Raspberry and Grape Mixture Problem: Two-Variable System

Mixture Problems 9th-10th Grade
Problem
Arun runs a farm stand that sells raspberries and grapes. Each pound of raspberries sells for $2.50 and each pound of grapes sells for $3.75. Arun made $230.25 from selling a total of 66 pounds of raspberries and grapes. Determine the number of pounds of raspberries sold and the number of pounds of grapes sold.

What This Problem Teaches

  • Setting up and solving systems of two linear equations with real-world constraints
  • Translating word problems into mathematical relationships using quantity and value equations
  • Working strategically with decimal coefficients by clearing them early in the solution
  • Recognizing mixture problems as a fundamental application of linear systems
  • Checking solutions by verifying they satisfy both physical and financial constraints

Solution: The Elimination Method

Step 1 — Define the variables

Let r = pounds of raspberries sold and g = pounds of grapes sold.

Step 2 — Set up the system of equations

We need two equations based on the given information:

r + g = 66 (total weight)
2.50r + 3.75g = 230.25 (total revenue)

Step 3 — Eliminate decimals

To avoid calculation errors, multiply the second equation by 100:

r + g = 66
250r + 375g = 23025

Step 4 — Use elimination to solve

Multiply the first equation by 250 to match the coefficient of r:

250r + 250g = 16500
250r + 375g = 23025

Subtract the first equation from the second:

(250r + 375g) - (250r + 250g) = 23025 - 16500
125g = 6525
g = 52.2

Step 5 — Find the other variable

Substitute g = 52.2 into the first equation:

r + 52.2 = 66
r = 13.8

Solution: Method 2 — Substitution Approach

Step 1 — Express one variable in terms of the other

From the weight equation r + g = 66, we get:

r = 66 - g

Step 2 — Substitute into the revenue equation

Replace r in the revenue equation:

2.50(66 - g) + 3.75g = 230.25

Step 3 — Solve for g

Distribute and combine like terms:

165 - 2.50g + 3.75g = 230.25
165 + 1.25g = 230.25
1.25g = 65.25
g = 52.2

Step 4 — Find r using substitution

r = 66 - 52.2 = 13.8
Answer: Arun sold 13.8 pounds of raspberries and 52.2 pounds of grapes.

Verification

Let's check our solution by substituting back into both original equations:

Weight check:13.8 + 52.2 = 66

Revenue check:

2.50(13.8) + 3.75(52.2) = 34.50 + 195.75 = 230.25

Both conditions are satisfied, confirming our solution is correct.

Watch Out For These

✗ Mixing up price and quantity

Writing 2.50 + 3.75g = 230.25 instead of 2.50r + 3.75g = 230.25. Remember that revenue equals price per unit times quantity, not price plus quantity.

✗ Forgetting to multiply both sides when eliminating variables

When using elimination, you must multiply every term in the equation by the same factor. Don't multiply just one variable's coefficient.

✗ Decimal calculation errors

Working directly with decimals like 3.75g often leads to computational mistakes. Always clear decimals early by multiplying the entire equation by 100.

✗ Not checking the reasonableness of decimal answers

Students sometimes worry that 13.8 and 52.2 "don't look right" because they're not whole numbers. But fruit can absolutely be sold in fractional pounds—this answer is perfectly valid.

The Underlying Pattern

Every two-item mixture problem follows the same structure. If you have quantities x and y with unit values v₁ and v₂, total quantity Q, and total value V, then:

x + y = Q (quantity equation)
v₁x + v₂y = V (value equation)

The key insight is that you always need exactly two pieces of information to find two unknowns. Mixture problems provide total quantity and total value, which gives you the perfect setup for a linear system.

When decimals are unavoidable: If the arithmetic produces non-whole answers, that's completely normal in mixture problems. Unlike problems involving discrete objects (coins, people), mixture problems often have fractional solutions because quantities can be measured continuously.

How to Spot This Problem Type

Look for these tell-tale phrases that signal a mixture problem:

  • "Each [item A] costs $X and each [item B] costs $Y"
  • "Total of [number] pounds/gallons/units"
  • "Made $[amount] from selling" or "total revenue/value was"
  • "Mixture," "combination," or "blend" of two different items with different prices
  • Problems involving coffee blends, fruit sales, ticket sales with different prices, or investments with different rates

The pattern is always: two different items, different unit prices, known total quantity, and known total value. Once you recognize this structure, you know you're setting up the same type of system every time.

Does This Seem Reasonable?

Let's do a quick sanity check on our answer:

Arun sold 13.8 pounds of raspberries and 52.2 pounds of grapes. Notice that he sold almost four times as many grapes as raspberries. Does this make sense?

Since grapes cost $3.75/lb and raspberries cost $2.50/lb, grapes are 50% more expensive. If Arun had sold equal amounts of each (33 lbs each), the revenue would have been:

33 × $2.50 + 33 × $3.75 = $82.50 + $123.75 = $206.25

But he actually made $230.25, which is $24 more than this "equal split" scenario. To make that extra money, he needed to sell more of the expensive grapes and fewer of the cheap raspberries. So yes, the lopsided split toward grapes makes perfect economic sense.

Where This Shows Up in Real Life

  • Coffee roasting: Blending different coffee beans with different costs per pound to achieve a target blend price and total quantity
  • Investment portfolios: Allocating money between investments with different returns when you know the total invested and total return
  • Manufacturing: Combining raw materials with different costs to produce a fixed quantity at a target total material cost

What If?

1
Price Change on Grapes
Arun still sold 66 total pounds and made $230.25, but grapes now cost $4.00 per pound while raspberries remain $2.50 per pound. How many pounds of each did he sell?
Step 1 — Set up the new system

r + g = 66 and 2.50r + 4.00g = 230.25

Step 2 — Clear decimals

Multiply the second equation by 100: 250r + 400g = 23025

Step 3 — Use elimination

Multiply first equation by 250: 250r + 250g = 16500
Subtract: 150g = 6525, so g = 43.5

Step 4 — Find r

r = 66 - 43.5 = 22.5

Verification

Check: 22.5 + 43.5 = 66 and 2.50(22.5) + 4.00(43.5) = 56.25 + 174 = 230.25

Answer: 22.5 pounds raspberries, 43.5 pounds grapes

2
Reverse the Unknown
Arun sold exactly 25 pounds of raspberries and 41 pounds of grapes at the original prices ($2.50 and $3.75). What was his total revenue? What price should grapes be if he wants to make exactly $250 from these same quantities?
Step 1 — Calculate original revenue

Revenue = 2.50(25) + 3.75(41) = 62.50 + 153.75 = 216.25

Step 2 — Set up equation for new grape price

Let p = new price per pound of grapes
2.50(25) + p(41) = 250

Step 3 — Solve for the new price

62.50 + 41p = 250
41p = 187.50
p = 4.57 (rounded to nearest cent)

Verification

Check: 2.50(25) + 4.57(41) = 62.50 + 187.37 = 249.87 ≈ 250

Answer: Original revenue was $216.25. Grapes should cost $4.57 per pound for $250 total.

3
Add a Third Fruit
Arun now sells raspberries ($2.50/lb), grapes ($3.75/lb), and blueberries ($5.00/lb). He sold 80 total pounds for $350. He sold twice as many pounds of raspberries as grapes. How many pounds of each fruit did he sell?
Step 1 — Define variables and constraint

Let r = raspberries, g = grapes, b = blueberries
Given: r = 2g (twice as many raspberries as grapes)

Step 2 — Set up system with substitution

r + g + b = 802g + g + b = 803g + b = 80
2.50r + 3.75g + 5.00b = 3502.50(2g) + 3.75g + 5.00b = 350
5g + 3.75g + 5b = 3508.75g + 5b = 350

Step 3 — Solve the two-variable system

From first: b = 80 - 3g
Substitute: 8.75g + 5(80 - 3g) = 350
8.75g + 400 - 15g = 350
-6.25g = -50
g = 8

Step 4 — Find all quantities

g = 8, so r = 2(8) = 16 and b = 80 - 3(8) = 56

Verification

Weight: 16 + 8 + 56 = 80
Revenue: 2.50(16) + 3.75(8) + 5.00(56) = 40 + 30 + 280 = 350

Answer: 16 lbs raspberries, 8 lbs grapes, 56 lbs blueberries

4
Whole Number Constraint
Arun can only sell fruit in whole-pound amounts. Using the original prices and needing exactly 66 pounds total, what whole number of pounds of raspberries and grapes gets closest to $230.25 in revenue?
Step 1 — Test values near the exact solution

Our exact solution was 13.8 lbs raspberries, 52.2 lbs grapes. Test whole numbers nearby.

Step 2 — Check (14, 52)

Revenue: 2.50(14) + 3.75(52) = 35 + 195 = 230
Error: |230 - 230.25| = 0.25

Step 3 — Check (13, 53)

Revenue: 2.50(13) + 3.75(53) = 32.50 + 198.75 = 231.25
Error: |231.25 - 230.25| = 1.00

Step 4 — Compare options

(14, 52) gives error of $0.25
(13, 53) gives error of $1.00
The first option is much closer.

Verification

Check totals: 14 + 52 = 66 pounds ✓

Answer: 14 pounds raspberries, 52 pounds grapes (revenue = $230.00)

Frequently Asked Questions

How do you set up a system of equations for a mixture problem?+
Write two equations: one for total quantity and one for total value. If you have two items with different prices and known total amount and revenue, let variables represent the quantities. In this example, r + g = 66 (total pounds) and 2.50r + 3.75g = 230.25 (total revenue), where r is pounds of raspberries and g is pounds of grapes.
When should you eliminate decimals in a system of equations?+
Always eliminate decimals when working with money to avoid rounding errors. Multiply the decimal equation by 100 or 1000 to convert to whole numbers. Here, multiplying 2.50r + 3.75g = 230.25 by 100 gives 250r + 375g = 23025, which is much cleaner to solve.
How do you check if your solution to a mixture problem is correct?+
Substitute your answers back into both original equations. Check that the quantities add to the given total and that price × quantity for each item sums to the total revenue. In this problem, 13.8 + 52.2 = 66 pounds, and (13.8 × $2.50) + (52.2 × $3.75) = $34.50 + $195.75 = $230.25.
NJ
Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

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This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-08-19