Recursive Formula for Decreasing Sequences

Sequences 9th-10th Grade
PROBLEM
A company's newsletter subscriptions decreased by 80 subscribers each month. Starting at 4,000 subscribers, write the recursive formula to predict subscriptions for coming months.

What This Problem Teaches

  • How to identify the first term and common difference in an arithmetic sequence
  • The structure of recursive formulas: starting value plus pattern rule
  • Why recursive formulas are perfect for modeling step-by-step processes
  • The difference between recursive thinking (each term depends on the previous) and explicit thinking (jump directly to any term)
  • Real-world applications of sequences in business modeling and predictions

Solution: Method 1 — The Step-by-Step Approach

When dealing with recursive formulas, we need two pieces: where we start and how we move from one term to the next. Let's work through this systematically.

Step 1 — Identify the starting value

The company begins with 4,000 subscribers. This becomes our first term: a(1) = 4000.

Step 2 — Determine the pattern of change

Each month, subscriptions decrease by 80. This means we subtract 80 from the current month to get the next month's value.

Step 3 — Write the recursive relationship

The recursive rule connects consecutive terms. Since we lose 80 subscribers each month:

a(n+1) = a(n) - 80

This reads as: "Next month's subscribers equals this month's subscribers minus 80."

Step 4 — Combine into complete recursive formula

A complete recursive formula needs both the starting point and the pattern rule:

a(1) = 4000
a(n+1) = a(n) - 80, for n ≥ 1

Solution: Method 2 — The Month-by-Month Visualization

Sometimes it helps to see the pattern by calculating the first few terms explicitly, then identifying the recursive structure from the pattern.

Step 1 — Calculate the first several terms

Let's trace through the first few months:

  • Month 1: 4,000 subscribers (starting point)
  • Month 2: 4,000 - 80 = 3,920 subscribers
  • Month 3: 3,920 - 80 = 3,840 subscribers
  • Month 4: 3,840 - 80 = 3,760 subscribers

Step 2 — Identify the recursive pattern

Looking at how each term relates to the previous one:

  • a(2) = a(1) - 80
  • a(3) = a(2) - 80
  • a(4) = a(3) - 80

Step 3 — Generalize the pattern

The pattern is consistent: each term equals the previous term minus 80. This gives us the same recursive formula:

a(1) = 4000
a(n+1) = a(n) - 80, for n ≥ 1
Answer: a(1) = 4000 and a(n+1) = a(n) - 80, for n ≥ 1

Verification

Let's verify our recursive formula produces the expected pattern by calculating the first few terms:

Given formula:a(1) = 4000 and a(n+1) = a(n) - 80

  • a(1) = 4000
  • a(2) = a(1) - 80 = 4000 - 80 = 3920
  • a(3) = a(2) - 80 = 3920 - 80 = 3840
  • a(4) = a(3) - 80 = 3840 - 80 = 3760

The pattern matches exactly: each month shows a decrease of 80 subscribers, confirming our recursive formula is correct.

Watch Out For These Common Mistakes

✗ Writing the wrong starting term:a(0) = 4000
The problem states the company starts with 4,000 subscribers, so month 1 has 4,000 subscribers. Don't use a(0) unless specifically told the sequence begins at term 0.
✗ Adding instead of subtracting:a(n+1) = a(n) + 80
The key word is "decreased." The subscriptions go down by 80 each month, so we subtract 80, not add it.
✗ Mixing up recursive and explicit formulas:a(n) = 4000 - 80n
This is an explicit formula (which is also useful), but the problem specifically asks for a recursive formula. Recursive formulas define each term using the previous term, not using the term number directly.

The Underlying Pattern

This problem demonstrates an arithmetic sequence with a negative common difference. The general form for any decreasing arithmetic sequence is:

a(1) = [first term]
a(n+1) = a(n) - d, where d > 0

In our case, the first term is 4,000 and the common difference is 80 (which we subtract, making it effectively -80). This pattern appears throughout mathematics and real-world modeling:

  • Growth sequences: Use a(n+1) = a(n) + d
  • Decay sequences: Use a(n+1) = a(n) - d
  • Multiplicative processes: Use a(n+1) = r × a(n)

Recursive formulas excel at modeling any process where the next state depends directly on the current state—which includes most real-world systems.

How to Spot This Problem Type

Look for these key phrases that signal a recursive formula problem:

  • "Each month/year/day..." — suggests a step-by-step process
  • "Starting with/at..." — gives you the first term
  • "Increased/decreased by [constant amount]" — indicates arithmetic sequence
  • "Write a recursive formula" — directly asks for the recursive form
  • "Predict/model future values" — recursive formulas are perfect for predictions

The problem structure typically follows: initial value + constant change + time progression. Any scenario involving regular, predictable changes over time—subscriptions, populations, savings accounts, depreciation—often uses recursive thinking.

Contrast with explicit formulas: If a problem asks "find the 50th term" or "what will the value be after 10 years," it might be hinting toward an explicit formula. But if it asks to "write a formula to predict" or "model the pattern," recursive formulas are often preferred because they show the underlying process.

Real Applications

Recursive formulas like this one appear constantly in business and scientific modeling:

  • Customer churn analysis: Companies track monthly subscriber losses to predict future customer base and plan retention strategies.
  • Inventory depletion: Retail businesses use recursive models when products have steady consumption rates and need reorder planning.
  • Population dynamics: Ecologists model species decline due to habitat loss or hunting pressure using similar recursive patterns.
  • Financial planning: Regular withdrawals from retirement accounts follow recursive formulas, helping predict account longevity.

The power of recursive thinking is that it matches how these processes actually work—each month's outcome depends on the previous month's state plus a predictable change.

Try These Variations

1
Growth Instead of Decline
A newsletter gains 120 new subscribers each month. If it starts with 2,500 subscribers, write the recursive formula for the number of subscribers after n months.
Step 1 — Identify the first term

The newsletter starts with 2,500 subscribers, so a(1) = 2500.

Step 2 — Determine the pattern

The newsletter gains 120 subscribers each month, so we add 120 to get the next term: a(n+1) = a(n) + 120.

Step 3 — Write the complete formula

a(1) = 2500 and a(n+1) = a(n) + 120

Step 4 — Verify

Check: a(2) = 2500 + 120 = 2620, a(3) = 2620 + 120 = 2740. The pattern shows consistent growth of 120 per month. ✓

Answer: a(1) = 2500 and a(n+1) = a(n) + 120

2
Percentage-Based Decline
A company loses 5% of its subscribers each month. Starting at 4,000 subscribers, write the recursive formula for the number of subscribers after n months.
Step 1 — Identify the first term

Starting with 4,000 subscribers: a(1) = 4000.

Step 2 — Handle percentage loss

Losing 5% means keeping 95% = 0.95 of the current subscribers. So each month: a(n+1) = 0.95 × a(n).

Step 3 — Write the complete formula

a(1) = 4000 and a(n+1) = 0.95a(n)

Step 4 — Verify

Check: a(2) = 0.95 × 4000 = 3800 (lost 200, which is 5% of 4000). a(3) = 0.95 × 3800 = 3610 (lost 190, which is 5% of 3800). ✓

Answer: a(1) = 4000 and a(n+1) = 0.95a(n)

3
Variable Loss Rate
A newsletter loses 80 subscribers in month 1, 70 in month 2, 60 in month 3, and so on (decreasing by 10 each month). Starting at 4,000 subscribers, write the recursive formula.
Step 1 — Identify the pattern in losses

Losses: 80, 70, 60, ... decreasing by 10 each month. The loss in month n is: Loss(n) = 90 - 10n.

Step 2 — Write the recursive relationship

Starting with a(1) = 4000, and a(n+1) = a(n) - (90 - 10n).

Step 3 — Simplify

a(n+1) = a(n) - 90 + 10n

Step 4 — Verify

a(2) = 4000 - 90 + 10(1) = 3920 (lost 80). a(3) = 3920 - 90 + 10(2) = 3850 (lost 70). ✓

Answer: a(1) = 4000 and a(n+1) = a(n) - 90 + 10n

4
Reverse the Unknown
A newsletter has a recursive formula: S(1) = 5000 and S(n+1) = S(n) - 60. After how many months will the newsletter have fewer than 3,000 subscribers?
Step 1 — Find the explicit formula

From the recursive formula, we can derive: S(n) = 5000 - 60(n-1).

Step 2 — Set up the inequality

We want S(n) < 3000, so: 5000 - 60(n-1) < 3000.

Step 3 — Solve for n

5000 - 60n + 60 < 3000
5060 - 60n < 3000
2060 < 60n
n > 34.33...

Step 4 — Interpret the result

Since n must be a whole number of months, n = 35 is the first month with fewer than 3,000 subscribers.

Answer: After 35 months

Frequently Asked Questions

What's the difference between recursive and explicit formulas for sequences? +
A recursive formula defines each term using the previous term (like a(n+1) = a(n) - 80), while an explicit formula gives any term directly using just its position (like a(n) = 4000 - 80(n-1)). Recursive formulas show the step-by-step pattern, while explicit formulas let you jump to any term immediately.
How do you write a recursive formula for an arithmetic sequence? +
Start with the first term, then write the pattern rule. For a decreasing sequence like newsletter subscriptions dropping by 80 each month from 4,000: a(1) = 4000 and a(n+1) = a(n) - 80. The key is identifying the constant difference and whether you're adding or subtracting it.
When would you use a recursive formula in real applications? +
Recursive formulas are perfect for modeling processes that depend on the previous state: population growth, compound interest, iterative algorithms, and business projections. In this problem, each month's subscribers depend on the previous month's count minus the steady loss of 80.
NJ
Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

Contact

This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-07-31