Solve Work-Rate Problems: Individual vs. Combined Time
Skills This Problem Builds
- Converting between work rates and work times using reciprocals
- Setting up equations where rates add when workers collaborate
- Solving rational equations with variables in denominators
- Interpreting relationships like "twice as long" in mathematical terms
- Verifying answers through substitution and logical reasoning
Solution: Method 1 — The Rate Addition Approach
The key insight is that work rates add when multiple workers collaborate. If we know how much of a job each worker completes per unit time, their combined rate is simply the sum of individual rates.
Step 1 — Define the variable
Let t = the time (in minutes) for the newer computer to send the email alone.
Since the older computer takes twice as long, it needs 2t minutes to send the email alone.
Step 2 — Express individual work rates
Work rate = jobs completed per unit time = 1 ÷ (time for one complete job)
- Newer computer's rate:
1/tjobs per minute - Older computer's rate:
1/(2t)jobs per minute
Step 3 — Set up the combined work equation
When working together, their rates add: 1/t + 1/(2t) jobs per minute.
In 10 minutes, they complete exactly 1 email, so:
10 × (1/t + 1/(2t)) = 1
Step 4 — Solve for t
First, simplify the rate sum by finding a common denominator:
Substitute back into our equation:
30/(2t) = 1
30 = 2t
t = 15
Step 5 — Find the older computer's time
The older computer takes 2t = 2(15) = 30 minutes to send the email alone.
Solution: Method 2 — The Fraction-of-Job Approach
Instead of thinking about rates, we can think about what fraction of the total job each computer completes during the 10-minute collaboration.
Step 1 — Set up fraction variables
Let x = the fraction of the email the newer computer sends in one minute.
Since the older computer is half as fast, it sends x/2 of the email in one minute.
Step 2 — Write the 10-minute equation
In 10 minutes working together, they complete the entire email (100% = 1):
10x + 5x = 1
15x = 1
x = 1/15
Step 3 — Convert to individual times
If the newer computer sends 1/15 of the email per minute, it needs 15 minutes for the complete job.
If the older computer sends 1/30 of the email per minute, it needs 30 minutes for the complete job.
Verification
Let's check that our answer is correct by substituting back into the original conditions:
Older computer time: 30 minutes
Combined rate: 1/15 + 1/30 = 2/30 + 1/30 = 3/30 = 1/10 jobs per minute
Time together: 1 job ÷ (1/10 jobs per minute) = 10 minutes ✓
Also verify the "twice as long" relationship: 30 ÷ 15 = 2 ✓
Both conditions are satisfied, confirming our answer is correct.
Where Students Go Wrong
✗ Mistake 1: Adding times instead of rates
Incorrect reasoning: "If they take 10 minutes together, and one is twice as slow, then 10 = t + 2t = 3t, so t = 10/3."
Why it's wrong: Times don't add when workers collaborate — rates do. When two people work together, they don't split the time; they combine their work speeds.
✗ Mistake 2: Misinterpreting "twice as long"
Incorrect setup: Setting the older computer's rate as 2/t instead of 1/(2t).
Why it's wrong: "Twice as long" means twice the time, not twice the rate. If something takes twice as long, it's actually half as fast. Time and rate are reciprocals.
✗ Mistake 3: Solving incorrectly for the wrong variable
Finding that t = 15 and then answering "15 minutes" instead of "30 minutes."
Why it's wrong: The variable t represents the newer computer's time. The question asks for the older computer's time, which is 2t = 30 minutes. Always check what the question is actually asking for.
The General Formula
For any two-worker problem where one worker takes time a and the other takes time b, their combined time T follows the harmonic mean formula:
Which rearranges to:
T = (a × b)/(a + b)
In our problem: a = 15, b = 30, so T = (15 × 30)/(15 + 30) = 450/45 = 10 ✓
This formula works for any number of workers: the reciprocal of the combined time equals the sum of the reciprocals of individual times. This same mathematics appears in electrical circuits (parallel resistors) and fluid flow (parallel pipes).
Why This Matters
Project management: Estimating completion times when assigning tasks to team members with different productivity levels.
Manufacturing: Calculating throughput when multiple machines with different speeds work on the same production line.
Network engineering: Determining data transfer rates when multiple connections with different bandwidths work in parallel.
Healthcare: Modeling how multiple medications with different clearance rates are processed by the body simultaneously.
What If?
Let t = time for newer computer alone. Then older computer takes 3t minutes alone.
Combined rate: 1/t + 1/(3t) = 3/(3t) + 1/(3t) = 4/(3t) jobs per minute
In 12 minutes: 12 × 4/(3t) = 1
48/(3t) = 1
48 = 3t
t = 16 minutes
Older computer: 3t = 3(16) = 48 minutes
Check: 1/16 + 1/48 = 3/48 + 1/48 = 4/48 = 1/12
Time together: 1 ÷ (1/12) = 12 minutes ✓
Newer: 15 minutes
Older: 2 × 15 = 30 minutes
Very old: 3 × 15 = 45 minutes
Newer: 1/15 jobs per minute
Older: 1/30 jobs per minute
Very old: 1/45 jobs per minute
Combined rate = 1/15 + 1/30 + 1/45
Common denominator 90: 6/90 + 3/90 + 2/90 = 11/90
Time = 1 ÷ (11/90) = 90/11 minutes
Answer: 90/11 minutes ≈ 8.18 minutes
Let t = time for older computer alone
If newer is 3 times faster, it takes t/3 minutes alone
Older computer rate: 1/t jobs per minute
Newer computer rate: 1/(t/3) = 3/t jobs per minute
Combined rate: 1/t + 3/t = 4/t
In 8 minutes: 8 × (4/t) = 1
32/t = 1
t = 32 minutes
The older computer takes 32 minutes alone
Newer takes 32/3 minutes alone
Combined rate: 1/32 + 3/32 = 4/32 = 1/8
Time together: 1 ÷ (1/8) = 8 minutes ✓
Let t = time for newer computer alone
Older computer takes 2t minutes alone
First 6 minutes: Both work together at rate 1/t + 1/(2t) = 3/(2t)
Work completed: 6 × 3/(2t) = 18/(2t) = 9/t
Remaining work: 1 - 9/t
Older computer works alone for 9 minutes at rate 1/(2t)
Work completed: 9 × 1/(2t) = 9/(2t)
Remaining work = Work done by older computer alone:
1 - 9/t = 9/(2t)
Multiply by 2t: 2t - 18 = 9
2t = 27
t = 13.5 minutes
The newer computer takes 13.5 minutes alone
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2026-07-09