Find Time for Alice to Lap Bob on Circular Track

Circular Motion 11th-12th Grade
PROBLEM
Alice runs at 7 m/s and Bob at 3 m/s on a circular track with radius 100/π meters. How long until Alice laps Bob 3 times?
Alice runs at 7 m/s and Bob at 3 m/s on a circular track with radius 100/π meters. How long until Alice laps Bob 3...

What You Will Learn

  • How to calculate circumference when radius contains π
  • Finding relative speed for objects moving in the same direction
  • Understanding what "lapping" means in circular motion problems
  • Converting between different measures of circular motion
  • Setting up and solving multi-step motion problems

Solution: Method 1 — The Relative Speed Approach

This problem is all about understanding that "lapping" means gaining a full circumference worth of distance. Let's work through it systematically.

Step 1 — Calculate the track circumference

Using the formula C = 2πr with radius 100/π meters:

C = 2π × (100/π) = 2π × 100/π = 200π/π = 200 meters

The π terms cancel out perfectly, giving us a clean circumference of 200 meters.

Step 2 — Find the relative speed

Since both runners move in the same direction, Alice gains ground on Bob at the difference of their speeds:

Relative speed = 7 m/s - 3 m/s = 4 m/s

This means Alice gains 4 meters on Bob every second.

Step 3 — Calculate time for one lap

For Alice to lap Bob once, she must gain exactly one full circumference (200 m) on him:

Time for one lap = Distance gained / Relative speed = 200 m / 4 m/s = 50 seconds

Step 4 — Find time for three laps

Since lapping events happen at regular intervals:

Time for 3 laps = 3 × 50 seconds = 150 seconds
Alice will lap Bob 3 times after 150 seconds (or 2 minutes and 30 seconds).

Solution: Method 2 — The Position Tracking Method

Instead of thinking about relative speed, we can track each runner's position and find when Alice is exactly one, two, and three laps ahead.

Step 1 — Express positions as functions of time

After t seconds:

Alice's position: 7t meters around the track
Bob's position: 3t meters around the track

Step 2 — Set up the lapping condition

Alice laps Bob when she has traveled exactly one more complete track length than Bob:

Alice's distance = Bob's distance + (number of laps × 200) 7t = 3t + n × 200

where n is the number of complete laps Alice is ahead.

Step 3 — Solve for each lap

Rearranging the equation:

7t - 3t = n × 200
4t = 200n
t = 50n

Step 4 — Find the specific times

First lap (n = 1): t = 50 × 1 = 50 seconds
Second lap (n = 2): t = 50 × 2 = 100 seconds
Third lap (n = 3): t = 50 × 3 = 150 seconds
Alice completes her third lap of Bob at 150 seconds.

Verification

Let's check our answer by calculating how far each runner has traveled after 150 seconds:

Alice's distance: 7 m/s × 150 s = 1,050 meters
Bob's distance: 3 m/s × 150 s = 450 meters
Difference: 1,050 - 450 = 600 meters

Since the track is 200 meters around, a 600-meter difference means Alice is exactly 3 complete laps ahead of Bob. ✓

We can also verify the individual lapping times:

At 50s: Alice = 350m, Bob = 150m → Difference = 200m = 1 lap ✓
At 100s: Alice = 700m, Bob = 300m → Difference = 400m = 2 laps ✓
At 150s: Alice = 1050m, Bob = 450m → Difference = 600m = 3 laps ✓

Common Pitfalls

Mistake 1: Adding speeds instead of subtracting

Combined speed = 7 + 3 = 10 m/s

This would be correct if the runners were moving toward each other, but they're moving in the same direction. When finding relative speed for same-direction motion, always subtract the slower speed from the faster one.

Mistake 2: Confusing radius and diameter in the circumference formula

C = 2π × (200/π) = 400 meters

The problem states the radius is 100/π meters, not the diameter. Using C = 2πr correctly gives us C = 2π × (100/π) = 200 meters.

Mistake 3: Thinking Alice needs to run 3 full laps

Time = (3 × 200) ÷ 7 = 600/7 ≈ 85.7 seconds

This calculates how long Alice takes to run 3 complete laps herself, but ignores that Bob is also moving. The question asks when Alice laps Bob 3 times, which depends on their relative motion.

Mistake 4: Not simplifying the π terms

C = 2π × (100/π) = 200π/π meters (leaving as 200π/π)

While mathematically correct, this makes the calculation unnecessarily complex. Always simplify: 200π/π = 200 meters exactly.

The General Formula

For any circular track lapping problem where both objects move in the same direction:

Time for n laps = n × (Track circumference) / (v₁ - v₂)

where v₁ is the faster speed and v₂ is the slower speed.

This formula works because:

  • The relative speed (v₁ - v₂) tells us how quickly the faster object gains ground
  • Each lap requires gaining exactly one circumference worth of distance
  • The lapping events occur at regular intervals
Important limitation: This formula only works when both objects maintain constant speeds and move in the same direction. For opposite directions, use v₁ + v₂ as the approach speed instead.

How to Spot This Problem Type

Watch for these key phrases that signal a relative motion problem:

  • "laps" or "overtakes" — indicates one object gaining a full circuit on another
  • "circular track" or "around a loop" — tells you it's circular motion
  • "same direction" vs "opposite directions" — determines whether to add or subtract speeds
  • "how long until..." — asking for time, not distance

This problem type also appears in disguised forms:

  • Cars on a racetrack
  • Cyclists on a velodrome
  • Satellites orbiting at different speeds
  • Clock hands (hour vs minute hand)

What If?

1
Reverse the Unknown
On the same track, Alice runs at 8 m/s. They start together, and Alice laps Bob for the first time after 40 seconds. What is Bob's speed?
Step 1 — Find the relative speed

In 40 seconds, Alice gained exactly 200 meters (one lap) on Bob. So relative speed = 200 m ÷ 40 s = 5 m/s

Step 2 — Use relative speed formula

Relative speed = Alice's speed - Bob's speed
5 = 8 - Bob's speed

Step 3 — Solve for Bob's speed

Bob's speed = 8 - 5 = 3 m/s

Verification

Check: After 40s, Alice travels 8 × 40 = 320 m, Bob travels 3 × 40 = 120 m. Difference is 320 - 120 = 200 m = 1 lap

2
Opposite Directions
Alice (7 m/s) and Bob (3 m/s) start at the same point but run in opposite directions on the same track. How long until they meet for the 5th time?
Step 1 — Find approach speed

When moving in opposite directions, speeds add: 7 + 3 = 10 m/s

Step 2 — Time for one meeting

They meet when they've covered one track circumference together: 200 m ÷ 10 m/s = 20 seconds

Step 3 — Time for 5 meetings

5 × 20 = 100 seconds

Verification

After 100s: Alice travels 7 × 100 = 700 m, Bob travels 3 × 100 = 300 m in opposite direction. Combined distance: 700 + 300 = 1000 m = 5 × 200 m

3
Head Start
Bob gets a 1/4 lap head start (50 m ahead). Alice still runs 7 m/s, Bob 3 m/s, same direction. How long until Alice laps Bob for the first time?
Step 1 — Calculate total distance Alice must gain

Alice must overcome Bob's 50 m head start PLUS gain a full 200 m lap: 50 + 200 = 250 meters

Step 2 — Find relative speed

Same as before: 7 - 3 = 4 m/s

Step 3 — Calculate time

Time = 250 m ÷ 4 m/s = 62.5 seconds

Verification

After 62.5s: Alice travels 7 × 62.5 = 437.5 m, Bob travels 3 × 62.5 = 187.5 m but started 50 m ahead, so his total is 187.5 + 50 = 237.5 m. Difference: 437.5 - 237.5 = 200 m = 1 lap

4
Square Track
They run on a square track with the same perimeter as the original circular track (200 m). Speeds are 7 m/s and 3 m/s. How long until Alice laps Bob twice?
Step 1 — Note that perimeter is the same

The square track has the same 200 m perimeter as the circular track. Track shape doesn't affect this calculation.

Step 2 — Use same relative speed

Relative speed = 7 - 3 = 4 m/s (unchanged)

Step 3 — Calculate time for 2 laps

Time = 2 × (200 m ÷ 4 m/s) = 2 × 50 = 100 seconds

Verification

After 100s: Alice travels 7 × 100 = 700 m, Bob travels 3 × 100 = 300 m. Difference: 700 - 300 = 400 m = 2 × 200 m = 2 laps

Frequently Asked Questions

How do you find relative speed when two objects move in the same direction? +
Subtract the slower speed from the faster speed. When Alice runs at 7 m/s and Bob at 3 m/s in the same direction, their relative speed is 7 - 3 = 4 m/s. This means Alice gains 4 meters on Bob every second.
What distance must the faster runner cover to complete one lap on the slower runner? +
The faster runner must gain exactly one full track circumference on the slower runner. In this problem, Alice must gain 200 meters on Bob to lap him once, which takes 200 ÷ 4 = 50 seconds at their relative speed of 4 m/s.
How do you calculate circumference when the radius contains π? +
Use the formula C = 2πr and simplify algebraically. With radius 100/π meters, the circumference is 2π × (100/π) = 2π × 100/π = 200π/π = 200 meters. The π terms cancel out completely.
NJ
Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

Contact

This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-09-05