Geometric Sequences: Savings Account Growth Formula
What This Problem Teaches
- Geometric sequence recognition — Identifying when a sequence follows multiplicative rather than additive growth
- Explicit formula construction — Converting from recursive patterns to closed-form expressions
- Financial literacy foundations — Understanding compound growth and how small monthly rates accumulate over time
- Mathematical modeling — Translating real-world scenarios into algebraic expressions
- Exponential notation mastery — Working with bases and exponents in practical contexts
Solution: Method 1 — The Geometric Sequence Approach
This problem is asking us to find an explicit formula for a geometric sequence. Let's work through this step-by-step by identifying the pattern and applying the standard formula.
Step 1 — Identify the initial term and growth factor
Bailee starts with $500 as her initial deposit. Each month, her balance is multiplied by 1.0025. This means:
- Initial amount (when n = 0):
a₀ = 500 - Growth factor:
r = 1.0025
Step 2 — Trace the first few terms to confirm the pattern
Let's see what happens month by month:
- After 0 months:
a₀ = 500 - After 1 month:
a₁ = 500 × 1.0025 = 501.25 - After 2 months:
a₂ = 501.25 × 1.0025 = 502.50 - After 3 months:
a₃ = 502.50 × 1.0025 = 503.76
This confirms we have a geometric sequence where each term equals the previous term multiplied by 1.0025.
Step 3 — Apply the geometric sequence explicit formula
For any geometric sequence, the explicit formula is:
aₙ = a₀ × rⁿwhere a₀ is the initial term and r is the common ratio.
Step 4 — Substitute our specific values
Substituting a₀ = 500 and r = 1.0025:
aₙ = 500 × (1.0025)ⁿThis is our explicit formula describing Bailee's account balance after n months.
Solution: Method 2 — Percentage Growth Model
We can also approach this by recognizing that a multiplication factor of 1.0025 represents percentage growth. This perspective helps connect the mathematics to financial concepts.
Step 1 — Convert the factor to a growth rate
A factor of 1.0025 means:
1represents keeping 100% of the original balance0.0025represents gaining an additional 0.25% each month
So Bailee's account grows by 0.25% monthly.
Step 2 — Apply compound growth formula
For compound growth, we use the formula:
Final Amount = Initial Amount × (1 + growth rate)ⁿStep 3 — Substitute the values
With initial amount = $500, growth rate = 0.0025, and time period = n months:
aₙ = 500 × (1 + 0.0025)ⁿ = 500 × (1.0025)ⁿThis matches our result from Method 1, confirming our formula is correct.
aₙ = 500 × (1.0025)ⁿVerification
Let's verify our formula by checking it against our manually calculated values from earlier.
For n = 1:
a₁ = 500 × (1.0025)¹ = 500 × 1.0025 = 501.25 ✓
For n = 2:
a₂ = 500 × (1.0025)² = 500 × 1.00500625 = 502.503125 ≈ 502.50 ✓
For n = 0:
a₀ = 500 × (1.0025)⁰ = 500 × 1 = 500 ✓
Our formula correctly produces the expected values, confirming that aₙ = 500 × (1.0025)ⁿ is the correct explicit formula.
Common Pitfalls
✗ Mistake 1: Using addition instead of multiplication
Writing aₙ = 500 + 0.0025n treats this as an arithmetic sequence. This would mean Bailee gains a fixed $0.0025 each month, which contradicts the problem statement that her balance "increases by a factor of 1.0025."
✗ Mistake 2: Confusing the growth rate with the factor
Writing aₙ = 500 × (0.0025)ⁿ uses the growth rate (0.0025) instead of the full factor (1.0025). This would mean her balance shrinks dramatically each month, which makes no sense for a savings account.
✗ Mistake 3: Wrong initial term indexing
Writing aₙ = 500 × (1.0025)ⁿ⁻¹ assumes the first term is a₁ instead of a₀. This formula would give a₀ = 500 × (1.0025)⁻¹ ≈ 498.75, suggesting Bailee started with less than her $500 deposit.
The Underlying Pattern
This problem illustrates the general structure of geometric sequences in financial contexts. The explicit formula for any geometric sequence is:
aₙ = a₀ × rⁿWhere:
a₀= initial value (principal amount)r= common ratio (growth factor per period)n= number of periods elapsed
In financial applications, r > 1 represents growth (like savings account interest), while 0 < r < 1 represents decay (like depreciation). The key insight is that when a quantity changes by a constant percentage each period, we get exponential growth or decay, not linear change.
Important Note: This formula assumes the growth factor is applied at discrete intervals (monthly, in this case). For continuous compounding, we would use A = Pe^(rt) instead.
How to Spot This Problem Type
Geometric sequence problems often contain these key phrases:
- "increases by a factor of" or "multiplied by" — signals multiplication, not addition
- "growth rate of" or "percentage increase" — when combined with compounding
- "each month/year/period" — indicates regular, repeating process
- "explicit formula" — asks for closed-form expression, not recursive formula
Watch out for problems that mention "compound interest," "population growth," "radioactive decay," or "appreciation/depreciation." These contexts almost always involve geometric sequences.
The key test: if each term equals the previous term times a constant, you have a geometric sequence. If each term equals the previous term plus a constant, you have an arithmetic sequence.
Real Applications
- Investment accounts: Mutual funds and retirement accounts often grow by a relatively consistent monthly factor, making this formula essential for financial planning.
- Population modeling: When birth rates are stable, populations grow geometrically. Epidemiologists use similar models to track disease spread.
- Technology scaling: Moore's Law (computer processing power doubling every two years) follows geometric growth, as do many technology adoption rates.
Four "What-If?" Problems
Initial amount: a₀ = 750, Growth factor: r = 1.0025
aₙ = 750 × (1.0025)ⁿ
a₁₈ = 750 × (1.0025)¹⁸ = 750 × 1.04603 ≈ 784.52
Check: 750 × 1.0460 ≈ $784.52 ✓
500 × (1.0025)ⁿ > 520
(1.0025)ⁿ > 520/500 = 1.04
n × ln(1.0025) > ln(1.04)
n > ln(1.04)/ln(1.0025) ≈ 0.0392/0.00250 ≈ 15.7
Since we need the balance to exceed $520, it takes 16 months.
a₁₆ = 500 × (1.0025)¹⁶ ≈ 520.51 > 520 ✓
aₙ = 500 × (1.003)ⁿ
Sarah: 500 × (1.003)²⁴ = 500 × 1.0744 ≈ 537.20
Bailee: 500 × (1.0025)²⁴ = 500 × 1.0618 ≈ 530.90
Sarah has $537.20 - $530.90 = $6.30 more than Bailee after 24 months.
The higher growth factor (1.003 vs 1.0025) compounds over time, creating a meaningful difference.
a₆ = 500 × (1.0025)⁶ = 500 × 1.01508 ≈ 507.54
Starting balance for second phase: $507.54
Growth for 6 more months at 1.004 factor: 507.54 × (1.004)⁶
a₁₂ = 507.54 × (1.004)⁶ = 507.54 × 1.02429 ≈ 519.87
For 0 ≤ n ≤ 6: aₙ = 500 × (1.0025)ⁿ
For n > 6: aₙ = 500 × (1.0025)⁶ × (1.004)ⁿ⁻⁶
Check: 500 × 1.01508 × 1.02429 ≈ 519.87 ✓
Frequently Asked Questions
2026-07-11