Multi-Person Age Problem: Five Siblings

Age Problems 9th-10th Grade
PROBLEM
Max is 3 years older than Ethan. Olivia is twice as old as Grace. Lena is 2 years younger than Max. Grace is 4 years older than Ethan. The average age of Ethan and Grace is 10. What are the ages of all five siblings?

What This Problem Teaches

  • Managing multiple variables connected by linear relationships
  • Converting word relationships into algebraic expressions
  • Using averages as equation constraints in multi-variable problems
  • Systematic substitution to reduce complex systems to single equations
  • Verification strategies for problems with multiple interconnected answers

Solution: Method 1 — The Chain Substitution Approach

With five people and multiple relationships, the key insight is to express everyone's age in terms of one person's age, then use the average constraint to solve.

Step 1 — Choose the base variable

Let E = Ethan's age. We choose Ethan because many relationships reference him directly.

Step 2 — Express all ages in terms of Ethan's age

Using the given relationships:

Ethan = E
Grace = E + 4 (Grace is 4 years older than Ethan)
Max = E + 3 (Max is 3 years older than Ethan)
Lena = Max - 2 = (E + 3) - 2 = E + 1 (Lena is 2 years younger than Max)
Olivia = 2 × Grace = 2(E + 4) = 2E + 8 (Olivia is twice as old as Grace)

Step 3 — Use the average constraint

The average age of Ethan and Grace is 10, which means their ages sum to 20:

(Ethan + Grace) ÷ 2 = 10
Ethan + Grace = 20
E + (E + 4) = 20
2E + 4 = 20

Step 4 — Solve for Ethan's age

2E + 4 = 20
2E = 16
E = 8

Step 5 — Calculate everyone's age

Now that we know Ethan is 8, we can find all other ages:

Ethan = 8
Grace = 8 + 4 = 12
Max = 8 + 3 = 11
Lena = 8 + 1 = 9
Olivia = 2(12) = 24

Solution: Method 2 — Age Line Visualization

Sometimes a visual approach helps organize the relationships before diving into algebra.

Step 1 — Start with the average constraint

If Ethan and Grace average 10, their ages sum to 20. Since Grace is 4 years older than Ethan, we can find their individual ages by solving: E + (E + 4) = 20, giving us E = 8 and Grace = 12.

Step 2 — Create an age timeline

Once we know Ethan = 8 and Grace = 12, we can position everyone on an age line:

Max is 3 years older than Ethan. Olivia is twice as old as Grace. Lena is 2 years younger than Max. Grace is 4 years...

Step 3 — Apply each relationship

Working from our anchor ages:

Max = Ethan + 3 = 8 + 3 = 11 ✓
Lena = Max - 2 = 11 - 2 = 9 ✓
Olivia = 2 × Grace = 2 × 12 = 24 ✓

The visual shows the age gaps clearly: a tight cluster of four siblings between ages 8-12, with Olivia significantly older at 24.

The ages are: Ethan = 8, Grace = 12, Max = 11, Lena = 9, Olivia = 24

Verification

Let's confirm each relationship holds with our calculated ages:

✓ Max is 3 years older than Ethan: 11 = 8 + 3
✓ Grace is 4 years older than Ethan: 12 = 8 + 4
✓ Lena is 2 years younger than Max: 9 = 11 - 2
✓ Olivia is twice as old as Grace: 24 = 2 × 12
✓ Average age of Ethan and Grace: (8 + 12) ÷ 2 = 20 ÷ 2 = 10

All relationships check out perfectly. The constraint that tied everything together was the average—without it, we'd have had infinitely many solutions.

Common Pitfalls

✗ Mixing up "older than" and "younger than"

Students often write "Lena is 2 years younger than Max" as Lena = Max + 2 instead of Lena = Max - 2. The word "younger" means subtract, not add. A helpful check: if Max is 11 and Lena is younger, then Lena must be less than 11.

✗ Misunderstanding what an average constraint means

Some students try to set each individual age equal to the average: "Ethan = 10 and Grace = 10." But average doesn't mean equal—it means their sum divided by 2 equals 10, so their sum is 20. The individual ages can be different as long as they average to 10.

✗ Getting lost in the substitution chain

With multiple relationships, students sometimes substitute incorrectly. For instance, writing Lena = E + 3 - 2 = E + 1 but forgetting that Max = E + 3, so the correct substitution is Lena = (E + 3) - 2 = E + 1. Always substitute the full expression, not just the variable.

Recognizing This Problem in the Wild

Age problems with multiple people often signal themselves with these patterns:

Watch for these clues:
  • "A is X years older/younger than B"
  • "C is twice as old as D" (or other multiplicative relationships)
  • "The average age of..." or "The sum of their ages is..."
  • Three or more people with interconnected age relationships

The telltale sign you need the chain substitution method: when most ages are defined relative to other ages, rather than as absolute values. Look for the person mentioned most often in the relationships—they make the best choice for your base variable.

The Pattern Behind This

This problem demonstrates the general structure of constraint satisfaction with linear relationships. The mathematical pattern is:

1. Express all unknowns in terms of one variable
2. Use constraints (averages, sums, products) to create equations
3. Solve for the base variable
4. Substitute back to find all unknowns

This exact approach works for any problem where you have N unknowns connected by N-1 linear relationships, plus one constraint equation. The constraint equation is what makes the system solvable—without the average condition, we'd have infinitely many solutions since we could pick any age for Ethan and calculate the rest.

You'll see this pattern in economics (supply chains), physics (connected systems), and computer science (dependency graphs).

What If?

1
Change the Average
Max is 3 years older than Ethan. Olivia is twice as old as Grace. Lena is 2 years younger than Max. Grace is 4 years older than Ethan. The average age of Ethan and Grace is 12. What are the ages of all five siblings?
Step 1 — Set up the base variable

Let E = Ethan's age. Express all ages in terms of E: Grace = E + 4, Max = E + 3, Lena = E + 1, Olivia = 2(E + 4) = 2E + 8.

Step 2 — Use the new average constraint

Average of Ethan and Grace is 12, so: (E + E + 4) ÷ 2 = 12, which gives us 2E + 4 = 24.

Step 3 — Solve for E

2E + 4 = 24 → 2E = 20 → E = 10

Step 4 — Calculate all ages

Ethan = 10, Grace = 14, Max = 13, Lena = 11, Olivia = 28

Verification

Check: (10 + 14) ÷ 2 = 12 ✓. All other relationships hold with the new ages.

2
Add a Sum Constraint
Max is 3 years older than Ethan. Olivia is twice as old as Grace. Lena is 2 years younger than Max. Grace is 4 years older than Ethan. The sum of all five ages is 70. What are their individual ages?
Step 1 — Express ages in terms of E

Let E = Ethan's age. Then Grace = E + 4, Max = E + 3, Lena = E + 1, Olivia = 2(E + 4) = 2E + 8.

Step 2 — Set up the sum equation

Sum of all ages = 70: E + (E + 4) + (E + 3) + (E + 1) + (2E + 8) = 70

Step 3 — Simplify and solve

E + E + 4 + E + 3 + E + 1 + 2E + 8 = 70 → 6E + 16 = 70 → 6E = 54 → E = 9

Step 4 — Find all ages

Ethan = 9, Grace = 13, Max = 12, Lena = 10, Olivia = 26

Verification

Sum check: 9 + 13 + 12 + 10 + 26 = 70 ✓

3
Add a Sixth Sibling
All original relationships remain the same, plus: Noah is 5 years younger than Olivia. The average age of all six siblings is 12. Given that Ethan and Grace still average 10, find Noah's age.
Step 1 — Find the original five ages

From the constraint that Ethan and Grace average 10, we get the same result as before: Ethan = 8, Grace = 12, Max = 11, Lena = 9, Olivia = 24.

Step 2 — Find Noah's age

Noah is 5 years younger than Olivia: Noah = 24 - 5 = 19

Step 3 — Verify the six-person average

Sum of all six ages: 8 + 12 + 11 + 9 + 24 + 19 = 83

Average: 83 ÷ 6 = 13.83... ≠ 12

Step 4 — Resolve the contradiction

The problem is over-constrained. We can't satisfy both "Ethan and Grace average 10" AND "all six average 12" with these relationships. One constraint must be relaxed.

4
Reverse the Unknown
The ages are: Ethan = 12, Grace = 16, Max = 15, Lena = 13, Olivia = 32. If Max is still 3 years older than Ethan, Grace is still 4 years older than Ethan, and Lena is still 2 years younger than Max, what multiple of Grace's age is Olivia?
Step 1 — Verify the given relationships

Check: Max = 15, Ethan = 12, so Max is 15 - 12 = 3 years older than Ethan ✓

Grace = 16, Ethan = 12, so Grace is 16 - 12 = 4 years older than Ethan ✓

Lena = 13, Max = 15, so Lena is 15 - 13 = 2 years younger than Max ✓

Step 2 — Find the relationship between Olivia and Grace

Olivia = 32, Grace = 16

Ratio: 32 ÷ 16 = 2

Step 3 — State the answer

Olivia is 2 times Grace's age.

Verification

Check: 2 × 16 = 32 = Olivia's age ✓

Frequently Asked Questions

How do you solve a multi-person age problem with relationships?+
Define one person's age as the variable, then express all other ages in terms of that variable using the given relationships. Use any additional constraints (like averages or sums) to set up an equation you can solve. In this problem, if Ethan is E years old, then Grace is E+4, Max is E+3, Lena is E+1, and Olivia is 2(E+4). The average constraint gives us (E + E+4)/2 = 10.
What does it mean when the average age of two people is 10?+
It means their ages add up to 20, since average = sum ÷ count. If Ethan and Grace have an average age of 10, then (Ethan's age + Grace's age) ÷ 2 = 10, which means Ethan's age + Grace's age = 20.
How do you check your answer in an age problem?+
Verify that each stated relationship holds true with your calculated ages, and check any numerical constraints like averages or sums. Here we confirm Max (11) is 3 years older than Ethan (8), Grace (12) is 4 years older than Ethan, and so on, plus that the average of Ethan and Grace is indeed 10.
NJ
Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

Contact

This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-11-01