Solve Work-Rate Problems: Individual vs. Combined Time

Work Rate 9th-10th Grade
PROBLEM
It takes an older computer twice as long to send out a company's email as it does a newer computer. Working together, it takes the two computers 10 minutes to send out the email. How long will it take the older computer to send out the email on its own? Do not round.

Skills This Problem Builds

  • Converting between work rates and work times using reciprocals
  • Setting up equations where rates add when workers collaborate
  • Solving rational equations with variables in denominators
  • Interpreting relationships like "twice as long" in mathematical terms
  • Verifying answers through substitution and logical reasoning

Solution: Method 1 — The Rate Addition Approach

The key insight is that work rates add when multiple workers collaborate. If we know how much of a job each worker completes per unit time, their combined rate is simply the sum of individual rates.

Step 1 — Define the variable

Let t = the time (in minutes) for the newer computer to send the email alone.

Since the older computer takes twice as long, it needs 2t minutes to send the email alone.

Step 2 — Express individual work rates

Work rate = jobs completed per unit time = 1 ÷ (time for one complete job)

  • Newer computer's rate: 1/t jobs per minute
  • Older computer's rate: 1/(2t) jobs per minute

Step 3 — Set up the combined work equation

When working together, their rates add: 1/t + 1/(2t) jobs per minute.

In 10 minutes, they complete exactly 1 email, so:

Time × Combined Rate = 1 Complete Job
10 × (1/t + 1/(2t)) = 1

Step 4 — Solve for t

First, simplify the rate sum by finding a common denominator:

1/t + 1/(2t) = 2/(2t) + 1/(2t) = 3/(2t)

Substitute back into our equation:

10 × (3/(2t)) = 1
30/(2t) = 1
30 = 2t
t = 15

Step 5 — Find the older computer's time

The older computer takes 2t = 2(15) = 30 minutes to send the email alone.

Solution: Method 2 — The Fraction-of-Job Approach

Instead of thinking about rates, we can think about what fraction of the total job each computer completes during the 10-minute collaboration.

Step 1 — Set up fraction variables

Let x = the fraction of the email the newer computer sends in one minute.

Since the older computer is half as fast, it sends x/2 of the email in one minute.

Step 2 — Write the 10-minute equation

In 10 minutes working together, they complete the entire email (100% = 1):

10x + 10(x/2) = 1
10x + 5x = 1
15x = 1
x = 1/15

Step 3 — Convert to individual times

If the newer computer sends 1/15 of the email per minute, it needs 15 minutes for the complete job.

If the older computer sends 1/30 of the email per minute, it needs 30 minutes for the complete job.

The older computer takes 30 minutes to send out the email on its own.

Verification

Let's check that our answer is correct by substituting back into the original conditions:

Newer computer time: 15 minutes
Older computer time: 30 minutes
Combined rate: 1/15 + 1/30 = 2/30 + 1/30 = 3/30 = 1/10 jobs per minute
Time together: 1 job ÷ (1/10 jobs per minute) = 10 minutes ✓

Also verify the "twice as long" relationship: 30 ÷ 15 = 2

Both conditions are satisfied, confirming our answer is correct.

Where Students Go Wrong

✗ Mistake 1: Adding times instead of rates

Incorrect reasoning: "If they take 10 minutes together, and one is twice as slow, then 10 = t + 2t = 3t, so t = 10/3."

Why it's wrong: Times don't add when workers collaborate — rates do. When two people work together, they don't split the time; they combine their work speeds.

✗ Mistake 2: Misinterpreting "twice as long"

Incorrect setup: Setting the older computer's rate as 2/t instead of 1/(2t).

Why it's wrong: "Twice as long" means twice the time, not twice the rate. If something takes twice as long, it's actually half as fast. Time and rate are reciprocals.

✗ Mistake 3: Solving incorrectly for the wrong variable

Finding that t = 15 and then answering "15 minutes" instead of "30 minutes."

Why it's wrong: The variable t represents the newer computer's time. The question asks for the older computer's time, which is 2t = 30 minutes. Always check what the question is actually asking for.

The General Formula

For any two-worker problem where one worker takes time a and the other takes time b, their combined time T follows the harmonic mean formula:

1/T = 1/a + 1/b

Which rearranges to:
T = (a × b)/(a + b)

In our problem: a = 15, b = 30, so T = (15 × 30)/(15 + 30) = 450/45 = 10

This formula works for any number of workers: the reciprocal of the combined time equals the sum of the reciprocals of individual times. This same mathematics appears in electrical circuits (parallel resistors) and fluid flow (parallel pipes).

Why This Matters

Project management: Estimating completion times when assigning tasks to team members with different productivity levels.

Manufacturing: Calculating throughput when multiple machines with different speeds work on the same production line.

Network engineering: Determining data transfer rates when multiple connections with different bandwidths work in parallel.

Healthcare: Modeling how multiple medications with different clearance rates are processed by the body simultaneously.

What If?

1
Different Speed Ratio
An older computer takes 3 times as long to send out a company's email as a newer computer. Working together, they complete the task in 12 minutes. How long would the older computer take alone?
Step 1 — Set up variables

Let t = time for newer computer alone. Then older computer takes 3t minutes alone.

Step 2 — Write the combined work equation

Combined rate: 1/t + 1/(3t) = 3/(3t) + 1/(3t) = 4/(3t) jobs per minute

In 12 minutes: 12 × 4/(3t) = 1

Step 3 — Solve for t

48/(3t) = 1

48 = 3t

t = 16 minutes

Step 4 — Find older computer's time

Older computer: 3t = 3(16) = 48 minutes

Verification

Check: 1/16 + 1/48 = 3/48 + 1/48 = 4/48 = 1/12

Time together: 1 ÷ (1/12) = 12 minutes ✓

2
Three Computers
A newer computer takes 15 minutes to send an email alone. An older computer takes twice as long. A very old computer takes three times as long as the newer one. How long do all three take working together?
Step 1 — List individual times

Newer: 15 minutes

Older: 2 × 15 = 30 minutes

Very old: 3 × 15 = 45 minutes

Step 2 — Calculate individual rates

Newer: 1/15 jobs per minute

Older: 1/30 jobs per minute

Very old: 1/45 jobs per minute

Step 3 — Find combined rate

Combined rate = 1/15 + 1/30 + 1/45

Common denominator 90: 6/90 + 3/90 + 2/90 = 11/90

Step 4 — Calculate time together

Time = 1 ÷ (11/90) = 90/11 minutes

Answer: 90/11 minutes ≈ 8.18 minutes

3
Reversed Unknown
Two computers working together take 8 minutes to send an email. The newer computer is 3 times faster than the older one. How long does the older computer take working alone?
Step 1 — Set up variables

Let t = time for older computer alone

If newer is 3 times faster, it takes t/3 minutes alone

Step 2 — Express rates

Older computer rate: 1/t jobs per minute

Newer computer rate: 1/(t/3) = 3/t jobs per minute

Step 3 — Set up equation

Combined rate: 1/t + 3/t = 4/t

In 8 minutes: 8 × (4/t) = 1

Step 4 — Solve

32/t = 1

t = 32 minutes

The older computer takes 32 minutes alone

Verification

Newer takes 32/3 minutes alone

Combined rate: 1/32 + 3/32 = 4/32 = 1/8

Time together: 1 ÷ (1/8) = 8 minutes ✓

4
Partial Completion
Two computers start sending an email together. After 6 minutes, the newer computer crashes. The older computer (which takes twice as long alone) finishes the remaining work in 9 more minutes. How long would the newer computer take working alone?
Step 1 — Set up variables

Let t = time for newer computer alone

Older computer takes 2t minutes alone

Step 2 — Analyze the work phases

First 6 minutes: Both work together at rate 1/t + 1/(2t) = 3/(2t)

Work completed: 6 × 3/(2t) = 18/(2t) = 9/t

Remaining work: 1 - 9/t

Step 3 — Analyze the older computer's solo work

Older computer works alone for 9 minutes at rate 1/(2t)

Work completed: 9 × 1/(2t) = 9/(2t)

Step 4 — Set up equation

Remaining work = Work done by older computer alone:

1 - 9/t = 9/(2t)

Step 5 — Solve

Multiply by 2t: 2t - 18 = 9

2t = 27

t = 13.5 minutes

The newer computer takes 13.5 minutes alone

Frequently Asked Questions

How do you solve work rate problems with two workers of different speeds? +
Set up equations using the principle that combined work rates equal the sum of individual work rates. If one worker takes time t and another takes 2t, their rates are 1/t and 1/2t jobs per unit time. When working together for 10 minutes to complete 1 job, you get: 10(1/t + 1/2t) = 1, which solves to give t = 15 minutes for the faster worker and 30 minutes for the slower worker.
What's the difference between work rate and work time in these problems? +
Work rate is jobs per unit time (like 1/15 jobs per minute), while work time is the total time to complete one job (like 15 minutes). They're reciprocals of each other. In this problem, if the newer computer takes 15 minutes alone, its rate is 1/15 jobs per minute. The older computer takes 30 minutes alone, so its rate is 1/30 jobs per minute.
Why do you add work rates when workers collaborate? +
Work rates add because each worker contributes their portion simultaneously. If one computer processes 1/15 of an email per minute and another processes 1/30 per minute, together they process 1/15 + 1/30 = 3/30 = 1/10 of the email per minute. This means they complete the entire email in 10 minutes when working together.
NJ
Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

Contact

This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-07-09