Finding Individual Work Rate from Combined Rate

Work Rate Problems 9th-10th Grade
Problem
Shaun can shovel the driveway in 6 hours, but if his sister Ashley helps it would take 2 hours. How long would it take Ashley to shovel the driveway alone?

What This Problem Teaches

  • Rate addition principle: Individual work rates add together to give the combined rate
  • Converting between time and rate: If a job takes t hours, the rate is 1/t jobs per hour
  • Setting up rational equations: Work problems create equations with variables in denominators
  • Solving for unknown rates: Using algebra to find the missing piece of a rate relationship
  • Real-world rate reasoning: Understanding how cooperation speeds up task completion

Visualizing the Work Rates

Shaun can shovel the driveway in 6 hours, but if his sister Ashley helps it would take 2 hours. How long would it...

In work problems, think of each person contributing a fraction of the job per hour. These rates add together when people work simultaneously.

Solution: Method 1 — The Rate Addition Approach

Step 1 — Define the variable

Let t = the number of hours it takes Ashley to shovel the driveway alone.

Step 2 — Express individual work rates

Work rate = fraction of job completed per hour:

  • Shaun's rate: 1/6 driveway per hour (since he takes 6 hours alone)
  • Ashley's rate: 1/t driveway per hour (since she takes t hours alone)

Step 3 — Set up the rate equation

When working together, their rates add up. Since they complete the job in 2 hours together, their combined rate is 1/2 driveway per hour:

Shaun's rate + Ashley's rate = Combined rate
1/6 + 1/t = 1/2

Step 4 — Solve for t

Subtract Shaun's rate from both sides:

1/t = 1/2 - 1/6

Find a common denominator (6):

1/t = 3/6 - 1/6 = 2/6 = 1/3

Therefore:

t = 3

Solution: Method 2 — Work Accomplished Analysis

Step 1 — Calculate work done in the joint time

In the 2 hours they work together, we know the entire driveway gets shoveled. Let's see how much each person contributes.

Step 2 — Find Shaun's contribution

Shaun works at 1/6 driveway per hour. In 2 hours:

Shaun's work = (1/6) × 2 = 2/6 = 1/3 of the driveway

Step 3 — Find Ashley's contribution

Since the whole job is done, Ashley must do the remaining portion:

Ashley's work = 1 - 1/3 = 2/3 of the driveway

Step 4 — Calculate Ashley's rate and time

Ashley completes 2/3 of the job in 2 hours, so her rate is:

Ashley's rate = (2/3) ÷ 2 = 2/3 × 1/2 = 1/3 driveway per hour

To complete 1 whole driveway at this rate:

Time = 1 ÷ (1/3) = 3 hours
Ashley would take 3 hours to shovel the driveway alone.

Verification

Let's check our answer by substituting back into the original rate equation:

Shaun's rate + Ashley's rate = 1/6 + 1/3 = 1/6 + 2/6 = 3/6 = 1/2 ✓

This matches their combined rate of 1/2 driveway per hour (finishing in 2 hours). ✓

Alternative check: In 2 hours working together:

  • Shaun completes: 2 × (1/6) = 1/3 of the driveway
  • Ashley completes: 2 × (1/3) = 2/3 of the driveway
  • Total completed: 1/3 + 2/3 = 1 complete driveway ✓

Common Pitfalls

✗ Averaging the times

Students often think: "If Shaun takes 6 hours and together they take 2 hours, Ashley must take 6 - 2 = 4 hours." This ignores how rates actually combine.

✗ Setting up the wrong equation

Writing 6 + t = 2 confuses times with rates. Times don't add—rates do. The correct equation involves 1/6 + 1/t = 1/2.

✗ Forgetting to convert rate to time

Finding Ashley's rate as 1/3 and stopping there. Remember: if her rate is 1/3 job per hour, she takes 3 hours to complete 1 job.

✗ Arithmetic errors with fractions

Calculating 1/2 - 1/6 as 1/4 instead of 1/3. Always find a common denominator: 3/6 - 1/6 = 2/6 = 1/3.

Does This Answer Make Sense?

Ashley taking 3 hours alone is completely reasonable. Here's why:

  • She's faster than Shaun: 3 hours vs. 6 hours means Ashley works twice as fast
  • The improvement makes sense: Adding a faster worker should significantly reduce the combined time from 6 hours to 2 hours
  • Rate comparison: Ashley's rate (1/3 per hour) is indeed twice Shaun's rate (1/6 per hour)
  • Boundary check: If Ashley were infinitely fast, they'd finish in close to 0 hours. If she were infinitely slow, they'd still take about 6 hours. Our answer of 2 hours falls reasonably between these extremes.
Quick check: Ashley being faster than Shaun makes perfect sense—if she were slower, adding her help wouldn't speed things up this dramatically!

The General Formula

For any work problem where you know one person's time and the combined time, here's the pattern:

If person A takes time a alone, and together they take time c,
then person B takes time b where:

1/a + 1/b = 1/c

Solving for b: b = (a × c)/(a - c)

In our problem: a = 6, c = 2, so:

b = (6 × 2)/(6 - 2) = 12/4 = 3 hours

Important limitation: This formula only works when the faster worker's time is less than the combined time. If a ≤ c, the problem setup is impossible.

Where This Shows Up in Real Life

  • Computer processing: When multiple CPU cores work on the same task, their processing rates combine similarly
  • Manufacturing: Assembly lines with workers of different speeds—knowing combined output to optimize staffing
  • Network bandwidth: Combining multiple internet connections doubles your effective download rate
  • Medical dosing: When multiple drugs clear from the body at different rates, calculating combined clearance

What If?

1
The Slower Helper
Shaun can shovel the driveway in 4 hours. Working together, Shaun and Ashley can finish in 3 hours. How long would it take Ashley alone? Is she faster or slower than Shaun?
Step 1 — Set up the rate equation

Let t = Ashley's time alone. Shaun's rate is 1/4, Ashley's is 1/t, combined is 1/3:
1/4 + 1/t = 1/3

Step 2 — Solve for Ashley's rate

1/t = 1/3 - 1/4 = 4/12 - 3/12 = 1/12
Therefore t = 12

Step 3 — Compare speeds

Ashley takes 12 hours alone vs. Shaun's 4 hours, so Ashley is slower than Shaun.

Step 4 — Verify

1/4 + 1/12 = 3/12 + 1/12 = 4/12 = 1/3 ✓

Answer: Ashley takes 12 hours alone (slower than Shaun)

2
Finding Combined Time
Shaun takes 5 hours to shovel alone, and Ashley takes 3 hours alone. How long will it take them working together?
Step 1 — Find individual rates

Shaun's rate: 1/5 driveway per hour
Ashley's rate: 1/3 driveway per hour

Step 2 — Add the rates

Combined rate = 1/5 + 1/3 = 3/15 + 5/15 = 8/15 driveway per hour

Step 3 — Convert to time

Time = 1 ÷ (8/15) = 15/8 = 1.875 hours = 1 hour 52.5 minutes

Step 4 — Verify

In 1.875 hours: Shaun does 1.875 × (1/5) = 0.375, Ashley does 1.875 × (1/3) = 0.625
Total: 0.375 + 0.625 = 1 ✓

Answer: 1 hour and 52.5 minutes (or 15/8 hours)

3
Three-Person Team
Shaun (6 hours alone), Ashley (3 hours alone), and their friend Ben (4 hours alone) all work together. How long will it take the trio?
Step 1 — Find each person's rate

Shaun: 1/6 per hour
Ashley: 1/3 per hour
Ben: 1/4 per hour

Step 2 — Add all three rates

Combined rate = 1/6 + 1/3 + 1/4
Find common denominator (12): 2/12 + 4/12 + 3/12 = 9/12 = 3/4

Step 3 — Convert to time

Time = 1 ÷ (3/4) = 4/3 hours = 1 hour 20 minutes

Step 4 — Verify

In 4/3 hours each person completes: (4/3) × (1/6) + (4/3) × (1/3) + (4/3) × (1/4) = 2/9 + 4/9 + 3/9 = 9/9 = 1 ✓

Answer: 1 hour and 20 minutes (or 4/3 hours)

4
Sequential Work Challenge
Ashley starts shoveling alone. After 1 hour, Shaun joins her, and together they finish the remaining work in exactly 45 minutes. If Shaun would take 4 hours to do the whole job alone, how long would Ashley take alone?
Step 1 — Set up what we know

Let t = Ashley's time alone. Ashley works for 1 hour alone, then both work for 0.75 hours.
Shaun's rate: 1/4 per hour, Ashley's rate: 1/t per hour

Step 2 — Calculate work done

Ashley's solo work: 1 × (1/t) = 1/t
Combined work: 0.75 × (1/4 + 1/t) = 0.75 × (1/4) + 0.75 × (1/t)

Step 3 — Set up the equation

Total work = 1 complete job:
1/t + 0.75/4 + 0.75/t = 1
1/t + 3/16 + 3/(4t) = 1
(1 + 3/4)/t + 3/16 = 1
7/(4t) = 1 - 3/16 = 13/16

Step 4 — Solve for t

7/(4t) = 13/16
7 × 16 = 13 × 4t
112 = 52t
t = 112/52 = 28/13 ≈ 2.15 hours

Answer: Ashley would take 28/13 hours (about 2 hours 9 minutes) alone

Frequently Asked Questions

How do you combine individual work rates to find the total rate?+

Add the individual rates together. If one person completes 1/6 of a job per hour and another completes 1/t jobs per hour, their combined rate is 1/6 + 1/t jobs per hour. In this problem, we know their combined rate is 1/2 job per hour (since they finish in 2 hours together), so 1/6 + 1/t = 1/2.

What's the difference between work rate and time to complete a job?+

Work rate is jobs per unit time (like 1/6 job per hour), while completion time is the reciprocal (6 hours per job). If someone takes t hours to complete one job, their rate is 1/t jobs per hour. Here, Shaun takes 6 hours alone, so his rate is 1/6 job per hour.

Why can't you just average the individual times in work problems?+

Because rates add, not times. Averaging Shaun's 6 hours with Ashley's unknown time doesn't account for how much work each person actually does per hour. You must work with rates (jobs per hour), add those rates, then convert back to time. In this problem, the correct approach gives Ashley 3 hours, not an average.

NJ
Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

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This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-10-20