Combined Work Rate: Pipe and Hose Filling a Pool

Work Rate 9th-10th Grade
PROBLEM
A swimming pool can be filled in 11 hours if water enters through a pipe alone, or in 20 hours if water enters through a hose alone. If water is entering through both the pipe and the hose, how long will it take to fill the pool?

What This Problem Teaches

  • Converting individual completion times into work rates using reciprocals
  • Understanding that combined work rates add together when sources operate simultaneously
  • Adding fractions with different denominators in practical applications
  • Converting combined rates back to completion times
  • Recognizing the mathematical principle that faster combined work emerges from rate addition, not time averaging

Solution: Method 1 — The Rate Addition Approach

The key insight is that when multiple sources work together, their rates of work add up. We need to think in terms of "pools per hour" rather than "hours per pool."

Step 1 — Convert times to work rates

Each source's work rate is the reciprocal of its completion time:

Pipe rate = 1/11 pools per hour
Hose rate = 1/20 pools per hour

Step 2 — Add the rates to find combined rate

When both sources work together, their outputs combine:

Combined rate = 1/11 + 1/20 pools per hour

To add these fractions, we need a common denominator. The LCM of 11 and 20 is 220:

1/11 = 20/220
1/20 = 11/220
Combined rate = 20/220 + 11/220 = 31/220 pools per hour

Step 3 — Convert combined rate back to completion time

To find how long it takes to fill 1 pool at this combined rate:

Time = Work ÷ Rate = 1 pool ÷ (31/220 pools/hour)
Time = 1 × (220/31) = 220/31 hours

Step 4 — Simplify the answer

Convert the improper fraction to a mixed number:

220 ÷ 31 = 7 remainder 3
So 220/31 = 7 3/31 hours

Converting to hours and minutes: 3/31 × 60 ≈ 5.8 minutes

Solution: Method 2 — The Harmonic Mean Formula

For exactly two sources working together, there's a direct formula that saves steps.

Step 1 — Apply the combined work formula

When two sources with times t₁ and t₂ work together, the combined time T satisfies:

1/T = 1/t₁ + 1/t₂

Step 2 — Substitute the given times

1/T = 1/11 + 1/20
1/T = 20/220 + 11/220 = 31/220

Step 3 — Solve for T

Take the reciprocal of both sides:

T = 220/31 hours ≈ 7.1 hours

This gives us the same answer: approximately 7 hours and 6 minutes.

The pool will be filled in 220/31 hours, which equals approximately 7 hours and 6 minutes.

Verification

Let's check our answer by seeing how much of the pool gets filled in 220/31 hours:

Pipe contribution: (1/11) × (220/31) = 220/341 = 20/31 pools
Hose contribution: (1/20) × (220/31) = 220/620 = 11/31 pools
Total: 20/31 + 11/31 = 31/31 = 1 pool ✓

Perfect! The contributions add up to exactly one complete pool.

Common Pitfalls

✗ Mistake 1: Averaging the times

A common error is to calculate (11 + 20)/2 = 15.5 hours. This would be correct if the sources took turns, but when they work simultaneously, their combined effect is much stronger than the average.

✗ Mistake 2: Adding times instead of rates

Some students try 11 + 20 = 31 hours, thinking more sources means more time. This ignores that additional sources help, not hinder, the work.

✗ Mistake 3: Incorrect fraction arithmetic

When computing 1/11 + 1/20, students might incorrectly get 2/31 by adding numerators and denominators. Always find a proper common denominator: 20/220 + 11/220 = 31/220.

The Pattern Behind This

This problem exemplifies the general principle of rate addition in parallel systems. The formula for any number of sources working together is:

Combined rate = Rate₁ + Rate₂ + Rate₃ + ...

Where each individual rate equals 1/(completion time).

This same mathematical structure appears in physics (electrical conductors in parallel), computer science (parallel processing), and biology (metabolic pathways). The key insight is that when systems work independently toward the same goal, their capabilities add directly.

How to Spot This Problem Type

Watch for these telltale phrases that signal a combined work rate problem:

  • "If X alone takes [time], and Y alone takes [time]..."
  • "Working together, how long would it take?"
  • "Both pipes/hoses/machines operating simultaneously"
  • Any scenario involving parallel completion of a single task

The structure is always the same: individual completion times given, combined completion time unknown. The solution path is always through rate addition, never time averaging.

What If?

1
Faster Source
The pipe can fill the pool in 8 hours alone, and the hose in 20 hours alone. How long working together?
Step 1 — Find individual rates

Pipe rate = 1/8 pools/hour, Hose rate = 1/20 pools/hour

Step 2 — Add the rates

Combined rate = 1/8 + 1/20. Using common denominator 40: 5/40 + 2/40 = 7/40 pools/hour

Step 3 — Convert to time

Time = 1 ÷ (7/40) = 40/7 hours = 5 5/7 hours ≈ 5 hours 43 minutes

Step 4 — Verify

In 40/7 hours: pipe fills (1/8) × (40/7) = 5/7 pools, hose fills (1/20) × (40/7) = 2/7 pools. Total: 7/7 = 1 pool ✓

2
Three Sources
A pool has three inlets: pipe A fills it in 12 hours, pipe B in 18 hours, and a hose in 30 hours. How long if all three work together?
Step 1 — Find individual rates

Pipe A: 1/12 pools/hour, Pipe B: 1/18 pools/hour, Hose: 1/30 pools/hour

Step 2 — Add all three rates

Combined rate = 1/12 + 1/18 + 1/30. LCM of 12, 18, 30 is 180.

15/180 + 10/180 + 6/180 = 31/180 pools/hour

Step 3 — Convert to time

Time = 180/31 hours = 5 25/31 hours ≈ 5 hours 48 minutes

Step 4 — Verify

Check: (1/12 + 1/18 + 1/30) × (180/31) = (31/180) × (180/31) = 1 pool ✓

3
Reverse the Unknown
A pipe and hose together can fill the pool in exactly 6 hours. The pipe alone takes 10 hours. How long would the hose take alone?
Step 1 — Set up the rate equation

Let h = hose time. Combined rate = 1/6 pools/hour

1/10 + 1/h = 1/6

Step 2 — Solve for hose rate

1/h = 1/6 - 1/10

Common denominator 30: 1/h = 5/30 - 3/30 = 2/30 = 1/15

Step 3 — Find hose time

If 1/h = 1/15, then h = 15

The hose alone takes 15 hours

Step 4 — Verify

Check: 1/10 + 1/15 = 3/30 + 2/30 = 5/30 = 1/6 ✓

4
With a Drain
The pipe fills the pool in 11 hours and the hose in 20 hours, but there's also a drain that empties the full pool in 15 hours. If all three (pipe, hose, drain) operate simultaneously, how long to fill the pool?
Step 1 — Identify positive and negative rates

Pipe: +1/11 pools/hour (filling)

Hose: +1/20 pools/hour (filling)

Drain: -1/15 pools/hour (emptying)

Step 2 — Calculate net rate

Net rate = 1/11 + 1/20 - 1/15

LCM of 11, 20, 15 is 660:

60/660 + 33/660 - 44/660 = 49/660 pools/hour

Step 3 — Find filling time

Time = 660/49 hours = 13 27/49 hours ≈ 13 hours 33 minutes

Step 4 — Verify

In 660/49 hours: inflow = (60+33)/660 × 660/49 = 93/49, outflow = 44/660 × 660/49 = 44/49

Net: 93/49 - 44/49 = 49/49 = 1 pool ✓

Frequently Asked Questions

Find each source's rate by taking the reciprocal of its individual time, add the rates together to get the combined rate, then take the reciprocal of the combined rate to find the time. In this problem: pipe rate = 1/11 pools/hour, hose rate = 1/20 pools/hour, combined rate = 1/11 + 1/20 = 31/220 pools/hour, so time = 220/31 ≈ 7.1 hours.
Because when sources work together, their outputs add up - each contributes its full rate simultaneously. Averaging times would assume they take turns, not that they work together. Here, the pipe contributes 1/11 pool per hour while the hose simultaneously contributes 1/20 pool per hour, giving a total of 31/220 pools per hour combined.
Take the reciprocal of the combined rate. If the combined rate is 31/220 pools per hour, then the time to fill 1 pool is 220/31 hours. Convert mixed numbers to hours and minutes: 220 ÷ 31 = 7 remainder 3, so 7 3/31 hours. The fraction 3/31 × 60 ≈ 5.8 minutes, giving about 7 hours 6 minutes total.
DN
Dr. Neven Jurkovic
Mathematics Professor

Expert in algebraic problem-solving and mathematical education. Specializing in making complex concepts accessible through step-by-step analysis.

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Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

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This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-10-31