Multi-Leg Journey Problem: Running and Flying Times

Distance, Rate & Time 9th-10th Grade
PROBLEM
Eudora ran from her home to her laboratory at 12 km/h, then flew to school at 76 km/h. She traveled 120 km total in 2 hours. How long did she spend running and flying?

Picture This

Let's visualize Eudora's journey to understand what we're solving for:

Eudora ran from her home to her laboratory at 12 km/h, then flew to school at 76 km/h. She traveled 120 km total in 2...

The diagram shows our two unknowns: how much time Eudora spent at each speed. Since the total time is 2 hours, if she runs for t hours, she must fly for (2-t) hours.

What This Problem Teaches

  • Setting up systems of equations when you have multiple constraints
  • Recognizing that "distance = rate × time" applies to each segment separately
  • Using substitution to reduce two equations to one variable
  • Converting between different time units (hours to minutes)
  • Checking solutions by verifying they satisfy all original conditions

Solution: Method 1 — The Standard System Approach

This is a classic two-leg journey problem where we need to find how time is split between two different speeds.

Step 1 — Define the variables

Let t = time spent running (in hours)
Then (2 - t) = time spent flying (in hours)

We use this relationship because the total time is 2 hours, so the two time periods must add up to 2.

Step 2 — Set up the distance equation

Using distance = rate × time for each segment:

Distance running + Distance flying = Total distance
12t + 76(2 - t) = 120

Step 3 — Solve for running time

Expand the equation:

12t + 152 - 76t = 120
-64t + 152 = 120
-64t = 120 - 152
-64t = -32
t = 0.5

Step 4 — Find flying time

Flying time = 2 - t = 2 - 0.5 = 1.5 hours

Step 5 — Convert to minutes for clarity

Running time: 0.5 hours = 30 minutes
Flying time: 1.5 hours = 90 minutes

Solution: Method 2 — The Weighted Average Approach

Instead of setting up equations formally, we can think about this as finding the right "mix" of two different speeds to achieve the overall constraints.

Step 1 — Calculate what "all flying" would give us

If Eudora flew the entire 2 hours at 76 km/h:

Distance = 76 × 2 = 152 km

This is 32 km more than her actual 120 km journey.

Step 2 — Find the speed difference per hour

Each hour of running instead of flying reduces the distance by:

76 - 12 = 64 km per hour

Step 3 — Calculate running time needed

To reduce the distance by 32 km:

Running time = 32 ÷ 64 = 0.5 hours = 30 minutes

Step 4 — Find flying time

Flying time = 2 - 0.5 = 1.5 hours = 90 minutes

Answer: Eudora spent 30 minutes (0.5 hours) running and 90 minutes (1.5 hours) flying.

Verification

Let's check our answer by substituting back into the original constraints:

Time check: 0.5 + 1.5 = 2 hours ✓

Distance check:

  • Running distance: 12 km/h × 0.5 h = 6 km
  • Flying distance: 76 km/h × 1.5 h = 114 km
  • Total distance: 6 + 114 = 120 km ✓

Both constraints are satisfied, confirming our solution is correct.

Common Pitfalls

✗ Mistake: Averaging the speeds: (12 + 76) ÷ 2 = 44 km/h, then assuming she travels at 44 km/h for 2 hours.

Why this is wrong: This assumes she spends equal time at each speed, which is exactly what we need to determine. The average speed depends on the time spent at each speed.

✗ Mistake: Setting up the equation as 12t + 76t = 120.

Why this is wrong: This assumes both legs take the same time t, but we know the total time is 2 hours. The correct setup recognizes that if running takes t hours, flying takes (2-t) hours.

✗ Mistake: Using the total distance (120 km) to find individual distances before solving for time.

Why this is wrong: We can't know how the 120 km is split between running and flying until we know the time split. The distances and times are both unknowns that must be solved together.

The Pattern Behind This

This problem follows the general structure for multi-leg journey problems:

For n legs with speeds r₁, r₂, ..., rₙ and times t₁, t₂, ..., tₙ:

Time constraint: t₁ + t₂ + ... + tₙ = Total time
Distance constraint: r₁t₁ + r₂t₂ + ... + rₙtₙ = Total distance

The key insight is that you need as many constraints as unknowns. With two unknown times, we need two constraints: one for total time and one for total distance.

This pattern extends to problems with fuel efficiency (mpg), work rates (items/hour), or any scenario where you're combining different rates over different time periods.

How to Spot This Problem Type

Look for these tell-tale signs:

  • "Then" or "next" — signals multiple legs of a journey
  • Two different speeds/rates — running and flying, walking and driving, etc.
  • Total distance and total time both given — provides the two constraints needed
  • "How long did she spend...?" — asks for time breakdown, not just total time

Variations include: different vehicles with different fuel efficiency, workers with different productivity rates, or investments with different interest rates. The mathematical structure remains the same.

What If?

1
Speed Change
Eudora ran from her home to her laboratory at 10 km/h, then flew to school at 80 km/h. She traveled 120 km total in 2 hours. How long did she spend running and flying?
Step 1 — Set up variables

Let t = running time, so flying time = (2-t)

Step 2 — Distance equation

10t + 80(2-t) = 120

Step 3 — Solve

10t + 160 - 80t = 120
-70t = -40
t = 4/7 ≈ 0.571 hours

Step 4 — Flying time

Flying time = 2 - 4/7 = 10/7 ≈ 1.429 hours

Step 5 — Convert to minutes

Answer: Running: 34.3 minutes, Flying: 85.7 minutes

2
Three-Leg Journey
Eudora walked to the bus stop at 6 km/h, rode the bus at 40 km/h, then ran from the bus stop to school at 12 km/h. The total journey was 24 km in 1 hour. She spent twice as long on the bus as walking. How long was each segment?
Step 1 — Variables

Let w = walking time, then bus time = 2w, running time = 1-3w

Step 2 — Distance equation

6w + 40(2w) + 12(1-3w) = 24

Step 3 — Simplify

6w + 80w + 12 - 36w = 24
50w = 12
w = 0.24 hours

Step 4 — All times

Walking: 0.24 hours = 14.4 minutes
Bus: 0.48 hours = 28.8 minutes
Running: 0.28 hours = 16.8 minutes

3
Reverse the Unknown
Eudora ran for 20 minutes and flew for 100 minutes. Her total journey was 118 km. If her flying speed was 76 km/h, what was her running speed?
Step 1 — Convert times to hours

Running: 20 min = 1/3 hour
Flying: 100 min = 5/3 hours

Step 2 — Set up equation

Let r = running speed
r(1/3) + 76(5/3) = 118

Step 3 — Solve for r

r/3 + 380/3 = 118
r/3 = 118 - 380/3 = -26/3

Step 4 — This gives a negative speed!

Let's recalculate: r/3 + 380/3 = 354/3
r/3 = 354/3 - 380/3 = -26/3
Wait, let me fix this...

Step 5 — Correct calculation

r/3 = 118 - 380/3 = (354-380)/3 = -26/3
This is impossible! The problem as stated has no solution.

4
Optimization Challenge
Eudora must travel exactly 120 km. She can run at 12 km/h, fly at 76 km/h, or use any combination. What combination of running and flying minimizes her total travel time?
Step 1 — Set up the time function

Let d = distance running, then (120-d) = distance flying
Total time = d/12 + (120-d)/76

Step 2 — Recognize the pattern

Since 76 > 12, flying is always faster than running. To minimize time, minimize running distance.

Step 3 — Optimal strategy

Run distance = 0 km, Fly distance = 120 km

Step 4 — Calculate minimum time

Minimum time = 120/76 ≈ 1.58 hours = 94.7 minutes

Answer

Optimal solution: Fly the entire 120 km for a total time of 1.58 hours.

Frequently Asked Questions

How do you set up a system of equations for a two-speed journey? +
Write one equation for total time and one for total distance. Use distance = rate × time for each segment. In this problem: t + (2-t) = 2 hours for time, and 12t + 76(2-t) = 120 km for distance, where t is running time.
Why can't you just average the two speeds to solve this problem? +
The average speed depends on how much time is spent at each speed, which is exactly what we're trying to find. Simply averaging 12 and 76 km/h gives 44 km/h, but this assumes equal time at each speed - which may not be the case.
What's the difference between distance-rate-time problems with one speed versus two speeds? +
Single-speed problems use d = rt directly. Two-speed problems require a system of equations because you have multiple unknowns. Here we need to find two time values that satisfy both the total distance and total time constraints.
NJ
Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

Contact

This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-08-05