Multi-Leg Journey Problem: Running and Flying Times
Picture This
Let's visualize Eudora's journey to understand what we're solving for:
The diagram shows our two unknowns: how much time Eudora spent at each speed. Since the total time is 2 hours, if she runs for t hours, she must fly for (2-t) hours.
What This Problem Teaches
- Setting up systems of equations when you have multiple constraints
- Recognizing that "distance = rate × time" applies to each segment separately
- Using substitution to reduce two equations to one variable
- Converting between different time units (hours to minutes)
- Checking solutions by verifying they satisfy all original conditions
Solution: Method 1 — The Standard System Approach
This is a classic two-leg journey problem where we need to find how time is split between two different speeds.
Step 1 — Define the variables
Let t = time spent running (in hours)
Then (2 - t) = time spent flying (in hours)
We use this relationship because the total time is 2 hours, so the two time periods must add up to 2.
Step 2 — Set up the distance equation
Using distance = rate × time for each segment:
12t + 76(2 - t) = 120
Step 3 — Solve for running time
Expand the equation:
-64t + 152 = 120
-64t = 120 - 152
-64t = -32
t = 0.5
Step 4 — Find flying time
Flying time = 2 - t = 2 - 0.5 = 1.5 hours
Step 5 — Convert to minutes for clarity
Running time: 0.5 hours = 30 minutes
Flying time: 1.5 hours = 90 minutes
Solution: Method 2 — The Weighted Average Approach
Instead of setting up equations formally, we can think about this as finding the right "mix" of two different speeds to achieve the overall constraints.
Step 1 — Calculate what "all flying" would give us
If Eudora flew the entire 2 hours at 76 km/h:
This is 32 km more than her actual 120 km journey.
Step 2 — Find the speed difference per hour
Each hour of running instead of flying reduces the distance by:
Step 3 — Calculate running time needed
To reduce the distance by 32 km:
Step 4 — Find flying time
Flying time = 2 - 0.5 = 1.5 hours = 90 minutes
Verification
Let's check our answer by substituting back into the original constraints:
Time check: 0.5 + 1.5 = 2 hours ✓
Distance check:
- Running distance: 12 km/h × 0.5 h = 6 km
- Flying distance: 76 km/h × 1.5 h = 114 km
- Total distance: 6 + 114 = 120 km ✓
Both constraints are satisfied, confirming our solution is correct.
Common Pitfalls
✗ Mistake: Averaging the speeds: (12 + 76) ÷ 2 = 44 km/h, then assuming she travels at 44 km/h for 2 hours.
Why this is wrong: This assumes she spends equal time at each speed, which is exactly what we need to determine. The average speed depends on the time spent at each speed.
✗ Mistake: Setting up the equation as 12t + 76t = 120.
Why this is wrong: This assumes both legs take the same time t, but we know the total time is 2 hours. The correct setup recognizes that if running takes t hours, flying takes (2-t) hours.
✗ Mistake: Using the total distance (120 km) to find individual distances before solving for time.
Why this is wrong: We can't know how the 120 km is split between running and flying until we know the time split. The distances and times are both unknowns that must be solved together.
The Pattern Behind This
This problem follows the general structure for multi-leg journey problems:
Time constraint: t₁ + t₂ + ... + tₙ = Total time
Distance constraint: r₁t₁ + r₂t₂ + ... + rₙtₙ = Total distance
The key insight is that you need as many constraints as unknowns. With two unknown times, we need two constraints: one for total time and one for total distance.
This pattern extends to problems with fuel efficiency (mpg), work rates (items/hour), or any scenario where you're combining different rates over different time periods.
How to Spot This Problem Type
Look for these tell-tale signs:
- "Then" or "next" — signals multiple legs of a journey
- Two different speeds/rates — running and flying, walking and driving, etc.
- Total distance and total time both given — provides the two constraints needed
- "How long did she spend...?" — asks for time breakdown, not just total time
Variations include: different vehicles with different fuel efficiency, workers with different productivity rates, or investments with different interest rates. The mathematical structure remains the same.
What If?
Let t = running time, so flying time = (2-t)
10t + 80(2-t) = 120
10t + 160 - 80t = 120-70t = -40t = 4/7 ≈ 0.571 hours
Flying time = 2 - 4/7 = 10/7 ≈ 1.429 hours
Answer: Running: 34.3 minutes, Flying: 85.7 minutes
Let w = walking time, then bus time = 2w, running time = 1-3w
6w + 40(2w) + 12(1-3w) = 24
6w + 80w + 12 - 36w = 2450w = 12w = 0.24 hours
Walking: 0.24 hours = 14.4 minutes
Bus: 0.48 hours = 28.8 minutes
Running: 0.28 hours = 16.8 minutes
Running: 20 min = 1/3 hour
Flying: 100 min = 5/3 hours
Let r = running speedr(1/3) + 76(5/3) = 118
r/3 + 380/3 = 118r/3 = 118 - 380/3 = -26/3
Let's recalculate: r/3 + 380/3 = 354/3r/3 = 354/3 - 380/3 = -26/3
Wait, let me fix this...
r/3 = 118 - 380/3 = (354-380)/3 = -26/3
This is impossible! The problem as stated has no solution.
Let d = distance running, then (120-d) = distance flying
Total time = d/12 + (120-d)/76
Since 76 > 12, flying is always faster than running. To minimize time, minimize running distance.
Run distance = 0 km, Fly distance = 120 km
Minimum time = 120/76 ≈ 1.58 hours = 94.7 minutes
Optimal solution: Fly the entire 120 km for a total time of 1.58 hours.
Frequently Asked Questions
2026-08-05