Break-Even: When Are Health Club Costs the Same?
What You Will Learn
- Setting up linear equations from real-world cost scenarios
- Solving systems of equations by substitution and elimination
- Interpreting break-even points in business contexts
- Understanding the relationship between fixed and variable costs
- Verifying solutions by checking both original equations
What This Looks Like
Let's visualize how the costs grow over time for each club:
| Months | Club A Cost | Club B Cost | Difference |
|---|---|---|---|
| 0 | $11 | $25 | Club A cheaper by $14 |
| 1 | $28 | $35 | Club A cheaper by $7 |
| 2 | $45 | $45 | Same cost! |
| 3 | $62 | $55 | Club B cheaper by $7 |
| 4 | $79 | $65 | Club B cheaper by $14 |
Solution: Method 1 — The Equation Setup
The most natural approach is to write cost equations for each club and find where they're equal.
Step 1 — Define the variable
Let m = number of months of membership.
Step 2 — Write cost equations for each club
Each club has a one-time initial fee plus monthly fees that accumulate:
Club B total cost: C₂ = 25 + 10m
Step 3 — Set the costs equal
We want to find when the total costs are the same, so:
Step 4 — Solve for m
Subtract 10m from both sides:
Subtract 11 from both sides:
Divide by 7:
Step 5 — Find the total cost at break-even
Substitute m = 2 into either cost equation:
Club B: 25 + 10(2) = 25 + 20 = 45
Solution: Method 2 — The Cost Difference Analysis
Instead of setting equations equal, we can think about how the cost difference changes over time.
Step 1 — Analyze the initial difference
At the start (month 0), Club B costs more:
Club B starts $14 ahead in cost.
Step 2 — Find how the gap closes each month
Each month, Club A charges $17 while Club B charges $10:
Club A gains $7 on Club B each month.
Step 3 — Calculate when the gap closes
Club A needs to make up the $14 initial disadvantage at $7 per month:
Step 4 — Find the total cost
After 2 months, both clubs will cost:
Club B: $25 + 2($10) = $45
Verification
Let's check our answer by substituting m = 2 back into both original cost equations:
Club B at 2 months: 25 + 10(2) = 25 + 20 = 45 ✓
Perfect! Both clubs cost exactly $45 after 2 months.
We can also check our logic by testing nearby values:
- At 1 month: Club A costs $28, Club B costs $35 (Club A is cheaper)
- At 3 months: Club A costs $62, Club B costs $55 (Club B is cheaper)
The costs cross over exactly at 2 months, confirming our answer.
Watch Out For These
Writing Club A as "17 + 11m" instead of "11 + 17m". The $11 is the one-time initial fee, not the monthly rate. Always check which number goes with which type of fee.
Setting up the equation as just "17m = 10m" and getting m = 0. This ignores the initial membership fees entirely. The full cost includes both the initial fee AND the accumulated monthly fees.
Setting "11 + 17 = 25 + 10" and getting confused. We need to set up equations with the variable m representing months, not solve for a specific month's cost directly.
Does This Seem Reasonable?
Our answer says the clubs cost the same after 2 months. Let's see if this makes intuitive sense:
Initial advantage: Club A starts $14 cheaper ($11 vs $25 initial fee).
Monthly disadvantage: Club A costs $7 more per month ($17 vs $10 monthly fee).
Break-even timing: It should take about $14 ÷ $7 = 2 months for Club A's higher monthly fees to catch up to Club B's higher initial fee.
This matches our calculated answer perfectly. For short-term memberships (under 2 months), choose Club A. For long-term memberships (over 2 months), choose Club B.
The General Pattern
This is a classic linear break-even problem. The general structure is:
Option 2: C₂ = a₂ + b₂t
Break-even when: a₁ + b₁t = a₂ + b₂t
Solving: t = (a₂ - a₁) ÷ (b₁ - b₂)
Where:
a₁, a₂are the initial costsb₁, b₂are the rates per time periodtis the break-even time
This formula only works when b₁ ≠ b₂ (different rates). If the monthly fees were the same, the cheaper initial option would always remain cheaper.
Real Applications
- Cell phone plans: Comparing unlimited vs pay-per-use plans with different activation fees and monthly rates
- Software subscriptions: Annual vs monthly billing with different upfront discounts
- Equipment leasing: Lease vs buy decisions where lease has lower upfront cost but higher monthly payments
What If?
Club A: C₁ = 15 + 12m
Club B: C₂ = 35 + 8m
15 + 12m = 35 + 8m
Subtract 8m: 15 + 4m = 35
Subtract 15: 4m = 20
Divide by 4: m = 5
At 5 months: 15 + 12(5) = 75
Check: 35 + 8(5) = 75 ✓
Answer: 5 months, $75 total cost
Club A cost = 20 + 15(6) = 20 + 90 = 110
Let x = Club B's monthly feeClub B cost = 50 + x(6) = 50 + 6x
50 + 6x = 110
Subtract 50: 6x = 60
Divide by 6: x = 10
Answer: Club B's monthly fee is $10
10 + 20m = 0 + 24m10 = 4mm = 2.5 months
40 + 12m = 0 + 24m40 = 12mm = 40/12 = 10/3 ≈ 3.33 months
At 2.5 months: A = C = 24(2.5) = $60
At 3.33 months: B = C = 24(10/3) = $80
Answer: A=C at 2.5 months ($60), B=C at 3⅓ months ($80)
With first month free: Club A = 11 + 17(m-1) for m ≥ 1
Simplified: Club A = 11 + 17m - 17 = 17m - 6
17m - 6 = 25 + 10m
Subtract 10m: 7m - 6 = 25
Add 6: 7m = 31m = 31/7 ≈ 4.43 months
At 31/7 months: 17(31/7) - 6 = 74.43 - 6 = $68.43
Answer: About 4.43 months, costing $68.43 each
Frequently Asked Questions
2026-08-28