8.25 + 19.5 = 36 ✓

Answer: Teo and Maria are each 8.25 years old, Richard is 19.5 years old.

4
Reverse the Known
Richard is 3 years older than twice Teo's age. If Richard is currently 23 years old, what is their combined age?
Step 1 — Set up equation from Richard's age

Richard = 2t + 3 = 23, where t = Teo's age

Step 2 — Solve for Teo's age

2t + 3 = 23, so 2t = 20, therefore t = 10

Step 3 — Calculate combined age

Combined age = Teo + Richard = 10 + 23 = 33

Step 4 — Verify the relationship

Check: 2(10) + 3 = 20 + 3 = 23 = Richard's age ✓

Answer: Their combined age is 33 years.

Frequently Asked Questions

How do you set up equations for age problems with relationships?+
First identify what each person's age represents with a variable. If one age is described in terms of another, write that relationship as an equation. Then use the sum constraint. In this example, if Teo is t years old and Richard is 3 years older than twice Teo's age, then Richard is (2t + 3) years old, and t + (2t + 3) = 24.
What does "older than twice" mean in age problems?+
This phrase means you multiply the base age by 2, then add the difference. "Richard is 3 years older than twice Teo's age" translates to Richard = 2×(Teo's age) + 3. If Teo is 7, then twice Teo's age is 14, and Richard is 14 + 3 = 17.
How do you check your answer in age word problems?+
Substitute both ages back into the original conditions. Verify the sum matches what was given, and check that the relationship holds. Here, Teo (7) + Richard (17) = 24 ✓, and Richard (17) = 3 + 2×7 = 3 + 14 = 17 ✓.
NJ
Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

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This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-10-21