Combined Work Rate: Two Drainage Pipes

Work Rate Problems 9th-10th Grade
Problem
A swimming pool holds 540,000 liters of water. The pool has two drainage pipes. When the pool is completely full, the first pipe alone can empty it in 180 minutes, and the second pipe alone can empty it in 120 minutes. When both pipes are draining together, how long does it take them to empty the pool?

Skills This Problem Builds

  • Converting individual completion times to work rates
  • Understanding that combined rates add when working toward the same goal
  • Using dimensional analysis to track units throughout calculations
  • Recognizing the relationship between rate, time, and total work
  • Applying the work rate formula to real-world drainage scenarios

Picture This

A swimming pool holds 540,000 liters of water. The pool has two drainage pipes. When the pool is completely full, the...

Solution: Method 1 — The Unit Rate Approach

The key insight is to convert each pipe's completion time into a drainage rate, then add those rates together.

Step 1 — Find each pipe's drainage rate

Rate equals work divided by time, so we divide the pool volume by each pipe's individual completion time.

Pipe 1 rate = 540,000 L ÷ 180 min = 3000 L/min
Pipe 2 rate = 540,000 L ÷ 120 min = 4500 L/min

Step 2 — Add the rates to find combined drainage

When both pipes work together, their rates add because they're both removing water from the same pool.

Combined rate = 3000 L/min + 4500 L/min = 7500 L/min

Step 3 — Calculate time using the combined rate

Now we divide the total work by the combined rate to find the time needed.

Time = Total work ÷ Combined rate
Time = 540,000 L ÷ 7500 L/min = 72 minutes

Solution: Method 2 — The Reciprocal Formula

There's an elegant shortcut when you're given individual completion times and need the combined time.

Step 1 — Apply the harmonic mean formula

For two workers (or pipes) that complete a job in times a and b, the combined time is ab/(a + b).

Combined time = (180 × 120) ÷ (180 + 120)
Combined time = 21,600 ÷ 300
Combined time = 72 minutes

Step 2 — Understand why this works

This formula comes from adding the work fractions. Pipe 1 completes 1/180 of the job per minute, Pipe 2 completes 1/120 per minute. Together they complete (1/180 + 1/120) = 1/72 of the job per minute.

1/180 + 1/120 = 2/360 + 3/360 = 5/360 = 1/72
So the job takes 72 minutes to complete.
Answer: 72 minutes (1 hour and 12 minutes)

Verification

Let's verify by calculating how much work each pipe accomplishes in 72 minutes:

Check using individual rates:
• Pipe 1 drains: 3000 L/min × 72 min = 216,000 L
• Pipe 2 drains: 4500 L/min × 72 min = 324,000 L
• Total drained: 216,000 + 324,000 = 540,000 L ✓

Check using work fractions:
In 72 minutes, Pipe 1 completes 72/180 = 2/5 of the job
In 72 minutes, Pipe 2 completes 72/120 = 3/5 of the job
Together: 2/5 + 3/5 = 5/5 = 1 complete job ✓

Watch Out For These

✗ Averaging the times: (180 + 120) ÷ 2 = 150 minutes
This treats the pipes as if they alternate working instead of working together. When rates add, times don't average—they get shorter than either individual time.
✗ Forgetting to convert to rates: "Both pipes together take 180 + 120 = 300 minutes"
This adds the completion times instead of the work rates. Two pipes working together always finish faster than either one alone.
✗ Using the wrong formula: ab ÷ (a - b) instead of ab ÷ (a + b)
The harmonic mean formula for combined work is ab/(a+b), not ab/(a-b). The subtraction version would give a negative time when both pipes have the same speed.

Recognizing This Problem Type

Look for these telltale signs that signal a combined work rate problem:

  • "Working together" or "both pipes draining" — multiple agents doing the same task
  • Individual completion times given — "Pipe A alone takes X minutes, Pipe B alone takes Y minutes"
  • Same type of work — filling, draining, building, or completing identical tasks
  • Question asks for combined time — "How long together?" or "How long with both?"

This problem structure appears in manufacturing (two machines making widgets), construction (two crews building), data processing (two servers handling requests), and anywhere multiple agents work in parallel toward the same goal.

The General Formula

For any number of workers or pipes completing the same job:

Combined Rate = Sum of Individual Rates
Combined Time = Total Work ÷ Combined Rate

For exactly two workers with times a and b:
Combined Time = ab/(a + b)

The reciprocal formula only works cleanly for two workers. With three or more, it's usually faster to convert to rates, add them, then find the time. Also remember this formula assumes all workers start and stop together—it doesn't handle scenarios where one worker leaves early or joins late.

Real Applications

Network engineering: When two internet connections are bonded, their bandwidths add. A 50 Mbps line and a 30 Mbps line together provide 80 Mbps of total throughput.

Manufacturing: Two assembly machines producing identical parts work at combined rates. If Machine A produces 100 units/hour and Machine B produces 150 units/hour, together they produce 250 units/hour.

Medical infusion: Multiple IV drips delivering the same medication combine their flow rates. This calculation ensures patients receive the intended dosage rate when multiple access points are used.

What If?

1
Half-Full Pool
The pool holds 540,000 L when full. If it is only half full (270,000 L), and both pipes drain together at their usual rates, how long will it take to empty?
Step 1 — The rates don't change

Pipe 1 still drains at 3000 L/min and Pipe 2 at 4500 L/min, so combined rate is still 7500 L/min.

Step 2 — Calculate time for half the volume

Time = 270,000 L ÷ 7500 L/min = 36 minutes

Verification

In 36 minutes: Pipe 1 drains 3000 × 36 = 108,000 L, Pipe 2 drains 4500 × 36 = 162,000 L. Total: 270,000 L ✓

Answer: 36 minutes

2
Adding a Third Pipe
A third pipe can empty the full pool alone in 90 minutes. If all three pipes drain together, how long does it take to empty the full 540,000 L pool?
Step 1 — Find the third pipe's rate

Pipe 3 rate = 540,000 L ÷ 90 min = 6000 L/min

Step 2 — Add all three rates

Combined rate = 3000 + 4500 + 6000 = 13,500 L/min

Step 3 — Calculate combined time

Time = 540,000 L ÷ 13,500 L/min = 40 minutes

Verification

Total drained in 40 min: 3000×40 + 4500×40 + 6000×40 = 120,000 + 180,000 + 240,000 = 540,000 L ✓

Answer: 40 minutes

3
Partially Clogged Pipe
Pipe 1 normally empties the pool in 180 minutes, but it is clogged and now drains at only 60% of its original rate. Pipe 2 works normally. How long does it take both pipes together to empty the full pool?
Step 1 — Calculate Pipe 1's reduced rate

Normal rate: 3000 L/min
Clogged rate: 3000 × 0.60 = 1800 L/min

Step 2 — Pipe 2 works normally

Pipe 2 rate: 4500 L/min (unchanged)

Step 3 — Find combined rate

Combined rate = 1800 + 4500 = 6300 L/min

Step 4 — Calculate time

Time = 540,000 ÷ 6300 = 85.7 minutes ≈ 86 minutes

Answer: 86 minutes

4
Reverse Engineering
When both pipes are open, the full pool empties in 72 minutes. Pipe 1 alone can empty it in 180 minutes. How long would Pipe 2 alone take to empty the pool?
Step 1 — Find the combined rate

Combined rate = 540,000 L ÷ 72 min = 7500 L/min

Step 2 — Find Pipe 1's rate

Pipe 1 rate = 540,000 L ÷ 180 min = 3000 L/min

Step 3 — Calculate Pipe 2's rate

Since rates add: Pipe 2 rate = 7500 - 3000 = 4500 L/min

Step 4 — Find Pipe 2's individual time

Time = 540,000 L ÷ 4500 L/min = 120 minutes

Verification

Check with reciprocal formula: (180 × 120) ÷ (180 + 120) = 21,600 ÷ 300 = 72 minutes ✓

Answer: 120 minutes

Frequently Asked Questions

How do you calculate combined work rates for draining or filling problems? +
Find each pipe's rate in volume per unit time, then add the rates together. In this problem, Pipe 1 drains at 3000 L/min and Pipe 2 at 4500 L/min, so together they drain at 7500 L/min. Then divide total volume by combined rate.
What's the difference between work rate problems and mixture problems? +
Work rate problems involve rates that add (like two pipes draining), while mixture problems involve concentrations that average. Here, we add drain rates (3000 + 4500 = 7500 L/min) because both pipes remove water from the same pool.
Can you use the reciprocal formula for combined work rates? +
Yes, when working with time-to-complete values. If job A takes time a and job B takes time b, combined time is ab/(a+b). In this problem: (180 × 120)/(180 + 120) = 21,600/300 = 72 minutes.
DN

Dr. Neven Jurkovic

Mathematics expert with 15+ years teaching algebra and problem-solving strategies

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Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

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This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-11-09