Pythagorean Theorem: Find Rectangle Diagonal Cut

Geometry 7th-8th Grade
PROBLEM
Liz takes a sheet of paper and cuts from one corner to the opposite corner, making two triangles. If the piece of paper is 60 inches long and 63 inches wide, how long is the diagonal cut that Liz made?

What This Problem Teaches

  • How diagonal cuts in rectangles create right triangles with predictable properties
  • Applying the Pythagorean theorem to find missing side lengths in real-world contexts
  • Recognizing that the rectangle's dimensions become the legs of a right triangle
  • Converting a geometry word problem into a mathematical formula
  • Understanding why diagonals are always longer than either individual dimension

Picture This

Liz takes a sheet of paper and cuts from one corner to the opposite corner, making two triangles. If the piece of...

When Liz cuts diagonally from corner A to corner C, she creates two identical right triangles. Each triangle has legs of 60 inches and 63 inches, with the diagonal cut as the hypotenuse.

Solution: Method 1 — Direct Pythagorean Application

Step 1 — Identify the right triangle

The diagonal cut creates a right triangle where the rectangle's length and width become the two legs. We have legs of 60 inches and 63 inches, and we need to find the hypotenuse (the diagonal cut).

Step 2 — Set up the Pythagorean theorem

For any right triangle, a² + b² = c², where c is the hypotenuse. In our case:

diagonal² = length² + width²
d² = 60² + 63²

Step 3 — Calculate the squares

Let's compute each squared term:

60² = 60 × 60 = 3,600
63² = 63 × 63 = 3,969

Step 4 — Add the squares

Now we add the results:

d² = 3,600 + 3,969 = 7,569

Step 5 — Take the square root

To find the diagonal length, we take the square root of both sides:

d = √7,569 = 87 inches

Solution: Method 2 — Factor Before Computing

Step 1 — Look for common factors

Before squaring, let's see if we can factor out common terms from 60 and 63:

60 = 3 × 20
63 = 3 × 21

Step 2 — Factor out the common term

We can factor out 3 from both dimensions:

d² = (3 × 20)² + (3 × 21)²
d² = 3²(20² + 21²)
d² = 9(400 + 441)
d² = 9(841)

Step 3 — Recognize the perfect squares

Notice that 841 = 29², so:

d² = 9 × 29²
d = 3 × 29 = 87 inches

This method often reveals when the answer will be a clean whole number, as it did here.

The diagonal cut that Liz made is 87 inches long.

Verification

Let's verify our answer by substituting back into the Pythagorean theorem:

87² = 60² + 63²
7,569 = 3,600 + 3,969
7,569 = 7,569 ✓

Perfect! Our calculation is correct. We can also do a reasonableness check: the diagonal (87 inches) is longer than either individual dimension (60 or 63 inches), which makes geometric sense.

Does This Seem Reasonable?

Let's think about whether 87 inches makes sense for a diagonal:

  • Longer than both dimensions: The diagonal (87") is longer than both the length (60") and width (63"), which it must be geometrically.
  • Not too much longer: If we were finding the perimeter, we'd add: 60 + 63 = 123 inches. The diagonal being 87 inches (much less than the perimeter) makes sense.
  • Clean number result: Getting exactly 87 (no decimals) suggests this problem was designed with a Pythagorean triple in mind—specifically, this is 3 times the (20, 21, 29) triple.

What Trips Students Up

❌ Adding instead of using Pythagorean theorem:
Some students calculate 60 + 63 = 123 inches.
Why this is wrong: This gives the distance if you walked along the edges, not the straight diagonal cut.
❌ Forgetting to take the square root:
Calculating 60² + 63² = 7,569 and stopping there.
Why this is wrong: This gives d², not d. You must take √7,569 = 87 to get the actual length.
❌ Mixing up length and width:
Worrying about which dimension is "length" vs "width."
Why this doesn't matter: Addition is commutative: a² + b² = b² + a². The order doesn't affect the final answer.

The Pattern Behind This

For any rectangle with length l and width w, the diagonal length d is:

d = √(l² + w²)

This formula works because cutting a rectangle corner-to-corner always creates two right triangles, where the rectangle's sides become the legs and the diagonal becomes the hypotenuse.

An interesting note: This problem uses a scaled version of the (20, 21, 29) Pythagorean triple. When you see "nice" dimensions in geometry problems, they're often chosen to produce clean answers using these special number relationships.

Where This Shows Up in Real Life

  • Construction: Carpenters use the "3-4-5 rule" (or larger versions) to ensure corners are perfectly square—if the diagonal matches the Pythagorean prediction, the corner is 90 degrees.
  • Screen sizes: TV and monitor sizes are measured diagonally. A "27-inch monitor" has a 27-inch diagonal, not 27-inch width or height.
  • Navigation: Finding the straight-line distance between two points on a grid-based map uses the same diagonal calculation.

What If?

1
Square Paper
Liz now cuts a square piece of paper along its diagonal. If the diagonal cut measures 50√2 inches, what is the side length of the square?
Step 1 — Set up for a square

For a square with side length s, both legs are equal: d² = s² + s² = 2s²

Step 2 — Substitute known diagonal

(50√2)² = 2s²

Step 3 — Simplify the left side

(50√2)² = 50² × (√2)² = 2500 × 2 = 5000

Step 4 — Solve for s

5000 = 2s²
s² = 2500
s = 50 inches

Verification

Check: √(50² + 50²) = √5000 = 50√2 ✓

2
Double the Dimensions
If the original paper's length and width were both doubled (to 120 inches and 126 inches), how long would the diagonal cut be? Is it simply double the original diagonal?
Step 1 — Apply Pythagorean theorem to new dimensions

d² = 120² + 126²

Step 2 — Calculate the squares

120² = 14,400
126² = 15,876

Step 3 — Add and take square root

d² = 14,400 + 15,876 = 30,276
d = √30,276 = 174 inches

Step 4 — Compare to doubled original

Original diagonal was 87 inches. Doubled would be 2 × 87 = 174 inches

Answer

Yes! When you double both dimensions, the diagonal exactly doubles too. This happens because of the scaling properties of the Pythagorean theorem.

3
Find the Missing Dimension
Liz makes a diagonal cut of 65 inches on a rectangular piece of paper. If the paper is 52 inches long, how wide is it?
Step 1 — Set up the equation

65² = 52² + w² where w is the unknown width

Step 2 — Calculate known squares

4225 = 2704 + w²

Step 3 — Solve for w²

w² = 4225 - 2704 = 1521

Step 4 — Find the width

w = √1521 = 39 inches

Verification

Check: √(52² + 39²) = √(2704 + 1521) = √4225 = 65 ✓

4
Two Cuts, Different Triangles
Liz cuts from one corner to the opposite corner (87 inches). Then, from the same starting corner, she cuts to the midpoint of the opposite long side (the 63-inch side). What is the length of this second cut?
Step 1 — Visualize the second cut

The second cut goes from a corner to the midpoint of the opposite 63-inch side. This creates a right triangle with legs of 60 inches (full length) and 31.5 inches (half the width).

Step 2 — Set up Pythagorean theorem

d² = 60² + 31.5²

Step 3 — Calculate the squares

60² = 3600
31.5² = 992.25

Step 4 — Add and find square root

d² = 3600 + 992.25 = 4592.25
d = √4592.25 = 67.8 inches

Answer

67.8 inches — shorter than the full diagonal because it doesn't go all the way to the far corner.

Frequently Asked Questions

How do you find the diagonal of a rectangle using the Pythagorean theorem?+
Treat the rectangle's length and width as the two legs of a right triangle, and the diagonal as the hypotenuse. Use the formula d = √(length² + width²). In this problem, d = √(60² + 63²) = √(3600 + 3969) = √7569 = 87 inches.
Why does cutting a rectangle diagonally create right triangles?+
Because rectangles have four 90-degree corners, any diagonal cut creates two identical right triangles. Each triangle has legs equal to the rectangle's length and width, with the diagonal as the hypotenuse.
What's the difference between finding area and finding diagonal length?+
Area involves multiplication (length × width), while diagonal length uses the Pythagorean theorem (√(length² + width²)). Area measures space inside the rectangle; diagonal measures the straight-line distance corner-to-corner.
NJ
Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

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This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-06-07