Combined Work Rate: Pipe and Hose Filling a Pool
What This Problem Teaches
- Converting individual completion times into work rates using reciprocals
- Understanding that combined work rates add together when sources operate simultaneously
- Adding fractions with different denominators in practical applications
- Converting combined rates back to completion times
- Recognizing the mathematical principle that faster combined work emerges from rate addition, not time averaging
Solution: Method 1 — The Rate Addition Approach
The key insight is that when multiple sources work together, their rates of work add up. We need to think in terms of "pools per hour" rather than "hours per pool."
Step 1 — Convert times to work rates
Each source's work rate is the reciprocal of its completion time:
Hose rate = 1/20 pools per hour
Step 2 — Add the rates to find combined rate
When both sources work together, their outputs combine:
To add these fractions, we need a common denominator. The LCM of 11 and 20 is 220:
1/20 = 11/220
Combined rate = 20/220 + 11/220 = 31/220 pools per hour
Step 3 — Convert combined rate back to completion time
To find how long it takes to fill 1 pool at this combined rate:
Time = 1 × (220/31) = 220/31 hours
Step 4 — Simplify the answer
Convert the improper fraction to a mixed number:
So 220/31 = 7 3/31 hours
Converting to hours and minutes: 3/31 × 60 ≈ 5.8 minutes
Solution: Method 2 — The Harmonic Mean Formula
For exactly two sources working together, there's a direct formula that saves steps.
Step 1 — Apply the combined work formula
When two sources with times t₁ and t₂ work together, the combined time T satisfies:
Step 2 — Substitute the given times
1/T = 20/220 + 11/220 = 31/220
Step 3 — Solve for T
Take the reciprocal of both sides:
This gives us the same answer: approximately 7 hours and 6 minutes.
Verification
Let's check our answer by seeing how much of the pool gets filled in 220/31 hours:
Hose contribution: (1/20) × (220/31) = 220/620 = 11/31 pools
Total: 20/31 + 11/31 = 31/31 = 1 pool ✓
Perfect! The contributions add up to exactly one complete pool.
Common Pitfalls
A common error is to calculate (11 + 20)/2 = 15.5 hours. This would be correct if the sources took turns, but when they work simultaneously, their combined effect is much stronger than the average.
Some students try 11 + 20 = 31 hours, thinking more sources means more time. This ignores that additional sources help, not hinder, the work.
When computing 1/11 + 1/20, students might incorrectly get 2/31 by adding numerators and denominators. Always find a proper common denominator: 20/220 + 11/220 = 31/220.
The Pattern Behind This
This problem exemplifies the general principle of rate addition in parallel systems. The formula for any number of sources working together is:
Where each individual rate equals 1/(completion time).
This same mathematical structure appears in physics (electrical conductors in parallel), computer science (parallel processing), and biology (metabolic pathways). The key insight is that when systems work independently toward the same goal, their capabilities add directly.
How to Spot This Problem Type
Watch for these telltale phrases that signal a combined work rate problem:
- "If X alone takes [time], and Y alone takes [time]..."
- "Working together, how long would it take?"
- "Both pipes/hoses/machines operating simultaneously"
- Any scenario involving parallel completion of a single task
The structure is always the same: individual completion times given, combined completion time unknown. The solution path is always through rate addition, never time averaging.
What If?
Pipe rate = 1/8 pools/hour, Hose rate = 1/20 pools/hour
Combined rate = 1/8 + 1/20. Using common denominator 40: 5/40 + 2/40 = 7/40 pools/hour
Time = 1 ÷ (7/40) = 40/7 hours = 5 5/7 hours ≈ 5 hours 43 minutes
In 40/7 hours: pipe fills (1/8) × (40/7) = 5/7 pools, hose fills (1/20) × (40/7) = 2/7 pools. Total: 7/7 = 1 pool ✓
Pipe A: 1/12 pools/hour, Pipe B: 1/18 pools/hour, Hose: 1/30 pools/hour
Combined rate = 1/12 + 1/18 + 1/30. LCM of 12, 18, 30 is 180.
15/180 + 10/180 + 6/180 = 31/180 pools/hour
Time = 180/31 hours = 5 25/31 hours ≈ 5 hours 48 minutes
Check: (1/12 + 1/18 + 1/30) × (180/31) = (31/180) × (180/31) = 1 pool ✓
Let h = hose time. Combined rate = 1/6 pools/hour
1/10 + 1/h = 1/6
1/h = 1/6 - 1/10
Common denominator 30: 1/h = 5/30 - 3/30 = 2/30 = 1/15
If 1/h = 1/15, then h = 15
The hose alone takes 15 hours
Check: 1/10 + 1/15 = 3/30 + 2/30 = 5/30 = 1/6 ✓
Pipe: +1/11 pools/hour (filling)
Hose: +1/20 pools/hour (filling)
Drain: -1/15 pools/hour (emptying)
Net rate = 1/11 + 1/20 - 1/15
LCM of 11, 20, 15 is 660:
60/660 + 33/660 - 44/660 = 49/660 pools/hour
Time = 660/49 hours = 13 27/49 hours ≈ 13 hours 33 minutes
In 660/49 hours: inflow = (60+33)/660 × 660/49 = 93/49, outflow = 44/660 × 660/49 = 44/49
Net: 93/49 - 44/49 = 49/49 = 1 pool ✓
Frequently Asked Questions
2026-10-31