When Will Two Gym Memberships Cost the Same?

Systems of Equations 7th-8th Grade
Problem
FitLife Gym charges $25 per month plus $3 per class. StrongBody Gym charges $35 per month plus $2 per class. For how many classes will the cost be the same?

What This Problem Teaches

  • Setting up linear equations from real-world situations with fixed and variable costs
  • Solving systems of equations by substitution to find break-even points
  • Interpreting solutions in context — understanding what the answer means for decision-making
  • Recognizing when two different payment structures will result in equal costs
  • Building foundation skills for analyzing competing business models or pricing plans

Visualizing the Problem

Let's create a table to see how costs change with the number of classes. This helps us understand the problem before diving into algebra:

Classes (c)FitLife Cost
$25 + $3c
StrongBody Cost
$35 + $2c
Difference
0$25$35StrongBody $10 higher
5$40$45StrongBody $5 higher
10$55$55Equal!
15$70$65FitLife $5 higher
20$85$75FitLife $10 higher

Notice how StrongBody starts more expensive but FitLife's costs grow faster. They cross at exactly 10 classes.

Solution: Method 1 — Setting Equal Cost Equations

Step 1 — Write the cost equation for each gym

Let c represent the number of classes taken per month.

FitLife total cost = $25 + $3c
StrongBody total cost = $35 + $2c

Step 2 — Set the costs equal

We want to find when both gyms cost the same amount:

25 + 3c = 35 + 2c

Step 3 — Solve for c

Subtract 2c from both sides:

25 + 3c - 2c = 35 + 2c - 2c
25 + c = 35

Subtract 25 from both sides:

25 + c - 25 = 35 - 25
c = 10

Both gyms will cost the same when you take 10 classes per month.

Solution: Method 2 — Cost Difference Analysis

Step 1 — Find the monthly fee difference

StrongBody has a higher monthly fee than FitLife:

$35 - $25 = $10 higher monthly fee

Step 2 — Find the per-class difference

But FitLife charges more per class:

$3 - $2 = $1 more per class

Step 3 — Calculate when differences cancel out

StrongBody's $10 higher monthly fee will be offset when FitLife's extra per-class cost reaches $10:

Number of classes = $10 ÷ $1 per class = 10 classes

This reasoning gives us the same answer: 10 classes.

The costs will be equal when you take 10 classes per month.
At that point, both gyms cost $55 per month.

Verification

Let's substitute c = 10 into both cost equations to confirm our answer:

FitLife: $25 + $3(10) = $25 + $30 = $55
StrongBody: $35 + $2(10) = $35 + $20 = $55

✓ Both gyms cost exactly $55 when you take 10 classes per month.

We can also check boundary cases to make sure our answer makes sense:

  • 9 classes: FitLife = $52, StrongBody = $53 (StrongBody still more expensive)
  • 11 classes: FitLife = $58, StrongBody = $57 (FitLife now more expensive)

Common Pitfalls

✗ Mixing up which gym has which rates
Setting up 25 + 2c = 35 + 3c instead of 25 + 3c = 35 + 2c. Always double-check which gym charges which amount. FitLife is $25 + $3/class, StrongBody is $35 + $2/class.
✗ Forgetting the monthly fee
Only comparing per-class costs: "$3 vs $2, so they're never equal." You must include the fixed monthly fees — they're what make the crossover possible.
✗ Solving for total cost instead of number of classes
Getting $55 as the final answer and stopping there. The question asks "for how many classes" — so the answer is 10 classes, with $55 being the cost at that point.

The Pattern Behind This

This is a break-even analysis problem. The general structure is:

Plan A: Fixed cost₁ + Variable rate₁ × quantity
Plan B: Fixed cost₂ + Variable rate₂ × quantity

Break-even point: (Fixed cost₂ - Fixed cost₁) ÷ (Variable rate₁ - Variable rate₂)

This formula only works when the variable rates are different — otherwise the plans never intersect (or are always equal).

Key insight: The plan with the higher fixed cost must have the lower variable rate for a break-even point to exist. If StrongBody had both higher monthly fees AND higher per-class rates, FitLife would always be cheaper.

How to Spot This Problem Type

Watch for these telltale signs:

  • "Plan A charges X plus Y per..." — signals fixed cost + variable cost structure
  • "When will the costs be the same?" — asking for intersection point
  • "Which is cheaper?" followed by specific quantities — often leads to break-even analysis
  • Two different pricing schemes with different fixed/variable cost splits

You'll see this pattern in phone plans, gym memberships, subscription services, shipping options, and rental agreements.

Real Applications

  • Business pricing decisions: Companies analyze break-even points to set competitive pricing structures and understand when customers will switch between plans.
  • Personal finance: Comparing cell phone plans, streaming services, or transportation options (taxi vs. rideshare vs. car ownership) often involves this exact calculation.
  • Project management: Choosing between contractors with different fee structures (one charges higher upfront but lower hourly, another has lower setup but higher hourly rates).

What If?

1
Change the Fixed Fee
FitLife raises its monthly fee to $30. StrongBody's rates stay the same ($35 monthly + $2/class). For how many classes are the costs equal now?
Step 1 — Set up the new equations

FitLife: 30 + 3c, StrongBody: 35 + 2c

Step 2 — Set them equal

30 + 3c = 35 + 2c

Step 3 — Solve

3c - 2c = 35 - 30
c = 5

Step 4 — Verify

FitLife: 30 + 3(5) = 45
StrongBody: 35 + 2(5) = 45

Answer: 5 classes

2
Find the Better Deal
You know you will take exactly 8 classes per month. Which gym is cheaper and by how much?
Step 1 — Calculate FitLife cost

25 + 3(8) = 25 + 24 = $49

Step 2 — Calculate StrongBody cost

35 + 2(8) = 35 + 16 = $51

Step 3 — Compare

$51 - $49 = $2

Conclusion

FitLife is cheaper by $2 per month when taking 8 classes.

3
Reverse the Unknown
If the costs are equal when a member takes 15 classes, and StrongBody's rates are still $35 + $2/class, what must FitLife's monthly fee be? (Assume FitLife's per-class rate is still $3.)
Step 1 — Calculate StrongBody cost at 15 classes

35 + 2(15) = 35 + 30 = $65

Step 2 — Set up FitLife equation

Let FitLife's monthly fee be x
FitLife cost: x + 3(15) = x + 45

Step 3 — Set costs equal

x + 45 = 65

Step 4 — Solve

x = 65 - 45 = 20

FitLife's monthly fee must be $20

4
Add a Third Competitor
A new gym, FlexZone, charges a flat $50 per month for unlimited classes. For what range of classes per month is FlexZone the cheapest option compared to FitLife ($25 + $3/class) and StrongBody ($35 + $2/class)?
Step 1 — Find when FlexZone equals FitLife

50 = 25 + 3c
25 = 3c
c = 8.33

Step 2 — Find when FlexZone equals StrongBody

50 = 35 + 2c
15 = 2c
c = 7.5

Step 3 — Analyze the ranges

FlexZone beats StrongBody when c > 7.5
FlexZone beats FitLife when c > 8.33

Conclusion

FlexZone is cheapest when you take 9 or more classes per month (since we need whole classes).

Frequently Asked Questions

Write an equation for each plan showing total cost in terms of the variable quantity. For the gym problem, FitLife costs 25 + 3c dollars (where c is classes) and StrongBody costs 35 + 2c dollars. Set them equal: 25 + 3c = 35 + 2c to find when costs are the same.
When one plan has a higher fixed cost but lower variable cost, it will eventually become more expensive than a plan with lower fixed cost but higher variable cost. The crossover point occurs where the accumulated savings from the lower variable rate exactly offset the higher upfront cost.
Make a table showing costs for different numbers of classes. Calculate FitLife: 25 + 3c and StrongBody: 35 + 2c for various values of c. Look for where the costs are equal. This method works well for checking your algebraic answer or when the numbers are small.
NJ
Neven Jurkovic, PhD

Professor of Computer Science, Palo Alto College, Alamo Colleges District, San Antonio, TX

Developer of Algebrator

Contact

This solution was prepared with AI assistance and reviewed by Dr. Jurkovic for mathematical accuracy and pedagogical clarity.

2026-08-07