Work Rate Problem: Staggered Printer Operation

Work Rate 9th-10th Grade
Problem
The larger of the two printers being used to print payroll for a company requires 40 minutes to print payroll. After both printers have been operating for 10 minutes the larger printer malfunctions. The smaller printer requires 50 more minutes to complete the payroll. How long would it take the smaller printer, working alone, to print payroll?

What This Problem Teaches

  • Setting up work rate equations when machines operate in different phases
  • Converting time-to-complete into fraction-per-minute rates
  • Breaking complex scenarios into manageable calculation steps
  • Solving fractional equations where the unknown appears in denominators
  • Verifying solutions by checking that work phases sum to exactly one complete job

Visualizing the Work Timeline

The larger of the two printers being used to print payroll for a company requires 40 minutes to print payroll. After...

Solution: Method 1 — The Work Rate Equation

Step 1 — Define the work rates

Let x = time (in minutes) for the smaller printer to complete the job alone.

Large printer rate = 1/40 jobs per minute
Small printer rate = 1/x jobs per minute
Combined rate = 1/40 + 1/x jobs per minute

Step 2 — Calculate work done in Phase 1 (both printers working)

Both printers work together for 10 minutes:

Work completed = (rate) × (time)
Work in Phase 1 = (1/40 + 1/x) × 10 = 10/40 + 10/x = 1/4 + 10/x

Step 3 — Calculate work done in Phase 2 (small printer only)

After the large printer breaks, the small printer works alone for 50 minutes:

Work in Phase 2 = (1/x) × 50 = 50/x

Step 4 — Set up the equation for total work

The sum of work from both phases must equal exactly 1 complete job:

Phase 1 + Phase 2 = 1 complete job
(1/4 + 10/x) + 50/x = 1
1/4 + 10/x + 50/x = 1
1/4 + 60/x = 1

Step 5 — Solve for x

Isolate the term containing x:

60/x = 1 - 1/4 = 3/4
60/x = 3/4
x = 60 × 4/3 = 240/3 = 80
The smaller printer would take 80 minutes to print the payroll working alone.

Solution: Method 2 — Work Units Approach

Step 1 — Define one complete job as 40 work units

Since the large printer completes the job in 40 minutes, let's say the complete job equals 40 work units. This means:

Large printer rate = 40 units ÷ 40 minutes = 1 unit per minute
Small printer rate = 40 units ÷ x minutes = 40/x units per minute

Step 2 — Calculate units completed in each phase

Phase 1 (both working for 10 minutes):

Units completed = (1 + 40/x) × 10 = 10 + 400/x units

Phase 2 (small printer alone for 50 minutes):

Units completed = (40/x) × 50 = 2000/x units

Step 3 — Set up the equation

Total units must equal 40 (one complete job):

(10 + 400/x) + 2000/x = 40
10 + 400/x + 2000/x = 40
10 + 2400/x = 40
2400/x = 30
x = 2400/30 = 80
The smaller printer takes 80 minutes working alone.

Verification

Let's check that our answer produces exactly one complete job:

With x = 80 minutes for the small printer:

Large printer rate = 1/40 jobs per minute
Small printer rate = 1/80 jobs per minute
Combined rate = 1/40 + 1/80 = 2/80 + 1/80 = 3/80 jobs per minute

Phase 1 (both working for 10 minutes):

Work completed = 3/80 × 10 = 30/80 = 3/8 of the job

Phase 2 (small printer alone for 50 minutes):

Work completed = 1/80 × 50 = 50/80 = 5/8 of the job

Total work:

3/8 + 5/8 = 8/8 = 1 complete job ✓

The verification confirms our answer is correct.

Common Pitfalls

✗ Mistake 1: Adding the times instead of the rates

Incorrect thinking: "If large takes 40 min and they work together for 10 min, then small works for 50 min, so small takes 40 + 10 + 50 = 100 minutes alone."

Why this fails: You can't add completion times directly. Work rates (fractions per minute) are what combine when machines work together, not their individual completion times.

✗ Mistake 2: Forgetting that "50 more minutes" is additional time

Incorrect setup: Small printer rate = 1/50 jobs per minute

Why this fails: The 50 minutes is how long the small printer needs after both worked together for 10 minutes. It's not the small printer's solo time for the entire job.

✗ Mistake 3: Setting up the work equation incorrectly

Incorrect equation: 10/40 + 50/x = 1

Why this fails: This only accounts for the large printer working for 10 minutes, ignoring that the small printer was also working during those first 10 minutes. The correct Phase 1 work is (1/40 + 1/x) × 10.

The Pattern Behind This

This problem follows the general pattern for two-phase work problems:

(Combined rate × Time₁) + (Remaining rate × Time₂) = 1 job

The key insight is recognizing when a problem has multiple phases with different working conditions. Any time you see "after X minutes, something changes," you're likely dealing with a multi-phase scenario.

For this specific type where one machine breaks down:

(1/A + 1/B) × t₁ + (1/B) × t₂ = 1

Where:

  • A = time for machine 1 alone
  • B = time for machine 2 alone (unknown)
  • t₁ = time both machines work together
  • t₂ = time machine 2 works alone after machine 1 breaks

Real Applications

This exact scenario appears in several real-world contexts:

Manufacturing: When a production line has multiple machines and one breaks down mid-shift, requiring calculation of individual machine capacities for maintenance planning.

Network Systems: When servers work in parallel to handle data processing, and one server goes offline partway through a large job batch.

Construction Projects: When multiple crews work together initially, but one crew is reassigned to another project, and you need to determine individual crew productivity rates.

What If?

1
Faster Large Printer
The large printer completes payroll in 30 minutes alone. After both printers work together for 10 minutes, the large printer breaks. The small printer needs 40 more minutes to finish. How long would the small printer take working alone?
Step 1 — Set up rates

Large printer rate = 1/30 jobs per minute. Small printer rate = 1/x jobs per minute.

Step 2 — Phase 1 work

Both work for 10 minutes: (1/30 + 1/x) × 10 = 10/30 + 10/x = 1/3 + 10/x

Step 3 — Phase 2 work

Small printer alone for 40 minutes: (1/x) × 40 = 40/x

Step 4 — Total work equation

1/3 + 10/x + 40/x = 1, so 1/3 + 50/x = 1

Step 5 — Solve

50/x = 2/3, so x = 50 × 3/2 = 75

Answer

75 minutes for the small printer working alone.

2
Extended Teamwork Phase
The large printer (40 min alone) and small printer work together for 15 minutes before the large printer malfunctions. The small printer then needs 45 more minutes to finish. Find the small printer's solo time.
Step 1 — Set up the equation

Phase 1: (1/40 + 1/x) × 15 = 15/40 + 15/x = 3/8 + 15/x

Step 2 — Phase 2

Small printer alone for 45 minutes: 45/x

Step 3 — Total work

3/8 + 15/x + 45/x = 1, so 3/8 + 60/x = 1

Step 4 — Solve

60/x = 5/8, so x = 60 × 8/5 = 96

Answer

96 minutes for the small printer working alone.

3
Three-Printer System
Three printers work together: large (40 min alone), medium (60 min alone), and small (unknown). After 8 minutes, the large printer breaks. After 5 more minutes, the medium printer breaks. The small printer needs 35 more minutes to finish. Find the small printer's solo time.
Step 1 — Phase 1 (all three)

All work for 8 minutes: (1/40 + 1/60 + 1/x) × 8 = 8/40 + 8/60 + 8/x = 1/5 + 2/15 + 8/x

Step 2 — Phase 2 (medium and small)

Medium and small for 5 minutes: (1/60 + 1/x) × 5 = 5/60 + 5/x = 1/12 + 5/x

Step 3 — Phase 3 (small only)

Small alone for 35 minutes: 35/x

Step 4 — Set up equation

1/5 + 2/15 + 8/x + 1/12 + 5/x + 35/x = 1. Combine constants: 1/5 + 2/15 + 1/12 = 12/60 + 8/60 + 5/60 = 25/60 = 5/12

Step 5 — Solve

5/12 + 48/x = 1, so 48/x = 7/12, thus x = 48 × 12/7 = 576/7 ≈ 82.3

Answer

82.3 minutes (or exactly 576/7 minutes) for the small printer alone.

4
Reverse Engineering
A large printer (40 min alone) and small printer (80 min alone) work together for some time before the large printer breaks. The small printer then needs exactly 30 minutes to complete the job. For how many minutes did both printers work together initially?
Step 1 — Let t be the unknown time

Both printers work together for t minutes, then small printer works alone for 30 minutes.

Step 2 — Set up work rates

Large rate = 1/40, small rate = 1/80, combined rate = 1/40 + 1/80 = 3/80

Step 3 — Work equation

Phase 1 + Phase 2 = 1 job: (3/80)t + (1/80)(30) = 1

Step 4 — Solve for t

3t/80 + 30/80 = 1, so 3t + 30 = 80, thus 3t = 50, and t = 50/3 ≈ 16.67

Answer

Both printers worked together for 16⅔ minutes (or exactly 50/3 minutes).

Frequently Asked Questions

How do you solve a work rate problem when one machine breaks down partway through? +
Break the problem into phases: first calculate the work completed when both machines operate together, then determine what fraction remains for the functioning machine to complete alone. In this problem, both printers work together for 10 minutes completing 10(1/40 + 1/x) of the job, then the small printer finishes the remaining work in 50 minutes.
What's the difference between combined work rate and individual work rate? +
Individual work rate is the fraction of a job completed per unit time by one worker alone (like 1/40 jobs per minute). Combined work rate is the sum of individual rates when working together. Here, the large printer works at 1/40 jobs/min and small at 1/x jobs/min, so together they work at (1/40 + 1/x) jobs/min.
Why do work rate problems often result in fractional equations? +
Because work rates are naturally expressed as fractions (portion of job per time unit), and the total work must equal exactly 1 complete job. When machines work in phases, you're adding fractions that represent different portions of the complete job, leading to equations like 1/4 + 1/x + 5/4x = 1.
NJ
Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

Contact

This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-09-04