Table Seating: Solving a System of Equations

Systems of Equations 9th-10th Grade
Problem
A school has two types of tables: round tables with 6 seats and rectangular tables with 8 seats. For a fundraising event, they filled the gym with 25 tables, for a total of 190 seats. a.write a system of equations to determine how many round tables, x, and how many rectangular tables, y, were used for the fundraising event. b. solve your system of equations using any strategy.

What This Looks Like

A school has two types of tables: round tables with 6 seats and rectangular tables with 8 seats. For a fundraising...

What You Will Learn

  • How to translate a word problem into a system of linear equations
  • Identifying count constraints versus value constraints in real-world scenarios
  • Using the elimination method to solve systems efficiently
  • Verifying solutions by substituting back into original equations
  • Recognizing when a problem has exactly one solution and why

Solution: Method 1 — The Elimination Approach

Step 1 — Define variables and identify constraints

Let x = number of round tables and y = number of rectangular tables. We have two pieces of information to work with: the total number of tables (25) and the total number of seats (190).

Step 2 — Write the system of equations

The first constraint is about counting tables: x + y = 25

The second constraint is about counting seats: round tables contribute 6 seats each, rectangular tables contribute 8 seats each, for a total of 190 seats: 6x + 8y = 190

System of equations:
x + y = 25
6x + 8y = 190

Step 3 — Use elimination to remove one variable

To eliminate x, multiply the first equation by -6:

-6(x + y) = -6(25)
-6x - 6y = -150

Step 4 — Add the equations to eliminate x

Now add this modified equation to the second original equation:

-6x - 6y = -150
6x + 8y = 190
________________
0x + 2y = 40
2y = 40
y = 20

Step 5 — Find the remaining variable

Substitute y = 20 back into the first equation:

x + 20 = 25
x = 5
The school used 5 round tables and 20 rectangular tables.

Solution: Method 2 — Substitution Strategy

Step 1 — Solve the simpler equation for one variable

From the first equation x + y = 25, we can express x in terms of y:

x = 25 - y

Step 2 — Substitute into the second equation

Replace x in the second equation:

6(25 - y) + 8y = 190
150 - 6y + 8y = 190
150 + 2y = 190
2y = 40
y = 20

Step 3 — Find the first variable

Use y = 20 to find x:

x = 25 - 20 = 5
The school used 5 round tables and 20 rectangular tables.

Verification

Let's check our solution by substituting x = 5 and y = 20 back into both original equations:

First equation: x + y = 5 + 20 = 25 ✓
Second equation: 6x + 8y = 6(5) + 8(20) = 30 + 160 = 190 ✓

Both equations are satisfied, confirming our solution is correct.

Does This Seem Reasonable?

Let's think about whether 5 round tables and 20 rectangular tables makes sense. The rectangular tables have more seats (8 vs 6), so if we want to maximize seating with a fixed number of tables, we'd expect more rectangular tables than round ones. Indeed, we found 20 rectangular tables versus only 5 round tables.

As a boundary check: if all 25 tables were round, we'd have 25 × 6 = 150 seats (too few). If all were rectangular, we'd have 25 × 8 = 200 seats (too many). Our answer of 190 seats falls between these extremes, which makes sense.

Common Pitfalls

✗ Mixing up the constraints: Writing 6x + 8y = 25 and x + y = 190
This reverses which equation represents counting tables versus counting seats. Always match the equation structure to what you're counting: simple addition for counting objects, weighted addition for counting values or capacities.
✗ Wrong elimination setup: Multiplying the wrong equation or by the wrong number
To eliminate x, you need the coefficients of x to be opposites. Since the coefficients are 1 and 6, multiply the first equation by -6, not the second equation by -1.
✗ Forgetting to verify: Stopping after finding the variables without checking
Always substitute your answer back into both original equations. If either equation isn't satisfied, you made an error somewhere.

The Pattern Behind This

This is a classic "mixture" or "constraint satisfaction" problem. The general pattern is:

Count equation: x + y = total number of objects
Value equation: (value₁)x + (value₂)y = total value

This pattern appears in many contexts: coin problems (pennies and dimes), ticket sales (adult and child tickets), and resource allocation (workers with different productivity rates). The mathematical structure is always the same: two unknowns, two linear constraints, yielding exactly one solution at their intersection point.

Real Applications

Event Planning: Restaurants and venues use this calculation to optimize table arrangements for different party sizes and revenue targets.

Manufacturing: Production managers solve similar systems when allocating resources between different product lines with varying capacity requirements.

Transportation: Airlines and buses mix vehicle types (small and large capacity) to meet passenger demand while minimizing fleet size.

What If?

1
Different Total Seats
The school still has 25 tables total, but this time they arrange them to provide exactly 180 seats. How many round tables and how many rectangular tables do they use?
Step 1 — Set up the system

The system becomes: x + y = 25 and 6x + 8y = 180

Step 2 — Eliminate x

Multiply first equation by -6: -6x - 6y = -150

Step 3 — Add equations

-6x - 6y + 6x + 8y = -150 + 180, so 2y = 30 and y = 15

Step 4 — Find x

x + 15 = 25, so x = 10

Step 5 — Verify

Check: 10 + 15 = 25 ✓ and 6(10) + 8(15) = 60 + 120 = 180 ✓

Answer: 10 round tables and 15 rectangular tables

2
Reverse the Unknown
You know there were 8 round tables and the total number of seats was 176. If the total number of tables was 24, how many rectangular tables were used?
Step 1 — Use the table count

With 8 round tables and 24 total tables: 8 + y = 24, so y = 16

Step 2 — Verify with seat count

Check: 6(8) + 8(16) = 48 + 128 = 176 ✓

Answer: 16 rectangular tables

3
Three Table Types
Now introduce square tables with 4 seats each. The gym has 30 total tables with 200 total seats. There are twice as many round tables as square tables. How many of each type are used?
Step 1 — Define variables

Let r = round tables, q = square tables, t = rectangular tables. Given: r = 2q

Step 2 — Write equations

Tables: r + q + t = 30
Seats: 6r + 4q + 8t = 200

Step 3 — Substitute r = 2q

2q + q + t = 303q + t = 30t = 30 - 3q

Step 4 — Substitute into seat equation

6(2q) + 4q + 8(30 - 3q) = 200
12q + 4q + 240 - 24q = 200
-8q = -40q = 5

Step 5 — Find other variables

r = 2(5) = 10 and t = 30 - 3(5) = 15

Step 6 — Verify

Tables: 10 + 5 + 15 = 30 ✓
Seats: 6(10) + 4(5) + 8(15) = 60 + 20 + 120 = 200 ✓

Answer: 10 round, 5 square, 15 rectangular tables

4
Optimization Challenge
For fire safety, you must have at least 8 round tables and at least 12 rectangular tables, but still only 25 tables total. What are the minimum and maximum possible total seats?
Step 1 — Identify constraints

Constraints: x ≥ 8, y ≥ 12, and x + y = 25

Step 2 — Find feasible range

From x + y = 25 and y ≥ 12: x ≤ 13
From x ≥ 8: the range is 8 ≤ x ≤ 13

Step 3 — Calculate seat function

Total seats = 6x + 8y = 6x + 8(25 - x) = 6x + 200 - 8x = 200 - 2x

Step 4 — Find extremes

Since seats = 200 - 2x, seats decrease as x increases.
Maximum seats: x = 8200 - 2(8) = 184 seats
Minimum seats: x = 13200 - 2(13) = 174 seats

Step 5 — Verify boundary cases

Max: 8 round + 17 rectangular = 25 tables, 48 + 136 = 184 seats ✓
Min: 13 round + 12 rectangular = 25 tables, 78 + 96 = 174 seats ✓

Answer: Minimum 174 seats, Maximum 184 seats

Frequently Asked Questions

How do you set up a system of equations for a constraint problem?+
Identify the two quantities being counted separately, then write one equation for the total count and another for the total value or constraint. In this problem, we count tables (x + y = 25) and seats (6x + 8y = 190), where x is round tables and y is rectangular tables.
What's the difference between elimination and substitution methods?+
Elimination removes one variable by adding or subtracting equations, while substitution solves for one variable and plugs it into the other equation. For this table problem, elimination works well: multiply the first equation by -6 to get -6x - 6y = -150, then add to 6x + 8y = 190 to eliminate x and find y = 20.
Why do systems of equations have exactly one solution in constraint problems?+
Two independent linear constraints in two unknowns typically intersect at exactly one point. Here, the line representing 25 total tables intersects the line representing 190 total seats at exactly one point: (5, 20), meaning 5 round tables and 20 rectangular tables.
NJ
Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

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This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-08-25